similar to: Functions within functions in R and S-Plus

Hi, I am upgrading my project from 3.7 to 3.8. I find that following code used to compile in 3.7 but doesn't in 3.8 and I can't understand why. llvm::Function *mainFunc = ...; auto argiter = mainFunc->arg_begin(); llvm::Value *arg1 = argiter++; arg1->setName("obj"); But if I change the code to following it compiles: auto argiter = mainFunc->arg_begin(); llvm::Value

I create a function with an empty signature: void llvm_start_new_function() { llvm::outs() << "Staring new LLVM function ...\n"; Mod = new llvm::Module("module", llvm::getGlobalContext()); builder = new llvm::IRBuilder<>(llvm::getGlobalContext()); llvm::FunctionType *funcType = llvm::FunctionType::get(builder->getVoidTy(), false);

I am trying to build a function (C++ Builder) and at the same time extend its parameter set. Here's what I try to do: Value* arg0 = add_param_float("arg0"); Value* tmp = builder->CreateFAdd(arg0,some_previous_value); Value* arg1 = add_param_float("arg1"); The function add_param_float should add a 'float' parameter to the function and return its value. Right

I am trying to get a handle on IR builder, at least some basics. I ran through a tutorial here: Create a working compiler with the LLVM framework, Part 1 <http://www.ibm.com/developerworks/library/os-createcompilerllvm1/>, and it worked well enough. I have some simple code that creates a hello world IR. I am trying to now bring in some concepts from the Kaleidoscope tutorial, namely

Friends, I'm trying to pass an equation as an argument to a function. The idea is as follows. Let us say i write an independent function Ideal Situation: ifunc <- function(x) { return((x*x)-2) } mainfunc <- function(a,b) { evala <- ifunc(a) evalb <- ifunc(b) if (evala>evalb){return(evala)} else return(evalb) } Now I want to try and write this entire program in a single

Hi all-- We are planning an intervention study for adolescent alcohol use, and I am planning to use simulations based on a hurdle model (using the hurdle() function in package pscl) for sample size estimation. The simulation code and power code are below -- note that at the moment the "power" code is just returning the coefficients, as something isn't working quite right. The

Hy! I would like to know how run a montecarlo simulation with R. Thank you!!!! Francesca Matalucci __________________________________________________________________ Accesso Internet Gratis per utenti Excite! Attivalo subito! http://www.excite.it/hitech/accesso Il Mio Excite. Personalizza la tua Home page Excite come vuoi tu! http://www.excite.it AAA/Relazioni. Sfoglia gli annunci e trova la

Hi, R guys: I'm using L-BFGS-B method of optim for minimization problem. My function called besselI function which need non-negative parameter and the besselI will overflow if the parameter is too large. So I set the constraint box which is reasonable for my problem. But the point outside the box was test, and I got error. My program and the error follows. This program depends on CircStats

Could I have some suggestions as to how (various ways) I can display my confidence interval results? rm(list = ls()) set.seed(1) func <- function(d,t,beta,lambda,alpha,p.gamma,delta,B){ d <- c(5,1,5,14,3,19,1,1,4,22) t <- c(94.32,15.72,62.88,125.76,5.24,31.44,1.048,1.048,2.096,10.48) post <- matrix(0, nrow = 11, ncol = B) theta <- c(lambda,beta) beta.hat <- 2.471546 for(j

Hi again, It is probably me doing something wrong, but I have attached a trimmed down sample that shows the issue and the output that Clang 8.0.0 makes (using the binary release from llvm.org). I invoke clang as follows: clang -S -O3 -o Evergrowing.s -Wall Evergrowing.ll I tried using -O1, -O2, and -O3, but all where the same. Please notice that I renamed 'main()' to

I'd like to create a polar plot similar to those created by the polarFreq function in the openair package. However, this package seems to be specific to wind speed and direction, and requires a "ws" (wind speed) and a "wd" (wind direction) column. My data is unrelated to wind speed, but I'd like to be able to get a plot that does what polarFreq's plots do; I'd

I have a problem integrating the 'standard map' ( http://en.wikipedia.org/wiki/Standard_map http://en.wikipedia.org/wiki/Standard_map ) with deSolve: By using the modulo-operator '%%' with 2*pi in the ODEs (standardmap1), the resulting values of P and Theta, should not be greater than 2pi. Because this was not the case, i was thinking that the function 'ode' has some

Dear R users, I try to compute this summation, http://www.nabble.com/file/p25054272/dd.jpg where f(y|x) = Negative Binomial(y, mu=exp(x' beta), size=1/alp) http://www.nabble.com/file/p25054272/aa.jpg http://www.nabble.com/file/p25054272/cc.jpg In fact, I tried to use "do.call" function to compute each u(y,x) before the summation, but I got an error, "Error in X[i, ]

Hi, I am turning crazy. I try to integrate Asterisk 11.5.1 into Samba4 LDAP, but when I import the ldif file from contrib directory I get this error. ldbmodify -H /usr/local/samba/private/sam.ldb asterisk.ldif --option="dsdb:schema update allowed"=true ERR: (No such object) "objectclass: Cannot add cn=asterisk,cn=schema,cn=config, parent does not exist!" on DN

Hello expeRts, I need generate symbolize the autocovariances matrix of a Gaussian ARMA(1,1), for derivate it and evaluate. I try this codes, but whitout sucess vacv<-NULL vacv[1]<-1-2*phi*theta-theta^2 vacv[2]<-(1-phi*theta)*(phi-theta) vacv[3:n]<-acv[2]*(phi^(1:(n-2))) facv<-list() for(i in 1:2)

I have this maximum liklihood estimate problem i need to find the roots of the following: [sum (from i=1 to n) ] ((2(x[i]-parameter)/(1+(x[i]-parameter)^2))=0 given to me is the x vector which has length 100 how would I find the roots using R? I have 2 thoughts...... 1 is using a grid search ... eg. brute force, just choosing a whole bunch of different values for my parameter .... such as

I'd like to make some polar plots with R, but I can't seem to find anything designed to help with that. Is there anyway to get a real polar mode, where instead of x and y you have r and theta? How about a way to draw a circle? -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send

Hi guys. I have a dataset with 4 columns. In the first and second column I have the same qualitative variable referred to different teams of people. There are 10 teams in total and they compete against each other to perform a certain task whose result is stored in the third column for the team recorded in the first column, and in the fourth column for the team in the second column. For example,

What is 1. par.ests <- optimfit$par 2. fisher <- hessb(negloglik, par.ests, maxvalue=maxima); 3. varcov <- solve(fisher); 4. par.ses <- sqrt(diag(varcov)); Thanks a lot, fit.GEV <- function(maxima) { sigma0 <- sqrt((6. * var(maxima))/pi) mu0 <- mean(maxima) - 0.57722 * sigma0 xi0 <- 0.1 theta <- c(xi0, mu0, sigma0) #10/5/2007: removed assign() for maxima.nl

Hi all, is there a way to define the containment option for a sortable so that it is a class name instead of an id list? I have a case very similar to the sortable lists demo, the only difference is that I'm adding new list containers dinamically, so either I need to redo the Sortable.create calls for all new elements to include the newly added container, or having someway to have them