similar to: Lattice: reversing order of panel placement in conditional histograms

I've been trying to get a basic 5 question IVR survey working in an AGI script, and am having trouble with the SQL portion not updating the table. When I take out all the AGI references, and run just the perl script, the table updates with no problem(DBname,username,password have been substituted in this example for the actual values): #!/usr/bin/perl # # use DBI; $DATETIME =

From: Jyri Sarha <jsarha at ti.com> Also adds inline asm implementations of WORD2INT(x) macro for fixed and floating point. --- libspeex/resample_neon.h | 101 ++++++++++++++++++++++++++++++++++++++++++++++ 1 files changed, 101 insertions(+), 0 deletions(-) diff --git a/libspeex/resample_neon.h b/libspeex/resample_neon.h index ba93e41..e7e981e 100644 --- a/libspeex/resample_neon.h +++

Hi, I have a question about how to obtain the union of several data frame rows. I'm trying to create a common key for several tests composed of different items. Here is a small scale version of the problem. These are keys for 4 different tests, not all mutually exclusive: id q1 q2 q3 q4 q5 q6 1 A C 2 B D 3 A D B 4 C D B D I would like

- Use MAC16_16 macros instead of (sum += a*b) and unroll a loop by 2. It increase performance when using optimized macros (ex: ARMv5E). A possible side effect of loop unroll is that i don't check for odd length here. - Add NEON version of FIR filter and autocorr -- Aur?lien Zanelli Parrot SA 174, quai de Jemmapes 75010 Paris France -------------- next part -------------- diff --git

Please ignore my previous mail and patch, there is a new version :). Patch changes are: - Use MAC16_16 macros instead of (sum += a*b) and unroll a loop by 2. It increase performance when using optimized macros (ex: ARMv5E). A possible side effect of loop unroll is that i don't check for odd length here. - Add NEON version of FIR filter and autocorr - Add a section in autoconf in order to

----- Original Message ----- From: "Silvano" <silvano at uel.br> To: <r-help at r-project.org> Sent: Thursday, June 30, 2011 9:07 AM Subject: Tables and merge > Hi, > > I have 21 files which is common variable CODE. > Each file refers to a question. > > I would like to join the 21 files into one, to construct > tables for each question by CODE. >

any suggestions on the following gratefully welcome, I have a dataframe, which I am subsetting via labels atpi[, creativity] where (for example) atpi = as.data.frame(matrix(1:50, ncol = 5, nrow = 10)) names(atpi) = c("Q1", "Q2", "Q3", "Q4", "Q5") and creativity = c("Q1", "Q3", "Q4") I want to add an extra column

Hi, I have got this start situation: structure(list(subject = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L), .Label = c("s1", "s2"), class = "factor"), part = structure(c(1L, 1L, 2L, 3L, 4L, 5L, 1L, 1L, 2L, 6L, 6L), .Label = c("p1", "p2", "p3", "p4", "p5", "p9"), class =

Hello, I have a table (1) of the form q1 q3 q4 q8 q9 A 5 2 0 1 3 B 2 0 2 4 4 I have another table (2): q1 q2 q3 q4 q5 q6 q7 q8 q9 C 10 7 4 2 6 9 3 1 2 I would like to divide the numbers in table (1) by the number of the appropriate column in table (2): q1 q3 q4 q8 q9 A 5/10 2/4 0/2 1/1 3/2 B 2/10 0/4 2/2 4/1 4/2

R- Help Forum Working with the "likert" package and I can't figure out why my "bar" graphs are backwards (see attached). The percentages are place correctly but the bars are backwards. #Sample code # libraries library(likert) # create data band <- c("Band 3","Band 3","Band 3","Band 3","Band 3","Band

R- Help Forum Working with the "likert" package and find that my "bar" graphs are backwards (see attached) > summary(results) Item low neutral high mean sd 4 Q4 5 15 80 2.75 0.5501196 5 Q5 20 40 40 2.20 0.7677719 1 Q1 65 30 5 1.40 0.5982430 3 Q3 5 90 5 2.00 0.3244428 2 Q2 90 10 0 1.10 0.3077935

InDATA <-read.table("C:/Data/May 2004/season.txt",header=T) X <- decompose(InDATA) print(X) Period Connections Q1 67519 Q2 69713 Q3 68920 Q4 69452 Q1 70015 Q2 59273 Q3 57063 Q4 65596 Q1 73527 Q2 58586 Q3 69522 Q4 60091 Q1 51686 Q2 63490 Q3 55702 Q4 53200 Q1 51033 Q2 48175 Q3 52709 Q4 50106 Q1 50855 Q2 43466 Q3 48190 Q4 41702 Q1 48747 Q2 51441 Q3 42537

This is my first post to R-help and I look forward receiving some advice for a novice like me... I?ve got a simple repeated (4 periods so far) 10-question survey data that is very easy to work on Excel. However, I?d like to move the compilation to R but I?m having some trouble operating on count list data in a neat way. The data C > str(C) 'data.frame': 551 obs. of 13

Maybe a dumb question (I admit I haven't followed this thread very closely)... But why are you writing a new FTS driver? If squat allegedly does everything you need it to do, why don't you just take that plugin and fix it up to do what you need? That seems way easier than trying to create a FTS driver from scratch. michael > On January 7, 2019 at 7:05 AM Joan Moreau via dovecot

Hello - I upgraded from FC4 to FC6. My samba configuration (samba 3.0.1x) was working just fine until I upgraded to FC6 and Samba 3.0.24. I had shares who where protected and only some users and groups can access them. I used valid users = @wireless, where the group wireless had 10 users. Before the upgrade this was working just fine. Now nobody from @wireless group members can access the

Dear List, I have spent some time playing around with oscap and the RHEL OVAL feed (https://www.redhat.com/security/data/oval/v2/RHEL8/, also check Chapter 16 of the RHEL 8 Design Guide). Because I could not find an existing OVAL file for CentOS, I downloaded one of the RHEL8 files and managed to modify (eg. the rhel-8.1-e4s.oval.xml) it to make it work on a CentOS machine. Basically I just

Hi Guys, I'm using zoo package now. I found lag is not doing what I assumed. > x <- zoo(11:21) > z <- zoo(1:10, yearqtr(seq(1959.25, 1961.5, by = 0.25)), frequency = 4) > x 1 2 3 4 5 6 7 8 9 10 11 11 12 13 14 15 16 17 18 19 20 21 > lag(x) 1 2 3 4 5 6 7 8 9 10 12 13 14 15 16 17 18 19 20 21 > z 1959 Q2 1959 Q3 1959 Q4 1960 Q1 1960 Q2 1960 Q3 1960 Q4

sample report data that i want to forecast quarter quarter_index Revenue 2007 Q1 1 $3,856,799 2007 Q2 2 $4,243,328 2007 Q3 3 $4,930,369 2007 Q4 4 $5,443,579 2008 Q1 5 $5,164,830 2008 Q2 6 $5,104,413 2008 Q3 7

I have a data.frame named "df". The dput of df is at the bottom of this e-mail. What I'd like to do is replace the "n/a " values with NA. On Mac OSX, it works to do this: df[df == "n/a"] <- NA However, it does not work on Ubuntu. See below. Thanks in advance, Garrett > x <- df[27, 4] # complete data.frame dput is below > dput(x) "n/a?"

Hi, what would be a good way of enhancing the ancova function from the HH package when using a 2 factor ANCOVA? The current behaviour for the "ancova" function from package HH is: ---------------------------------------------- | P1 || P1 || P3 || P4 | | PS | <- the lattice strip ---------------------------------------------- | x|| x ||x ||x | |