Displaying 20 results from an estimated 3000 matches similar to: "Splitting the list"
2007 Apr 24
4
Size of an object in workspace
Hi folks,
Is there a function to show the size of an R object? eg. in Kbytes?
Couple months ago Bendix Carstensen posted this marvelous little function lls(), which shows all objects in the current workspace by mode, class and 'size'. This is a wonderful enhancement to the build-in ls() already and I now have it sourced in my Rprofile.site at startup.
The only drawback is,
2006 Sep 27
3
Space required by object?
Does R provide a function analogous to LS() or str() that reports the
storage space, on disk or in memory, required by objects?
Ben Fairbank
2006 Dec 14
5
Better way to change the name of a column in a dataframe?
Hello R users --
If I have a dataframe such as the following, named "frame" with the
columns intended to be named col1 through col6,
> frame
col1 col2 cmlo3 col4 col5 col6
[1,] 3 10 2 6 5 7
[2,] 6 8 4 10 7 1
[3,] 7 5 1 3 1 8
[4,] 10 6 5 4 9 2
and I want to correct or otherwise change the
2005 Jun 28
1
Using data frames for EDA: Insert, Change name, delete columns? (Newcomer's question)
I am finding complex analyses easier than some elementary operations in
R. In particular I want to do some low level exploratory data analyses
with data in a data frame but cannot find commands to easily insert,
remove (delete), rename, and re-order (arbitrarily, not sort) columns.
I see that the micEcon package has an insertCol command, but that is for
matrices, not data frames. I have looked
2008 Jun 20
2
The Green Book and its relevance to R
I bogged down about half way through reading the Green Book, in part
because it became increasingly difficult to understand how some of the
ideas related to R, as opposed to S (which I have not used). Does any
reader know whether there is a document that points out differences
between S and R that would be helpful in reading the Green Book?
Ideally, perhaps, I need a "crib sheet" to
2007 Jan 19
4
Newbie question: Statistical functions (e.g., mean, sd) in a "transform" statement?
Greetings listeRs -
Given a data frame such as
times
time1 time2 time3 time4
1 70.408543 48.92378 7.399605 95.93050
2 17.231940 27.48530 82.962916 10.20619
3 20.279220 10.33575 66.209290 30.71846
4 NA 53.31993 12.398237 35.65782
5 9.295965 NA 48.929201 NA
6 63.966518 42.16304 1.777342 NA
one can use "transform" to
2006 Oct 17
4
Book recommendation for newbie to stats and R?
I'm trying to learn statistics and R at the same time. I have an
undergraduate science degree and one year of calculus (30 years ago),
but never took a stats course. I hope to take some stats courses in the
next year, but thought I would start to see how much I could teach
myself.
I work for an organization that analyses behavior change communication
programs regarding HIV/AIDS and
2008 Jan 30
1
"hist" combines two lowest categories -- is there a workaround?
When preparing a series of histograms I found that hist was combining
the two lowest categories or bins, 1 and 2. Specifying breaks, as
illustrated below, resulted in the correct histogram:
values <- sample(10,500,replace=TRUE)
hist(values)
hist(values,breaks = 0:10)
Apparently, the number of values strictly less than 1 is shown in the
first bin (and since none is less than 1,
2014 Apr 02
3
[LLVMdev] decompiler
Hi -
Not sure if anyone else saw this or cares about a decompiler (not
personally tested)
https://github.com/draperlaboratory/fracture
I wonder if they have been in contact with anyone in the community in
getting this upstreamed. Does it look interesting to anyone else?
(thoughts/random comments/feedback)
2006 May 13
2
What does it mean to be "masked from data" when attaching? (Newbie question)
I have several data frames, each with six variables and several hundred
cases broken out from a larger dataframe by eleven values of a factor
called "Division". I have to perform the same analysis on each one. I
would like to do it by creating a data frame called data2 eleven times,
once with data corresponding to each value of the factor, and performing
the same analysis on each of
2009 Jan 12
3
irrelevant warning message
Context:
R version 2.7.1 (2008-06-23)
I don't know when this was upgraded in the department, I just ran into the
aberrent behavior today.
Problem:
Our group BY CHOICE does not change character variables into factors by
default. I can get into a long arguement as to why later, and will give one
example of why below.
The default behavior of S, Splus and R has been to create
2007 Jan 26
2
Use a text variable's value to specify another varaible?
Greetings guRus --
If a variable, e.g., 'varname', is a character string, e.g. varname <-
"datavector", and I want to apply a function, such as table(), to
datavector, what syntax or method will do so using only the variable
varname? This seems similar to indirect addressing, but I have not seen
a method for it in the R manuals. Is there a general name for such
indirect
2007 May 01
0
[Fwd: Re: [R-downunder] Beware unclass(factor)] (PR#9641)
It really is unclear what is claimed to be a bug here. But see
https://stat.ethz.ch/pipermail/r-devel/2007-May/045592.html
for why the bug is not in R: your old and new data do not match.
Your fit is to a category.
[The problem with the web interface to R-bugs was reported last week: it
is being worked on.]
On Mon, 30 Apr 2007, r.darnell at uq.edu.au wrote:
> This is a multi-part
2014 Jun 03
2
[LLVMdev] [LLVM Doc] tblgen backends
Hi all!
There is doc about tglben backends:
http://llvm.org/docs/TableGen/BackEnds.html
May be should to add link at
https://github.com/draperlaboratory/fracture/wiki/How-TableGen%27s-DAGISel-Backend-Works
I remember when I first met the LLVM it would be very useful.
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2014 Jun 03
3
[LLVMdev] [LLVM Doc] tblgen backends
I agree, but I have no experience with LLVM doc.
The job is very simple: add link at page
https://github.com/draperlaboratory/fracture/wiki/How-TableGen%27s-DAGISel-Backend-Works
into doc page
http://llvm.org/docs/TableGen/BackEnds.html
But how I can do it?
On Tue, Jun 3, 2014 at 4:41 PM, Renato Golin <renato.golin at linaro.org>
wrote:
> Hi Daniil,
>
> Those look great! I think
2017 Jun 23
5
Comparing pooled proportions(complication and reoperation rates) of different treatment modalities
Dear sir/madame,
I am currently writing a meta-analysis on the complication and reoperation rates of 5 different treatment modalities after a distal radius fracture. I was able to pool the rates of the 5 different rates using R. Now I have to compare the pooled rates of the 4 treatment modalities with the golden standard separately. I though the chi squared test would be the best method. How do
2006 Jan 01
20
A comment about R:
Readers of this list might be interested in the following commenta about R.
In a recent report, by Michael N. Mitchell
http://www.ats.ucla.edu/stat/technicalreports/
says about R:
"Perhaps the most notable exception to this discussion is R, a language for
statistical computing and graphics.
R is free to download under the terms of the GNU General Public License (see
http://www.r-project.
2001 Mar 08
1
inconsistent results when calling functions with other func (PR#869)
Hello Bug people,
I have an unexpected behavior and am unsure whether the problem is in my
thinking, my implementation or the program R.
Basically I get two different answers depending on how I call a function
which takes other functions as arguments as indicated below.
To me it should make no difference if f is a function that returns the
function g then z(f(x)) whould give the same as
y<-
2004 Dec 22
2
Why use 'Answer'?
Why is it that newcomers always feel like inserting 'Answer' is a
necessary step in their extension.conf entries?
>[voiptalk.org]
>;forwards any calls starting with an "8" thru voiptalk.org
>exten => _8.,1,Answer
>exten => _8.,3,SetCIDNum(55555555)
>exten => _8.,4,SetCIDName(My Name And Surname)
>exten => _8.,5,Dial(SIP/${EXTEN:1}@voiptalk.org,,g)
2007 Mar 20
0
[R-downunder] las with stripchart
Hi Ross -
I believe I was wrong in thinking that passing via the ...
list to stripchart() was ever allowed. Here are patches:
Add ... to the argument list
Add, at the beginning of the function:
pars <- list(...)
There are two calls to axis(). Modify these to:
axis(1, at = at, labels = names(groups), las=pars$las)
axis(2, at = at, labels = names(groups), las=pars$las)
Also