similar to: Copying rows from a matrix using a vector of indices

Displaying 20 results from an estimated 20000 matches similar to: "Copying rows from a matrix using a vector of indices"

2013 Sep 06
1
Importing function that is previously imported by other package
Dear developeRs, I encounter the following problem: in the current version of my package FrF2, certain calls to a functioni do not work when package combinat is loaded, because function combn from combinat masks the function from utils that my package uses. I tried to solve this issue by importing function combn into the namespace of FrF2; I don't need to export it, I just want to use it
2006 May 08
3
Non repetitive permutations/combinations of elements
Hello all, I am trying to create a matrix of 1s and -1s without any repetitions for a specified number of columns. e.g. 1s and -1s for 3 columns can be done uniquely in 2^3 ways. -1 -1 -1 -1 -1 1 -1 1 -1 -1 1 1 1 -1 -1 1 -1 1 1 1 -1 1 1 1 and for 4 columns in 2^4 ways and so on. I finally used the function combn([0 1],3) that I found at the following link
2013 Jan 24
2
Please help R error message "masked from 'package:utils':combn"
Hi The message occurred from R, when I was selected of "optimization > block diagonal Fhiser matrix" and used the attached file on PFIM. Could you please advise me about the following message? ***************************** Loading required pakage: combinat Attaching package:'combinat' The following object(s) are masked from 'package:utils':combn
2007 Apr 10
1
R CMD Rdconv drops sections: arguments, seealso, examples (PR#9606)
I've created a .Rd file (below), then converted that to .sgml using R CMD Rdconv --type=Ssgm combn.Rd > combn.sgml The output (shown below) is missing some of the sections: arguments seealso examples If instead I convert to .d (below), the same sections are missing, and the "note" section is included but without the necessary newline.
2006 Jul 13
1
looping using combinatorics
I have a problem where I need to loop over the total combinations of vectors (combined once chosen via combinatorics). Here is a simplification of the problem: STEP 1: Define three vectors a, b, c. STEP 2: Combine all possible pairwise vectors (i.e., 3 choose 2 = 3 possible pairs of vectors: ab,ac, bc) NOTE: the actual problem has 8 choose 4, 8 choose 5 and 8 choose 6 combinations. STEP
2006 May 09
1
combn(n, k, ...) and all its re-inventions
It seems people are reinventing the wheel here: The goal is to generate all combinations of 1:n of size k. This (typically) results in a matrix of size k * choose(n,k) i.e. needs O(n ^ k) space, hence is only applicable to relatively small k. Then alternatives have been devised to generate the combinations "one by one", and I think I remember there has been a quiz/challenge about 20
2006 Oct 06
1
Sum of Bernoullis with varying probabilities
Hi Folks, Given a series of n independent Bernoulli trials with outcomes Yi (i=1...n) and Prob[Yi = 1] = Pi, I want P = Prob[sum(Yi) = r] (r = 0,1,...,n) I can certainly find a way to do it: Let p be the vector c(P1,P2,...,Pn). The cases r=0 and r=n are trivial (and also are exceptions for the following routine). For a given value of r in (1:(n-1)), library(combinat) Set <- (1:n)
2008 Jul 03
1
Problem in applying conditional looping
Respected All, I hope you are enjoying good health, I am tring to write a program in R but could not be very sucessful. My program draws random sample form bivariate normal distribution and then compute a variable PIJ. For certian samples some entries of variable PIJ is apearing as negative, which result in negative variance estimator. I want to introduce a loop in my program that verify the each
2006 Jan 30
2
yet another vectorization question
Dear R-helpers, I'm trying to develop a function which specifies all possible expressions that can be formed using a certain number of variables. For example, with three variables A, B and C we can have - presence/absence of A; B and C - presence/absence of combinations of two of them - presence/absence of all three A B C 1 0 2 1 3 0 4 1 5 0 6 1
2017 Nov 01
0
"prob" package alternative
