Displaying 20 results from an estimated 8000 matches similar to: "problem with dates"
2005 Sep 12
6
trouble with reading data from excel
I have been trying to open data that I have saved in an excel spread sheet. I saved it as a csv. Then I tried using the read.csv command. However, everytime I do this--
diseasedat<-read.csv("M:/sloan/R/disease/disease.csv", sep=, header = TRUE, fill= TRUE)--
I get an error message:
Error in file(file, "r") : unable to open connection
In addition: Warning message:
2006 Dec 27
2
Help with histograms
I would like to make one histogram combining two value vectors. One vector has more than 50 entries and the other only has 16. Both vectors contain dates in the POSIXct format. I need to be able to highlight the 16 entries from the smaller data set.
Is it possible to do this with the hist function? Which function should I use?
Sloan
--
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Surf the
2005 Sep 30
1
ACCESS R and dates
I have used the RODBC package to read in data I have stored in an Access file. When I am using data from files other than ACCESS I have no problem using the survival package to work with dates; however, with the ACCESS data the dates are reading-in in the following format: "2004-02-11 Pacific Standard Time". How do I remove the "Pacific Standard Time" part in ACCESS or R so
2013 Feb 13
3
date and matrices
Hi Elisa,
Try this:
date1<-format(seq.Date(as.Date("1991.1.1",format="%Y.%m.%d"),as.Date("1996.12.31",format="%Y.%m.%d"),by="day"),"%Y.%m.%d")
?length(date1)
#[1] 2192
mat1<-matrix(c(.314,.314,.273,.273,.236,.236,.236,.236,.273,.314,.403,.314),ncol=1)
res1<-
2009 Jan 21
3
Error as.Date on Invalid Dates
Hi All,
I have an script in R which accepts user inputs for certain parameters,
particularly dates, which the user inputs as character strings.
eg:
> date1 <- "2009-01-21"
The script later parses the input via the as.Date function:
> as.Date(date1)
However, as.Date encounters an error when the string does not represent an
actual date.
eg:
> date1 <-
2006 Dec 28
3
Dates in R
Hello all,
Can somebody point me to references or provide some code on dealing with
this date issue. Basically, I have two vectors of values that represent
dates. I want to convert these values into a date format and subtract the
differences to show elapsed time in days. More specifically, here is the
example:
Date1 Date2
032398 061585
032398 061585
111694 101994
111694
2009 Jul 11
2
Date conversions
Hi all,
I'm having a little bit of trouble with some date conversions and
am hoping someone can help me out. Thanks in advance.
OK, I have two sources of data that provide date info in a csv file
differently. I've attached a small zipped file with two text files
that illustrate both. (Is it ok to send attachments to this list? Not
sure. It's very small.) I need to be able to
2012 Nov 10
4
help on date dataset
Hi everybody,
I am beginer in R and I need your precious help.
I want to create a small function in R as in sas to retrieve date.
I have a file with data that import in R.
DATE PAYS nb_pays.ILI.
1 24/04/2009 usa 0
2 24/04/2009 usa 0
3 24/04/2009 Mexique 0
4 24/04/2009
2008 Jan 02
3
Find missing days
Hi,
I have a data.frame like this:
y <- rnorm(60)
lev <- gl(3,20, labels=paste("lev", 1:3, sep=""))
date1 <- as.Date(seq(ISOdate(2007,9,1), ISOdate(2007,11,5),
by=60*60*24))
date1 <- date1[-c(3,4,15,34,38,40)]
df <- data.frame(lev=lev, date1=date1, y=y)
I would like to produce a new data.frame with missing days in df$date1
in each df$lev, like this:
lev
2005 Feb 24
2
Row median of Date class variables in a data frame
I am trying to calculate the median of each row of a
data frame where the data frame consist of
columns of class Date.
Below are my test data and best attempt at using apply.
I didn't see a solution via Google or the Baron search
site.
I'd be grateful for any suggestions or solutions.
I'm using R 2.0.0 on Mac OS X.
