Displaying 20 results from an estimated 1000 matches similar to: "Bonferroni simultaneous confidence intervals for multiple regression"
2009 Feb 02
1
wilcoxon test with bonferroni correction
Hi!
I need to run a wilcoxon (Mann-whitly, in fact) test with bonferroni
correction, as I am running 10 consecutive wilcoxon test not
independent, and I know that bonferroni will partially correct for
this problem, but I have no idea how to do it with R, I have been
looking in the archive but couldn't understand how to do it.
The format I am using at the moment is
r4_o <-
[1]
2012 Aug 29
3
Bonferroni correction for multiple correlation tests
Please can someone advise me how I can adjust correlations using bonferroni's correction? I am doing manny correlation tests as part of an investigation of the validity/reliability of a psychometric measure.
Help would be so appreciated!
Cheers,
Louise
2010 Sep 05
4
bonferroni en R
Hola a todos/as
estoy analizando un diseño factorial con una variable intrasujeto y una inter-sujeto. Ambas resultan significativas en el anova y quiero hacer un análisis por pares, pero aún no sé como puedo hacerlo en R. Me interesan ambos Bonferroni y Tukey. ¿Alguien podría indicarme?
Gracias
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2009 Jul 27
1
calculating p-values from t-values for a Bonferroni adjustment
I am performing a sequential bonferroni adjustment on the results of an
ANCOVA but the equation I have for calculating p-values from the t-values is
not working. I can't seem to find it anywhere else. This is the code I have
now: 2*(1-pt(t,df)) where t=t-value and df=degrees of freedom from the
ANCOVA. Is there an error in the code? maybe another way to find the
p-values? Help!
--
View this
2009 Oct 23
1
Bonferroni with unequal sample sizes
Hello-
I have run an ANOVA on 4 treatments with unequal sample sizes (n=9,7,10 and 10). I want to determine where my sig. differences are between treatments using a Bonferroni test, and have run the code:
pairwise.t.test(Wk16, Treatment, p.adf="bonf")
I receive an error message stating that my arguments are of unequal length:
Error in tapply(x, g, mean, na.rm = TRUE) :
2000 Aug 03
1
multiple comparison tests & simultaneous multiple plots
I am not sure if my message made it through, so here it is again!
Hi Rer's,
R-1.1.0
I have two questions for you:
1)
I am trying to complete a multiple comparison test after completing a
one-way ANOVA on some data. I think this is pretty reasonable.
aov(MetricSubset ~ GeneNameFactor)
works
pairwise.t.test(MetricSubset,GeneNameSubset,p.adjuxt.method=bonferroni,p
ool.sd=FALSE)
2006 Sep 11
2
Wilcoxon Rank-Sum Test with Bonferroni's correction
Dear all,
I am trying to run Wilcoxon Rank-Sum Test with Bonferroni's
correction. I have two lists: l0, l1:
mapply(function(x,y)wilcox.test(x,y)$p.value, l0, l1)
How do I run Bonferroni's correction on mapply? Any help is much apperciated.
Thanks,
-Raj
2009 Apr 01
0
How to set the number of multiple comparisons (Bonferroni-Holm)
Hello.
We have a question concerning the nonparametric analysis of a dataset, which
resulted in rejection of the null hypothesis (Kruskal-Wallis-test = H-test).
In order to find out which sample means actually are statistically
different, we want to do multiple comparisons with the Wilcoxon rank sum
test (= U-test); the p-level should be corrected according to
Bonferroni-Holm. Thus we decided to
2005 Jul 14
2
Partek has Dunn-Sidak Multiple Test Correction. Is this the same/similar to any of R's p.adjust.methods?
The Partek package (www.partek.com) allows only two selections for Multiple
Test Correction: Bonferroni and Dunn-Sidak. Can anyone suggest why Partek
implemented Dunn-Sidak and not the other methods that R has? Is there any
particular advantage to the Dunn-Sidak method?
R knows about these methods (in R 2.1.1):
> p.adjust.methods
[1] "holm" "hochberg" "hommel"
1998 Jul 16
1
R-beta: Re: Post-hoc tests
Matt,
Here's a Bonferroni-corrected multiple one-sample t-test that I wrote
some years ago. It took a while to get it into R, as na.omit doesn't
seem to handle vectors and I had to write a quick kludge (na.remove).
Another more general point was that I discovered that the help page for
t.test gives the name "parameters" for the degrees of freedom, as in S.
However, the name
1998 Jul 14
1
Are post-hoc tests being developed for R?
Hi-
Is anyone working on multiple comparisons of means or post-hoc tests
(ie: Tukey, Bonferroni) for R? I saw in the winter 98' archives of the R
mailing lists that these tests had not been implemented yet, I was just
wondering if I could look foward to having them. ;-)
I also looked through the contributed packages and didn't see anything
that offered such tests.
I guess I could check
2006 Jul 11
2
Multiple tests on 2 way-ANOVA
Dear r-helpers,
I have a question about multiple testing.
Here an example that puzzles me:
All matrixes and contrast vectors are presented in treatment contrasts.
1. example:
library(multcomp)
n<-60; sigma<-20
# n = sample size per group
# sigma standard deviation of the residuals
cov1 <- matrix(c(3/4,-1/2,-1/2,-1/2,1,0,-1/2,0,1), nrow = 3, ncol=3, byrow=TRUE,
dimnames =
2012 Oct 19
2
Post Hoc tests for ANOVA
Hi,
I was trying to figure out how to do post-hoc tests for Two Way ANOVAs and
found the following 2 approaches:
a. Do pairwise t-tests (bonferroni corrected) if one finds significance with
the ANOVA.
Link-
http://rtutorialseries.blogspot.com/2011/01/r-tutorial-series-two-way-anova-with.html
b. Do TukeyHSD on an aov model
Link-
2003 Oct 21
3
explaining curious result of aov
Hello. I have come across a curious result that I cannot explain.
Hopefully, someone can explain this. I am doing a 1-way ANOVA with 6
groups (example: summary(aov(y~A)) with A having 6 levels). I get an F
of 0.899 with 5 and 15 df (p=0.51). I then do the same analysis but
using data only corresponding to groups 5 and 6. This is, of course,
equivalent to a t-test. I now get an F of 142.3
2013 Dec 03
5
seleccionar columnas de un dataframe mediante variables
Buenos días a todos:
Para empezar, y como este es mi primer mensaje a la lista, me
presentaré. Mi nombre es Jorge Tornero y trabajo en el Instituto Español
de Oceanografía como Ayudante de Investigación. No soy usuario habitual
de R pero estoy tomando contacto con él de cara a un proyecto en el que
ando involucrado.
Mi consulta es:
Me interesaría poder seleccionar columnas de un dataframe,
2005 Jan 20
1
confidence intervals in Manova and Mancova in Splus
Anyone
I'm wondering how to make confidence intervals (bonferroni or simultaneous)
when using Manova and Mancova in Splus. I 'm doing manova with four variables
on length and four variables on weight (of salmon). The measuring is done on
different time points. I'm working on my master in the field between
biostatistics and fishery biology. If anyone knows a good book on mancova
2007 Mar 28
3
multi-level modeling & R?
A colleague was asking me if R does multi-level
modelling as opposed to multiple regression. Since I
have no knowledge of multi-level modelling (except 5
minutes googling ) I thought that I would as here.
Does are offer any multi-level modeling packages? It
looked like arm might be one but I was not sure.
Thanks
2009 Nov 17
2
:Problem with Looping
Hello,
Sometimes the looping (using "for") seems to skip some iterations.
An example:
arg <- matrix(NA,length(seq(.30,.5,.01)),1)
for (i in seq(.30,.5,.01)) {
arg[i*100-29] <- i
}
arg
What is the problem with this coding, please?
Thank you so much,
--
Bruno Cara Giovannetti, PhD Candidate
Economics Department
Columbia University
Personal Webpage: www.columbia.edu/~bcg2108
2005 Sep 15
3
means comparison in R (post-hoc test)
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Hi.
I have been using SAS for some time, and now I have discovered R. I am
very happy with it, but I have not found out how to perform some of the
multiple comparisons I was used to do in SAS.
With the SAS/STAT, I generally used the MEANS (for comparison of
arithmetic means) and the LSMEANS (for adjusted means) statements of the
GLM procedure (I
2012 Feb 02
1
Error con package agricolae
Hola a todos
Estoy trabajando con el package agricolae para realizar pruebas de medias y obtengo un error que no entiendo al trabajar las interacciones. Os explico:
Poseo un Diseño Completamente al Azar para el arreglo de tratamientos factorial de la forma 2*2*4. El modelo consta de 6228 observaciones, el esquema para el anova es:
A= 2 niveles={2,5}
B= 4 niveles={F1,F2,F3,F4}
C= 2