> On Nov 1, 2017, at 12:51 PM, Tiby Kantrowitz <tlkantro at gmail.com> wrote: > > The prob package has been archived because it depends upon some other > packages which have issues. > > However, such projects as Introduction to Probability and Statistics in R > depend upon it for learning. There are a few other resources that also use > it. > > Does anyone
2015 Mar 23
2
Combinatoria
Hola Jorge, gracias por ayudarme antes de empezar. Ayer me fui a cama con tan solo escribir el título "Ecuaciones no lineales" Básicamente lo que voy a buscar es lo clásico, es decir, resolver cualquier ecuación no lineal, ya sea polinómica o trascendente, con una o varias incógnitas. Ejemplo típico: x^2 + y^2 = 1 y = sin x Si me van surgiendo dudas, aquí estaré, no lo dudéis. Por
2015 Mar 22
2
Combinatoria
Ya me extrañaba a mi! Mañana a primera hora miro todo lo que me comentas. Ahora estoy con ecuaciones no lineales y ya veo que hay que cargar librerias Muchas gracias. Un saludo El 23 de marzo de 2015, 0:08, Carlos Ortega <cof en qualityexcellence.es> escribió: > Hola, > > Por precisar un par de detalles: > > > - Con el paquete gtools se pueden generar: > - las
2017 Nov 02
2
"prob" package alternative
The issue is fAsianOptions. Is there a version that works with the latest version of R? If not, which version of it works with which version of R and where can it be found? I tried several at the archive already. Alternatively, is there another package that behaves similarly to prob? On Wed, Nov 1, 2017 at 6:17 PM, David Winsemius <dwinsemius at comcast.net> wrote: > > > On Nov
2015 Mar 22
3
Combinatoria
Hola amigos, muchas gracias por vuestra ayuda. Entonces veo que mi sorpresa era legítima. Por todos vuestros mails la conclusión es que: - En el módulo base de R no incluye combinatoria elemental, ni siquiera el número combinatorio Cm,n hay que cargar el paquete *combinat* - Y para las variaciones con repetición el paquete* gtools* - Y aún así no tenemos ni las combinaciones ni las
2015 Mar 21
3
Combinatoria
Hola buenos días, me presento, me llamo Miguel y 'soy de' y 'vivo en' Galicia. Soy profesor de secundaria (Bachillerato Adultos) y llevo 15 días estudiando R a un buen ritmo, pero todavía me faltan miles de cosas. He visto que R facilita, no solo el análisis de datos y que posee una potencia en cálculos estadísticos a cualquier nivel, sino gran caudal de recursos para Data Mining,
2013 Apr 12
2
processing matrix equation derived from rows of two matrices
Hi, May be this helps: ?tb[1,]%*%(((val-rep(meansb79[1,],5))^2)/6) #??????? [,1] #[1,] 1.47619 tryvarb<-c(1,2,3,4,4,4,4) ?var(tryvarb) #[1] 1.47619 tb[2,]%*%(((val-rep(meansb79[2,],5))^2)/6) #???????? [,1] #[1,] 1.904762 sapply(seq_len(nrow(tb)),function(i) tb[i,]%*%(((val-rep(meansb79[i,],5))^2/6))) # [1] 1.4761905 1.9047619 1.9047619 1.9047619 1.9047619 2.2857143 1.9047619 # [8] 1.9047619
2007 Apr 30
1
R CMD Rdconv drops sections: arguments, seealso, examples (PR#9645)
On Tue, 10 Apr 2007 timh at insightful.com wrote: > I've created a .Rd file (below), then converted that to .sgml using > R CMD Rdconv --type=Ssgm combn.Rd > combn.sgml > The output (shown below) is missing some of the sections: > arguments > seealso > examples > If instead I convert to .d (below), the same sections are missing, > and the "note"
2010 Nov 25
2
delete-d jackknife
Hi dear all, Can aynone help me about delete-d jackknife usually normal jackknife code for my data is: n <- nrow(data) y <- data$y z <- data$z theta.hat <- mean(y) / mean(z) print (theta.hat) theta.jack <- numeric(n) for (i in 1:n) theta.jack[i] <- mean(y[-i]) / mean(z[-i]) bias <- (n - 1) * (mean(theta.jack) - theta.hat) print(bias) but how i can apply delete-d jackknife
2015 Mar 22
2
Combinatoria
Hola Miguel, Sí se pueden obtener las variaciones con y sin repetición en R. Eso sí están un poco escondidas... Se pueden calcular de esta forma: #---------------------- > #Cargar el paquete gtools > library(gtools) > #Definir el conjunto sobre el que se hará el cálculo > x <- c('rojo', 'azul', 'verde') > #Utilizar la función "permutations()"
2017 Nov 02
0
"prob" package alternative
> On Nov 2, 2017, at 11:15 AM, Tiby Kantrowitz <tlkantro at gmail.com> wrote: > > The issue is fAsianOptions. Is there a version that works with the latest version of R? If not, which version of it works with which version of R and where can it be found? I tried several at the archive already. sessionInfo() R version 3.4.2 Patched (2017-10-04 r73465) Platform: