similar to: Writing a list to a file !

Dear all, I like to extract row names & column names from the named matrix...... like...... a<-matrix(1:6,2) ro<-c("aa","bb") co<-c("dd","ee","ff") dimnames(a)<-list(ro,co) a > dd ee ff aa 1 3 5 bb 2 4 6 from the above matrix "a" I like to extract rownames separately like

Hello R-users! My (simple?) doubt: How to reverse the sequence of axis Y ?? the diagram below illustrate my idea... (default) | | . | . | . | 3 | 2 | 1 | 0 +---------------------------- 0 1 2 3 ... like I want... 0 | 1 | 2 | 3 | . | . | . | | +---------------------------- 0 1 2 3 ... thanks in advance klebyn

Say I have a FOR-loop for computing powers (just a trivial example) for(i in 1:5) { x<-i^2 y<-i^3 } How can I create a data.frame and a 3D plot of (i,x(i),y(i)), i.e. for each iteration Thanks, Serguei Kaniovski -- ___________________________________________________________________ ??sterreichisches Institut f??r Wirtschaftsforschung (WIFO) Name: Serguei Kaniovski

Hello, I'm a new user... I have a function : calculate <- function(x,y) { z <- x + y } I would like to use the result (z) with another function : recalculate <- function(...) { a <- z^2 } But R says that z does not exist... How can I use z in an another function ? Thank you for your answer... -- David [[alternative HTML version deleted]]

Hello R - users, This may sound simple to may people: I have a list of data as follows type value y 7 y 7 y 8 y 8 y 8 y 9 y 9 y 9 y 9 y 10 y 10 y 10 y 10 y 11 y 11 y 12 y 12 y 14 y 14 y 14 y 15 y 17 y 20 y 20 y 20 y 20 y 25

Hello there, I would like to simulate X --Normal (20, 5) Y-- Normal (40, 10) and the correlation between X and Y is 0.6. How do I do it in R? Thank you very much Lisa Wang Msc. Princess Margaret Hospital Toronto, Ca

Hello, I try to define a global variable. My example: R> a <- "old" R> test <- function () { a <- "new" } R> test() R> a # shoud be "new" This doesn't work. I would like to modify the variable "a" in a procedure. How can I do that. Thank you for helping. Sven Kn侟ppel (Germany-Berlin)

Dear, I am looking for the simplification of a formula to improve the calculation speed of my program. Therefore I want to simplify the following formula: H = sum{i=0..n-1 , [ sum {j=0..m-1 , sqrt ( (Ai - Bj)^2 + (Ci - Dj)^2) } ] } where: A, C = two vectors (with numerical data) of length n B, D = two vectors (with numerical data) of length m sqrt = square root Ai = element of A with index

Dear R-helpers, I apologize for this certainly simple question. I have the following R lines : > m = matrix(1:12 , 3 , 4); > m [,1] [,2] [,3] [,4] [1,] 1 4 7 10 [2,] 2 5 8 11 [3,] 3 6 9 12 > m1 = subset(m , m[,2]>=5); > m1 [1] 2 3 5 6 8 9 11 12 but in fact I would appreciate m1 to be also a matrix, and thus would like to get :

Dear All, It is not a typical R question (though I use R for this) but I thought someone will help me. For the list of P values, I have calculated FDR using p.adjust() in R (bioconductor). But my FDR values are same for all the P values. When do we get same FDR values? Does the smallest P values should less than 1/N? (where N is the number of P values) Thanks in advance. Kind regards, Ezhil

Hi, I have a matrix HR(9x27). I would like to make a single vector with elements: t(HR[,1]) followed by t(HR[,2]) and then t(HR[,3] ... etc. Is there any neat way of converting this matrix into a vector rather doing something like c(t(HR[,1]), t(HR[,2]), t(HR[,3]) ..)? Thanks in Advance. Kind regards, Ezhil ____________________________________________________________________________________

Dear All, How can I store hist() or any plot output graphics in PNG format? I tried with bitmap() but not getting the result. Appreciate your help on fixing this. Thanks in Advance. Regrads, Ezhil

Dear All, I have a correlation matrix of size 100 x 100 and would like to extract the diagonal matrix from it. I have used the for loop to store tha correlation values of the diagonal matrix. Is there a 'R way' of doing this? Thanks in advance. Kind regards, Ezhil

Dear All, I have large matrix (46000 x 11250). I would like to do the linear regression for each row. I wrote a simple function that has lm() and used apply(mat,1,func). The issue is that it takes ages to load the file and also to finish the lm. I am using LINUX 64 bit with 32G mem. Is there an elegant and fast way of completing this task? Thanks in advance. Kind regards, Ezhil

Dear All, I have two matrices A (40 x 732) and B (40 x 1230) and would like to calculate correlation between them.  I can use: cor(A,B, method="pearson") to calculate correlation between all possible pairs. But the issue is that there is one-many specific mappings between A and B and I just need to calculate correlations for those pairs (not all). Some variables in A (proteins, say p1)

Dear All, I am trying to install R 2.7 on my openSUSE 10.3. I have faithfully followed instruction at http://cran.r-project.org/bin/linux/suse/ReadMe.txt. I have downloaded all the RPMs but still R complains about: libtcl8.4.so is needed by R-base-2.7.1-6.1.i586 I searched for this library and found a one, tcl-8.4.15-22.i586.rpm at openSUSE distribution site and installed. But R still complains

Hi everyone, I would like to identify the case by groups that is just bigger that avg plus sd. For example, using species as group and petal.wid as my variable in the iris data. What's the better way to doit? creating a function? So,the question is to identify the single element of each species that is just larger than a cut-off point (i.e. larger than mean + sd) I made this, but I can not

Dear All, I am using the following commands to do the scatter plot of two vectors, say X and Y. plot(X,Y, col="blue") abline(a=1,b=1, col="red") abline(a=-1,b=1, col="green") I would like to split the scatter plot into 3 part with 3 different colors: (i) points lies between 2 lines, (ii) points above line 1, and (iii) points below line 2. I am struggling to do

Dear all, I am a total beginner in R, so sorry if this is the wrong place. I am using R 2.10.1 on a Mac (Mac OS 10.6.2). I have this small dataset : growth sugar 75 C 72 C 73 C 61 F 67 F 64 F 62 S 63 S I have no problem reading the table, or getting the summary, but if I try boxplot(growth~sugar, ylab="growth", xlab="sugar", data=Dataset), I have the following error :

Dear All, I am trying to install rgl on my mac notebook from the source file. I tried using: /usr/bin/R64 CMD INSTALL rgl_0.92.798.tar.gz and get the following error message: checking for X... no configure: error: X11 not found but required, configure aborted. ERROR: configuration failed for package ?rgl? * removing ?/Library/Frameworks/R.framework/Versions/2.14/Resources/library/rgl? *