similar to: Visualizing a Data Distribution -- Was: breaks in hist()

Dear listers, A quick question about breaks in hist(). The histogram is highly screwed to the right, say, the range of the vector is [0, 2], but 95% of the value is squeezed in the interval (0.01, 0.2). My question is : how to set the breaks then make the histogram look even? Thanks in advance, Leaf

Hello R-list, I've been using hist to plot histograms of some data, but I get variable numbers of bins. I understood from reading the help file that breaks will set the number of bins. Please correct me if I'm wrong. I'm plotting measures from subsets of a larger data set. Depending on the data subset the number of bins varies despite having set breaks to 5 in all cases. See

Hi R users, My goal is to rank my samples according to how they fall out in a histogram with 10 bins to produce a ranking for each sample according to where it falls on the histogram, with a "1" to represent one tail of the hist, a "10" to represent the other tail, and a "5" for the median/mean. I have a number of different data sets to do this with and in all cases

Hi Folks, I'd like to know how hist() decides how many cells to use when it ignores my "suggestion" to use say 'hist(...,breaks=50)'. More specifically, I have the results of 10000 simulations, each returning an 8-vector, therefore 8 variables each with 10000 values. Some of these 8 have somewhat skew distributions. Say one of these 8 variables is X. I ask for H <-

Hello, How can I display the xlim of the boundaries of all or specific breaks in a histogram? I generated the attached plot with hist and would like to know which values of x correspond to the frequency 329 and display these values on the x axis? Best, carol

Hello Guys, I would like help in script R when I try to plot the histogram appears the error: Erro em hist.default some 'x' not counted; maybe 'breaks' do not span range of 'x' I using a file with more 1000 datas (vector) hist(dados[[1]], seq(0, 20, 0.5), prob=TRUE, xlab="chuva (mm/dia)",ylab="frequência", main="", cex.lab=1.6,

Hi all, I came across some curious behavior today in using hist.Date() and subsequently noted the same behavior in cut.Date(), both of which are using similar code when 'breaks = "months"' or 'breaks = "years"'. I was in the process of creating a histogram of subject enrollment in a clinical trial. The counts needed to be by month, so essentially used:

> From: Pieter Provoost > > I'm sure it's possible to display the variable names by making a small > change to the code. Someone did this last week but I can't > contact this > person now to ask how. I tried this > > vars <- names(Rdata) > pairs(Rdata, labels=vars,...) > > but that doesn't work (formal argument "labels" matched by

Hy all, I give example code : connexions_jours<-c(1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,3,3,3,3,3,3,3,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,5,5,5,5,5,5,6,6,7,7,7,7,7,7,7,7,8,8,8,12,15,19) pas_de_groupe<-1 hist(connexions_jours,col="red",xlab="Répartition du nombre de connexions par jours (sans

Dear R People: Is there a way to "guarantee" that breaks=n will give you exactly n breaks, please? I'm fairly certain that the answer is "no", but thought I'd check. Thanks, Erin -- Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of Houston - Downtown mailto: erinm.hodgess at gmail.com

On Sun, 11 Dec 2005 clausen at econ.upenn.edu wrote: > Full_Name: Andrew Clausen > Version: 2.1.0 > OS: Debian GNU/Linux > Submission from: (NULL) (71.242.192.73) > > > Hi, > > When I type > > hist(x, freq=F) > > I get a density function, as I expect. However, if I type > > plot(hist(x, freq=F)) > > then I get the same output as if I had

Hi, I have the following code: hist(gps$heartpercent, breaks=5) rect(90, par("usr")[3], 100, par("usr")[4], col = "red") How do I get the rectangle to appear behind the histogram. Barring that, how can I make certain bars of the histogram to be a certain color? Thanks, Jason

Full_Name: Mark Wall Version: 1.6.0 OS: linux Submission from: (NULL) (63.251.119.254) I want to plot a histogram of a *subset* of some data: >t = c(0:9) >hist(t,right=FALSE,breaks=10,xlim=c(0,5),xaxs="i") This means I should plot a histogram from 0 to 5 with breaks at 1,2,3,4. This should produce exactly 5 bars of frequency=1. Instead I get 5 and 1/4 bars. I do not want the

Hello, After spending sometime trying to generate histograms of all the numeric variables in a data frame using a for loop, I realized I could use apply to create the histograms. This was one of those few moments when I `see' the alternative to looping. So, I can generate all the histograms with this command: apply(toblo.df[,-c(40,52)],2,hist) # 40 and 52 are ID's When I do this, the

Using "par" seems easily put a "hist" and a density side by side on the same output window. I would like to use some features in "histogram" from Lattice, but how can I put "histogram" and "densityplot" side by side on the same graph? Thank you par(mfrow=c(2,1)) hist(y) plot(density(y)) Jue Wang, Biostatistician Contracted Position for

When preparing a series of histograms I found that hist was combining the two lowest categories or bins, 1 and 2. Specifying breaks, as illustrated below, resulted in the correct histogram: values <- sample(10,500,replace=TRUE) hist(values) hist(values,breaks = 0:10) Apparently, the number of values strictly less than 1 is shown in the first bin (and since none is less than 1,

Hi all, I am doing histogram using the "hist" function. For some reason, the histogram does not look good... is there a way I can change the number of bins, and/or change the way that data gets binned... so that I can obtain a better looking histogram? Thanks a lot! [[alternative HTML version deleted]]

This message is in MIME format. The first part should be readable text, while the remaining parts are likely unreadable without MIME-aware tools. Send mail to mime@docserver.cac.washington.edu for more info. --0-201145637-953833073=:7710 Content-Type: TEXT/PLAIN; charset=US-ASCII Dear all, I've been hacking on histograms the past couple of days. I wanted to do two things, add

. I am looking for a histogram or box plot with the adding normal distribution curve I think that must be possible, but I am not able to find out how to do. Regards Knut

Hi, I've been passing the hist() function to tapply() to quickly generate histograms based on the list of factors supplied to tapply(). However, I have not figured out how to generate titles for each of the histograms, which paste in the unique values of the list factors as part of the histogram title. I'm hoping that someone can tell me how to do this. Thanks for your time and