similar to: breaks in hist()

> > Leaf Sun wrote: > > The histogram is highly screwed to the right, say, the range > > of the vector is [0, 2], but 95% of the value is squeezed in > > the interval (0.01, 0.2). I guess the histogram is as you wrote. See http://web.maths.unsw.edu.au/~tduong/seminars/intro2kde/ for a short explanation. > -----Original Message----- > From: Berton Gunter

Hi Listers, I am producing some graphics that the commands are in a FUNCTION... The problem is that I end up viewing just last graphic and in my FUNCTION there are 4 graphics with the PAR command function... Like those below... How do I view/get the other 3 graphics? Any help? Thanks in advance... histogram<-par(mfrow=c(1,2)) hist(rw_mean_app,main='Bootstrap Method

Hi Folks, I'd like to know how hist() decides how many cells to use when it ignores my "suggestion" to use say 'hist(...,breaks=50)'. More specifically, I have the results of 10000 simulations, each returning an 8-vector, therefore 8 variables each with 10000 values. Some of these 8 have somewhat skew distributions. Say one of these 8 variables is X. I ask for H <-

Hello R-list, I've been using hist to plot histograms of some data, but I get variable numbers of bins. I understood from reading the help file that breaks will set the number of bins. Please correct me if I'm wrong. I'm plotting measures from subsets of a larger data set. Depending on the data subset the number of bins varies despite having set breaks to 5 in all cases. See

Dear R-help listers, I am new. I just want to get helps on how to plot two histograms overlapped in the same plane coordinate. What I did is very ugly. Could you please help me to improve it? I want to got a plot with semi- transparent overlapping region. And, I want to know how to specify the filled colors of the different histograms. I also prefer other solutions other than ggplot2. Many

Hi R users, My goal is to rank my samples according to how they fall out in a histogram with 10 bins to produce a ranking for each sample according to where it falls on the histogram, with a "1" to represent one tail of the hist, a "10" to represent the other tail, and a "5" for the median/mean. I have a number of different data sets to do this with and in all cases

Hi, I have the following code: hist(gps$heartpercent, breaks=5) rect(90, par("usr")[3], 100, par("usr")[4], col = "red") How do I get the rectangle to appear behind the histogram. Barring that, how can I make certain bars of the histogram to be a certain color? Thanks, Jason

Full_Name: Mark Wall Version: 1.6.0 OS: linux Submission from: (NULL) (63.251.119.254) I want to plot a histogram of a *subset* of some data: >t = c(0:9) >hist(t,right=FALSE,breaks=10,xlim=c(0,5),xaxs="i") This means I should plot a histogram from 0 to 5 with breaks at 1,2,3,4. This should produce exactly 5 bars of frequency=1. Instead I get 5 and 1/4 bars. I do not want the

Think I'm missing something to understand what is going on with hist(...) http://n2.nabble.com/What-is-going-on-with-Histogram-Plots-td3022645.html For my example I count 7 unique years, however, on the histogram there only 6. It looks like the bin to the left of the tic mark on the x-axis represents the number of entries for that year, i.e. Frequency. I guess it looks like the bin for

. I am looking for a histogram or box plot with the adding normal distribution curve I think that must be possible, but I am not able to find out how to do. Regards Knut

Hello, How can I display the xlim of the boundaries of all or specific breaks in a histogram? I generated the attached plot with hist and would like to know which values of x correspond to the frequency 329 and display these values on the x axis? Best, carol

Dear List, I have the following function where I plot on one page a histogram and a boxplot. I use option labels = TRUE in hist to show labels. However the label on the highest bar in the histogram is not showing entirely. How can I correct this? Thanks for any suggestions? histtst <- function(n = 100,...){ set.seed(15) # makes rnorm reproducible par(mfrow = c(2,1)) x <-

Hi all, I'm trying to superimpose a rchisq density line over a histogram with something like: hist(alnlength) lines(density(rchisq(length(alnlength), 4)),col="red") But the rchisq line won't appear anywhere, Anyone knows what I am missing here? Thanks in advance, Albert.

Hi, I am trying to plot a histogram with my dataset that has 68 elements, 67 of which are zero and the last one is 18. It can be reproduced as follows: x<-array(0, dim=(68)) x[1] = 18 I am trying to plot its histogram using: hist(x, breaks=10, xlim=c(0, 100), axes=F) axis(2, at=seq(0, 70, 5)) # for the y-axis axis(1, at=seq(0, 100, 10)) # for the x-axis As you would also see if you

On Sun, 11 Dec 2005 clausen at econ.upenn.edu wrote: > Full_Name: Andrew Clausen > Version: 2.1.0 > OS: Debian GNU/Linux > Submission from: (NULL) (71.242.192.73) > > > Hi, > > When I type > > hist(x, freq=F) > > I get a density function, as I expect. However, if I type > > plot(hist(x, freq=F)) > > then I get the same output as if I had

Dear everybody! I have load a list A of numbers and want a histogram to be drawn. on hist(Y) the Machine returns: Error in hist.default(A) : `x' must be numeric I found out, that the list is of type data.frame. Y<-as.numeric(Y) returns Error in as.double.default(A) : (list) object cannot be coerced to double What schould I do? Than you in advance!

Hi, I've been passing the hist() function to tapply() to quickly generate histograms based on the list of factors supplied to tapply(). However, I have not figured out how to generate titles for each of the histograms, which paste in the unique values of the list factors as part of the histogram title. I'm hoping that someone can tell me how to do this. Thanks for your time and

The command hist(c(2,2,2,4,5,6)) returns a histogram that looks incorrect -- 3 in the bin labeled 2 on the left, but 1 each in the bins labeled 3,4,5 on the left. Thanks! Pam Surko -------------------- > version _ platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major 1 minor

When preparing a series of histograms I found that hist was combining the two lowest categories or bins, 1 and 2. Specifying breaks, as illustrated below, resulted in the correct histogram: values <- sample(10,500,replace=TRUE) hist(values) hist(values,breaks = 0:10) Apparently, the number of values strictly less than 1 is shown in the first bin (and since none is less than 1,

Hello, After spending sometime trying to generate histograms of all the numeric variables in a data frame using a for loop, I realized I could use apply to create the histograms. This was one of those few moments when I `see' the alternative to looping. So, I can generate all the histograms with this command: apply(toblo.df[,-c(40,52)],2,hist) # 40 and 52 are ID's When I do this, the