similar to: Time line plot in R?

Hi, Can anybody tell me what the message below means and how to overcome it. Thanks, Neil Warning message: X matrix deemed to be singular; variable 2 in: coxph(Surv(age_at_death, death) ~ project$pluralgp + project$yrborn + ......... >

What is the best way to produce a barplot from my data? I would like the barplot to show each person with the values stacked val1+val2+val3, so there is one bar for each person When I use barplot(data.matrix(realdata)), it shows one bar for each value instead. To post here, I created an artificical data set, but it works fine. fakedata <- as.data.frame(list(LETTERS[1:3])) colnames(fakedata)

I got simple x,y pairs of data and simple scatterplot and just cannot figure how to do it , there are many examples but always there is error popping out please show me an example stripped with additional data just core of what I need to do to get this damn line -- View this message in context:

I'd like to convert a dist into a table/matrix/thingy of the form: A B value A C value B C value (assuming the dist was over 3 names). Is there a way to do this without using a for loop? -- Taral <taralx at gmail.com> "Please let me know if there's any further trouble I can give you." ? ? -- Unknown

Dear R users, I am facing a pretty a unusual problem while converting character to numeric. Any input would be appreciated. Below is the code and error faced: --------------------------------------- *> str(cmie.dts)* *'data.frame': 4397 obs. of 1 variable:* * $ INE001A01036: chr "1482181740.000000" "1482181740.000000" "1482181740.000000"

What I want to do is create a horizontal bar chart matrix for a set of data that have a common set of variables (e.g., % of As, % of Bs, etc.) listed on the Y-axis and groups (e.g., Classes) on the X-axis. The key here is that the bars for each individual class plot are "centered" rather than left or right-justified. In archaeology plots similar to this are called battleship curves or

I would like to output a nicely formatted data frame to a bitmap. Is this possible in R? -- View this message in context: http://r.789695.n4.nabble.com/Table-Frame-output-tp4636790.html Sent from the R help mailing list archive at Nabble.com.

Dear useRs, i have certain commands for some operations in R. They are good if you have a small dataset but my dataset, apart from what i used in the recent past, is prety large. I want to convert these massive sets of commands into a simple loop. Your help is required on it thanks in advance eliza kindly note: "e" is matrix whose each column has to be executed into a distance vector

Dear all, I have a data frame in which the columns need to be ordered. The first column X is at the right position, but the remaining columns X1-Xn should be ordered like this: X1, X2, X3 etc instead of like below. > colnames(pos1) [1] "X" "X1" "X10" "X11" "X12" "X13" "X14" "X15" "X16"

Hi there, I'm trying to remove multiple columns by name from a data.frame. As a result I need to get back the modified data.frame without the removed columns. My columns I want to delete are listed in a vector called "delete". data <- read.csv2("data.csv") delete <- c("col1", "col2", "col3") newData <- subset(data, select =

Dear R Plots without par arguments do start not at zero (means, the box around is somwhere outside the specified plotrange). How to start really from zero, pe. basline y=0? every standart par works like this: x<-seq(1,10,0.1) y<-sin(x) plot(sin(x)) Thanks for help Marc -- Ist Ihr Browser Vista-kompatibel? Jetzt die neuesten Browser-Versionen downloaden:

Hi everyone, I have the following problem: I have three variables, 'group', 'city' and 'pressure' There is an interaction effect between group and city and I'd like to show this in an interaction plot: interaction.plot(group, city, pressure, type="b", col= c(1:2), leg.bty="o", leg.bg="blue", lwd=1,

Dear List, I recently started using R and I have a simple question. I am running R (v. 2.12.1) and Rcmdr (v.1-6.3) on Mac (Snow Leopard). I am using a data set I used before for practicing ANOVA with R, so I know what the results should look like. I can get ANOVA table using both Rcmdr and GUI. However, I cannot make R prepare the ANOVA diagram (with boxplots, showing the data points, including

I have a dataframe in which I have values 0-255, I wish to transpose them such that: if value > 127.5 value = 1 if value < 127.5 value = -1 I did something similar using the "binarize" function of the biclust package, this transforms my dataframe to 0 and 1 values, but I wish to use -1 and 1 and looking for a way in R to do this. Brian

Hello R-Help, ----------------------------------------------------------------------------------------------------------------------------------------- Issues (there are 2): 1) Possible bug when using lmtest::encomptest() with a linear model created using nlme::lmList() 2) Possible modification to lmtest::encomptest() to fix confusing fail when models provided are, in fact, nested. I have

Hi, I am running my code in a cluster at Arizona State University. I have a huge climate data, 66000 X 500 I am not sure if I can find correlation of such a huge data in the cluster. Normally I allocate 20000M and operate on 5 X 20000. Even this is taking lot of time. Is there any way I can find cl = cor(cdata) utilizing the computers in the clusters(I am using 32 nodes ). I am using the

I am very new to R statistics. Have installed R-2.15.2 ; Rcmdr 1.9-2 ; RStudio 0.97.237 on Debian Squeeze and also windows7 I can Import from Excel File OK .Workbook <- loadWorkbook("/media/4C90-B739/Oct13-Dec21Bsl.xls") JJData <- readWorksheet(.Workbook, "Oct13-Dec21Bsl") remove(.Workbook) have a data frame with following. DATEEVENT

Hello, I''m trying to compile wxruby for Ruby 1.9 on Ubuntu Karmic 64 bit, but I can''t get it to work. I''ve already done this for the 32 bit version (on another machine, of course), so I don''t see where''s the problem with that. I thought, I had all neccessary libraries installed, but maybe you know better... After compiling for a long time, rake fails

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Puppet 0.25.1 - code name "zoot" - is now available. The 0.25.1 release is a maintenance release in the 0.25.x branch. The release is available at: http://reductivelabs.com/downloads/puppet/puppet-0.25.1.tar.gz http://reductivelabs.com/downloads/gems/puppet-0.25.1.gem Please report issues and feedback via the Reductive Labs Redmine site: