similar to: data.frame, data types, and apply

Hello, I can`t figure out how can increase the velocity of the fitting data by nls. I have a long data .csv I want to read evry time the first colunm to the other colunm and analisy with thata tools setwd("C:/dati") a<-read.table("Normalizzazione.csv", sep=",", dec=".", header=F) for (i in 1:dim(a[[2]]]) { #preparazione dati da analizzare

> On Aug 23, 2017, at 2:29 AM, Rolf Turner <r.turner at auckland.ac.nz> wrote: > > > On 23/08/17 18:33, Stefan Evert wrote: > >>> On 23 Aug 2017, at 07:45, Rolf Turner <r.turner at auckland.ac.nz> wrote: >>> >>> My reading of ?regex led me to believe that >>> >>> gsub("[:alpha:]","",x) >>>

Hello, I’d like to do next, see if you could help me please: I have a csv called “datuak” with a id called “calee_id” and a colunm called “poids”. I have another csv called “datuak2” with the same id called “calee_id”, (although there are “calee_id” that are in “datuak” but not in “datuak2” and inverse), and a column called “kg_totales” in which the values are repeteated for each calee_id

Try colnames(df)[4:6] <- c("x","y","z") -----Original Message----- From: r-help-bounces at stat.math.ethz.ch [mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of xmeng at capitalbio.com Sent: 21 December 2004 09:45 To: r-help at stat.math.ethz.ch Subject: [R] about colnames Hello sir: If there's a data frame(with name "df"): a b c d e f

Dear All, I have tried to calculate tree mean growth but I think the structure I used below (growthresumo) is not the most elegant, even though it worked. The only problem I had in this first part was that I cannot use 'summary', just 'mean' (sorry but 'R' is pretty new for me). >growthresumo <-

Hi, I want to use the value of variable to quote elements in matrix. For example, I have a matrix like:               y1   y2m1         1      2m2         3      4 where y1,y2,m1,m2 are column and row names.  I have two random character variable, say x,  that could be either  y1 or y2  and  y that could be either m1 or m2.  So can I  do like   Matrix[y,x] to quote elements?  I've tried this

Dear All, I created a script to calculate averages - two groups: "parcel" and "date" - and, based on these averages, make a graph. The problem is that 'R' does not recognize the first column even if I try to insert one. A brief example Raw data: Data <- sample(1:100, 30, replace = FALSE, prob = NULL) Date <-

Not sure if this tool already exists in some form, or if it's been talked about before.. but I got to thinking of a way to support FLAC in applications that haven't added support in their code: In windows, programs can be launched using the Microsoft Detours API (or similar). This API can be used to do binary instrumentation on the programs. This instrumentation can be used to intercept

Le 26 juil. 07 à 13:55, Georgi Alexandrov a écrit : > Vincent Dautremont wrote: > >> Hi, >> here I have another newcomer question :-) >> in the section 9.6.1 of this how too >> http://tldp.org/HOWTO/Adv-Routing-HOWTO/lartc.qdisc.filters.html >> we can read commands about filters : >> ------------------------------------------ >> >> # tc

On 23/08/17 18:33, Stefan Evert wrote: > >> On 23 Aug 2017, at 07:45, Rolf Turner <r.turner at auckland.ac.nz> wrote: >> >> My reading of ?regex led me to believe that >> >> gsub("[:alpha:]","",x) >> >> should give the result that I want. > > That's looking for any of the characters a, l, p, h, : . OK. I see

Hi All, I am (almost) successfully using apply() to apply a function recursively on a data matrix. The function is question is as.genotype() from the library 'genetics' apply(subset(chr1, names$breed == 'lab'),2,as.genotype,sep ="") Unfortuantely apply puts it's results into a matrix object rather than a data frame, tranforming my factors into numerics and

oops, i forgot to reply to the list :-/ Début du message réexpédié : > De : Vincent Dautremont <vdautrem@ulb.ac.be> > Date : 30 août 2007 16:58:26 GMT+02:00 > À : Ali Jawad <alijawad1@gmail.com> > Objet : Rép : [LARTC] Priotirize SSH Traffic > > try that > #tc qdisc add dev eth0 root handle1: prio > # tc filter add dev eth0 protocol ip parent 1: prio 1 u32

Hi, i''m sort of testing a configuration and things are not working sa i planned. i have the following network diagram: PC1 to 7 cnneced on the same ethernet hub. PC1 PC2 PC 3 PC4 PC5 PC6 on network 192.168.5.0 PC6 and PC7 on network 192.168.1.0 so PC6 work as a router. in addition, PC6 is connected to both network on the same device eth0. now on PC6, put a tbf on dev eth0 root

Dear Rusers, I would like some comments about the following results (under R-2.2.0) > m = matrix(1:6 , 2 , 3) > m [,1] [,2] [,3] [1,] 1 3 5 [2,] 2 4 6 > z1 = m[(m[,1]==2),] > z1 [1] 2 4 6 > is.matrix(z1) [1] FALSE > z2 = m[(m[,1]==0),] > z2 [,1] [,2] [,3] > is.matrix(z2) [1] TRUE Considered together, I'm a bit surprised about

Hi, directory<- "/home/arunksa111/data.new" #first function filelist<-function(directory,number,list1){ setwd(directory) filelist1<-dir(directory) direct<-dir(directory,pattern = paste("MSMS_",number,"PepInfo.txt",sep=""), full.names = FALSE, recursive = TRUE) list1<-lapply(direct, function(x) read.table(x,header=TRUE, sep =

Hi I try to create from a data frame a new one which contains only the numerical variables (or factorial ones). Is there any function which does this task directly ? Or, is there any function which return the mode of each columns of a data frame. ? Thanks a lot for any help you can offer me, Vincent Spiesser

Folks, I have a very basic question. The solution eludes me perhaps because of my own lack of creativity. I am not attaching a fully reproducible session because the issue may well be becuase of the way the data file is, and the data file is large (and I don't know whether I can legally distribute it). If people can suggest things that might be wrong in my data or the way that I am reading it,

Hi All, I don't have a "I need help" question, so much as a query into any update whether 'R' has made any progress with some of the core functions retaining classes. As an example, because it's one of the cases that most egregiously impacts me & my work and keeps pushing me away from 'R' and into other numerical languages (such as NumPy in python), I

Hi All, I don't have a "I need help" question, so much as a query into any update whether 'R' has made any progress with some of the core functions retaining classes. As an example, because it's one of the cases that most egregiously impacts me & my work and keeps pushing me away from 'R' and into other numerical languages (such as NumPy in python), I

Suppose I have x<-data.frame(v1=1:4, v2=c(2,4,NA,7), v3=rep(1,4), v4=LETTERS[1:4],v5=rep('Z',4)) or a much larger frame, and I wish to test for and remove the constant numeric columns. I made: is.constant<-function(x){identical(min(x),max(x))} and apply(x,2,is.constant) # Works for numerics x[,-which(apply(x,2,is.constant))] I'd really like to be able to