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Good Evening Is there a setting that I can change in R so that I get either a warning or an error message if I reference non-existent data in a data frame? For example I get no warning or error message with the following: > set.seed(2013) > df0=data.frame(cbind(x=rnorm(1000),y=rnorm(1000))) > df0$z=df0$w > head(df0) x y 1 -0.09202453 1.51179695 2 0.78901912

Hello, I am trying to achieve something which I *think* is possible using rowsum, but a little help should be useful: Consider the following dataframe DF0: A B C 89 1 140 89 06 20 89 29 137 89 52 13 89 57 10 89 97 23 89 1 37 89 1 12 89 1 3 52 1 11 52 1 31 52 1 16 52 1 6 52 1 10 52 1 13 52 1 10 52 1 25 52 1 2 52 59 38 52 97 75 57 1 14 57 1 13 57 1 14 57 114 12 57 1 23 57 06 26 I need create a

Hola Consulto por un problema que no consigo resolver. Tengo un dataframe con muchas columnas todas de texto. Cada columna tiene solamente un valor válido y el resto son NAs. También cada fila tiene un único valor válido. Quiero colapsar ese data frame en uno que tenga solamente una fila y todas las columnas. Intenté con loops, while, apply y otros parecidos pero no lo logro El ejemplo del

Hi there I am new user of r, i would need some help to translate som code for vectors in matlab to r. I have managed to translate the first 7 rows, but not the rest. Could anyone give me any suggestions for this problem?? Matlab code: tempo=[]; temps=[]; tempn=[]; tempao=[]; tempas=[]; tempan=[]; for k=1:5 tempo = [tempo n_o(k,:)]; temps = [temps n_s(k,:)]; tempn = [tempn

Javier Muchas gracias por su respuesta Aunque no está funcionando, pues si ejecuto: EncDTE1<- t.EncDTE1[ !is.na(t.EncDTE1$Var1),] obtengo Var1, Var2, Var3,...Varn con datos "texto", NA, NA....NA Pero al ejecutar EncDTE1<- t.EncDTE1[ !is.na(t.EncDTE1$Var2),] obtengo Var1, Var2, Var3,...Varn con datos NA,"texto", NA....NA Estoy tratando de dar la vuelta con el loop

Hola a todos, -Estoy estudiando el efecto de dos genotipos (~tratamientos) en la aparición de síndrome metabólico (MetS) con datos longitudinales recogidos a tiempo 0,7,10,15,20 y 25 años. -He hecho un dataframe con las siguientes variables MetS: Síndrome Metabólico (Si=1,No=0) bmi: Indice de masa corporal (IMC) cuando se produce la conversión a MetS+ . Para los que permancen MetS-, esta variable

Hi all, I'm trying to use the package read.table within a foreach loop. I'm grabbing 500M rows of data at a time from two different files and then doing an aggregate/tapply like function in read.table after that. I had planned on doing a foreach loop 39 times at once for the 39 files I have, but obviously that won't work until I figure out why the segfault is occurring. The

Hi, If df is a dataframe, its last column can't be deleted using "[<-", but other columns can be deleted this way. Example: > (df <- df0 <- data.frame(x = 1:3, y = 4:6, z = 7:9)) x y z 1 1 4 7 2 2 5 8 3 3 6 9 > df[, "z"] <- NULL Error in x[[jj]] : subscript out of bounds > df[, 3] <- NULL Error in x[[jj]] : subscript out of bounds >

Dear R buddies, This weekend I became interested in solving Google Code Jam problems using R. I guess R may work very well in this kind of contests but the input of file has been a problem for me. Take this case for example (http://code.google.com/codejam/contest/dashboard?c=agdjb2RlamFtchALEghjb250ZXN0cxjRzBQM), the files are usually of the form: A(number of lines for group 1) a11 a12 a13 a21

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Dear Help-Rs,   I have data similar to the following:   DF <- structure(list(X = 1:22, RESULT = structure(c(2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c("NEG", "POS"), class = "factor"), YR_MO = c(201011L, 201012L, 201101L, 201102L, 201103L, 201104L, 201105L, 201106L, 201107L, 201108L, 201109L, 201011L,

Hello, I have a csv file with many variables, both characters and integers. I would like to load it on R and do some operations on integer variables, the problem is that R loads the entire dataset considering all variables as characters, instead I would like that R makes the distinction between the two types, because there are too many variables to do: x1<-as.integer(x1)

Dear Heinz, ---------------------------------------------- > On Dec 17, 2018, at 10:19 AM, Heinz Tuechler <tuechler at gmx.at> wrote: > > Dear All, > > do you think that use of a data argument is best practice in the example below? No, but it is *normally* or *usually* the best option, in my opinion. Best, John > > regards, > > Heinz > > ###

FWIW, before all the examples are changed to data frame variants, I think there's fairly good reason to have at least _one_ example that does _not_ place variables in a data frame. The data argument in lm() is optional. And there is more than one way to manage data in a project. I personally don't much like lots of stray variables lurking about, but if those are the only variables out

Here is a drop-in replacement for the R incomplete beta function. src/math/pbeta.c It is a slightly modified version of the cephes library one from Netlib. In the few cases I tried it seems to give at least 14 digit agreement with the one in S-PLUS (its hard to get more). I'm not sure what performance is like. I'd like to know if it helps with some of the problems which have been

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I have a failure in 'make check' and I would appreciate assistance regarding what to do about it. Thanks -Don Installing R-1.2.3 on build[99]% uname -sr SunOS 5.8 (for those who may recall my previous request for help, I have updated GCC to 2.95.3, and configured with gcc, GCC's c++, and f77 [not g77]) Running 'make check' got this: creating `no-segfault.R'

Am Freitag, den 26.08.2005, 12:50 +0200 schrieb Holly Bostick: >>Problem solved: > >>http://portal.suse.com/sdb/en/2005/05/dkukawka_hal_mountpoints.html > > Thanks Hiji, that was useful for me too. Thats an ugly workaround that should be forbidden. See Below. > > It might be nice to be able to symlink "d::" to /dev/hdc > > and have wine figure out

Hi, I'm bit confused about ecdf (read the help files but still not sure about this). I have an analytical expression for the pdf, but want to get the empirical cdf. How do I use this analytical expression with ecdf? If this helps make it concrete, the pdf is: f(u) = \sum_{t = 1}^T 1/n_t \sum_{i = 1}^{n_t} 1/w K((u - u_{it})/w) where K = kernel density estimator, w = weights, and u_{it} =

Dear Users, I would like to simulate an AR(1) (y_t=ct1+y_t-1+e_t) model in R where the innovations are supposed to follow a t-GARCH(1,1) proccess. By t-GARCH I want to mean that: e_t=n_t*sqrt(h_t) and h_t=ct2+a*(e_t)^2+b*h_t-1. where n_t is a random variable with t-Student distribution. If someone could give some guidelines, I can going developing the model. I did it in matlab, but the loops