similar to: Plot Problem

Hello useRs and helpRs, Some time ago, in a gallaxy far away (here is the thread : http://finzi.psych.upenn.edu/R/Rhelp02a/archive/46532.html ) we discussed about a graph gallery showing the power of R in that domain. I did some work around that, and there is a (pretty advanced) draft here : http://addictedtor.free.fr/graphiques/displayGallery.php For instance, there are some of my graphs,

Dear All, is there a simple way to print a data.frame without its row.names? example: datum <- as.Date(c("2004-01-01", "2004-01-06", "2004-04-12")) content <- c('Neujahr', 'Hl 3 K.', 'Ostern') df1 <- data.frame(datum, content) print(df1) datum content 1 2004-01-01 Neujahr 2 2004-01-06 Hl 3 K. 3 2004-04-12 Ostern Can I get

Hello ! There is something quite simple I want to do with R but I found nowhere in the help how to do it. I just want to plot data which are in a matrix, every column being a data set and having the same x-axis (just an index). So for example if I have a 50 x 6 matrix I want 6 set of points on the same plot. I tried plot,new() plot(MATRIX[,1]) plot(MATRIX[,2]) ... but it replaces the previous

Hi, can you tel me how can I make a Forrest Plot with R? It is possible and easy or are there a more practical free software available? Than you Mic [[alternative HTML version deleted]]

New to R, can't afford SPSS! Why can't I assign spss variables? Here are the details. > ### I've read in my collaborator's sav file using read.spss, eg > children = read.spss(filename) > ### It has many variables > length(children) [1] 347 > ### and I would like to assign individual variables. > ### I can of course type out all the ones I want, eg >

Hello, My name is Philippe Favrot, I'm a french occupational doctor (working in Luxembourg), and I'm an "R beginner". I would be happy you could help me about the utilization of "R". Recently, I measured sound levels in a plant. Before the measuring, I divided the plant in 3 virtual rows and 8 virtual columns. I measured the sound level at each intersection of rows

Hello list, I'd like to know if there is a function that tells in which package is a given function. Something like : which.package("lda") [1] "MASS" Thank you. Romain -- ~~~~~~~~ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~ ~~~~~~ Romain FRANCOIS - http://addictedtor.free.fr ~~~~~~ ~~~~ Etudiant ISUP - CS3 - Industrie et

Good morning, (sorry for my english) i have some problems to put off by extimation ARIMA coefficients the ones not significatives. Exist a method to extimate only that significatives? i use the command: arima(). thanks to all Stefano [[alternative HTML version deleted]]

Hi, I have a grouping of some observations. I want to cluster them using hierarchical clustering and compare how the hierarchical clustering shows up vis-a-vis the groupings. Is it possible to do this in color? I guess what I am looking for is a way to color the labels of a hierarchical clustering plot using different colors according to the original grouping. Any suggestions? Many thanks and

Hi Everyone, I'm trying to use cutree to get the clusters after hclust. What I used is: mycluster<-cutree(cnclust,h=0.5) Now, my problem is, how can I get the actual clusters? Thanks! Best, Baoqiang Cao

Hello, I am looking for documentation (PDF ?) about doing clustering with the EM Algorithm on R... I'm sorry for this question which may be trivial... Thanks... Dominique

hi, is it possible to create a matrix with one row and according to add a row? in fact, at present, I'm doing an algorithm which fill a matrix. On the web site of CRAN, the package basic is impossible to be load! can you tell me where i can found it! Thanks Sabine --------------------------------- [[alternative HTML version deleted]]

Hello, On my barplot, I have on the axis y, the names of the rows of my matrix r_mat! is it possible to change the color of these names on my barplot? barplot2(t(r_mat),beside=TRUE,horiz=TRUE,plot.grid=TRUE,xlab="R",font.lab=4,las=2,xlim=c(0,1)) thanks, Sabine --------------------------------- [[alternative HTML version deleted]]

Hi all, I want to draw a line with the values of x marked in X axis. I tried with x <- c(0,6,12,18,24,30) #coordinates of points x y <- c(2,5,7,5,7,16) #coordinates of points y plot(x,type="n",xlab="Months",ylab="Y values",main="main",ylim=c(0,16),xlim=c(0,30)) lines(x,y) The graph shows by default an increment of the sequence in x axis that

hi all, I wish to draw on the same graphic device 3 functions. But i don't want them to be on different graph, i want to compare them on the same I don't need mfrow or mfcol, I need something else... 1 graph on 1 device inside this graph 3 ploted function. I saw something unsing data.frame, but i think it's overkill, and something less complicated must exist, if not why? why not

hi all a very simple question once again!!! can we change the "y" range in a histogram? e.g. x=rnorm(1000) hist(x,ylim=0.5,prob=T) #this does not work any suggestions???

That's probably a stupid question, but I'm looking for a low-level command which plots ellipse, specifying only center and deformation axes. The purpose is to illustrate bivariates gaussians with 2D .95 confident levels without using any specific library. Thanxs for your help, Guillaume

Dear List, I am using R to learn bootstrapping concepts. Not to be oblivious to the contributed packages of boot and bootstrap, I have opted to do the following as a way to hone my R skills. One example I am trying to work through is the following: x <- 1:20 Observed <- sample(x,20) Resamples <- replicate(1000,sample(Observed,replace=TRUE)) Boot.Means <- apply(Resamples,2,mean)

Dear All, How can I sort a data frame with respect to more than one variable? I know that for one variable X one may use: df[order(df$X), ] where df is the data frame containing X. Many thanks, Bernard --------------------------------- [[alternative HTML version deleted]]

I'm working on some heatmaps, and the person I'm working with would prefer a red-black-green color palette (red denoting gene induction and green denoting gene repression). Does such a palette exist already? If not, is there an easy way to create one? Thanks, Jake