Thank you,
Stephen Weigand
### Test data
date1 <- c(1000,
2013 Feb 19
1
data format
Hi,
Try this:
el<- read.csv("el.csv",header=TRUE,sep="\t",stringsAsFactors=FALSE)
?elsplit<- split(el,el$st)
?
datetrial<-data.frame(date1=seq.Date(as.Date("1930.1.1",format="%Y.%m.%d"),as.Date("2010.12.31",format="%Y.%m.%d"),by="day"))
elsplit1<- lapply(elsplit,function(x)
2015 Nov 06
4
Puzzled by eval
I am currently puzzled by a seach path behavior. I have a library of a dozen routines
getlabs(), getssn(), getecg(), ... that interface to local repositories and pull back
patient information. All have a the first 6 arguments in common, and immediately call a
second routine to do initial processing of these 6. The functions "joe" and "fred" below
capture the relevant
2013 Mar 09
1
Unexpected behavior looping through sequence of dates
I understand that the two following loops should produce the exact same output. However, they do not. It appears that looping directly through the sequence of Date objects somehow makes them be coerced to numeric:
> date1 = "20130301"
> date2 = "20130302"
>
> d1 = as.Date(date1, format="%Y%m%d", tz="GMT")
> d2 = as.Date(date2,
2009 Dec 09
1
reshape() makes R run out of memory (PR#14121)
Full_Name: Alexander L. Belikoff
Version: 2.8.1
OS: Ubuntu 9.04 (x86_64)
Submission from: (NULL) (67.244.71.200)
I'm trying to reshape the following data frame:
ID DATE1 DATE2 VALUE_TYPE VALUE
'abcd1233' 2009-11-12 2009-12-23 'TYPE1' 123.45
...
VALUE_TYPE is a string and is a factor with only 2 values
2008 Jun 29
1
Calculating quarterly statistics for time series object
I have time series observation on daily frequencies :
library(zoo)
SD=1
date1 = seq(as.Date("01/01/01", format = "%m/%d/%y"), as.Date("12/31/02", format = "%m/%d/%y"), by = 1)
len1 = length(date1); data1 = zoo(matrix(rnorm(len1, mean=0, sd=SD*0.5), nrow = len1), date1)
plot(data1)
Now I want to calculate 1. Quarterly statistics like mean, variance etc
2012 May 12
1
Query regarding date as argument in functions - and about sqldf
Hi,
I have a query about sqldf, and dates in general. I couldnt find much on
the net or on the forums, hence I am here. Here is the issue:
I want to write a function that accepts 3 arguments: date1, date2 and a
dataframe, say 'df'. Within the function, I want to populate a temp
dataframe which essentially contains the output of the query "select * from
df where DATE between date1
2012 Mar 07
1
date columns chooser
i have a data frame with 2 columns of dates.
with str(dataframe) i have ensured myself that they were indeed formatted
as dates.
one column has NA's in it.
the aim is now to make a third column that chooses date1 if it is a date,
and choose date2 if it is a NA.
i am trying
df$date3=ifelse(is.na(df$date1), df$date2, df$date1).
this leads to unexpected behaviour: the resulting column is
2002 Aug 27
1
au audio format?
ogg123 will output to the au audio format so
why doesn't oggenc accept this format as input?
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2007 Nov 25
5
Syslinux & usb booting
Hi
It looks to me there's some issues in the Linux implementation of syslinux (root ver, I don't have mtools).
When I used "syslinux -sf /dev/sda1", the stick was not bootable, it showed a black screen when booted, with a ";" appearing when I pressed a button.
The partition was marked active & bootable. And it was the only partition, and primary.
Then I did the
2013 Oct 15
2
Data handling
Hello all,
I'm having a problem with data handling. My input data is (dput in the
after the signature):
Date Time Fraction
06/19/13 22:15:39 0.3205
06/19/13 22:15:44 0.3205
06/19/13 22:15:49 0.3205
06/19/13 22:15:54 0.3205
06/19/13 22:15:59 0.3205
06/19/13 22:16:09 0.3205
Date in format month/day/year, Time in HH:MM:SS and fraction represents the
fractions of