similar to: scheduling R tasks under windows

I run a batch file with the following command in Windows XP: C:\R\R-2.12.1\bin\Rterm.exe --no-save --no-restore <C:\users\me\file.R> C:\users\me\file.out 2>&1 Is there any way to get only the output of R in file.out, without getting all the code from file.R too? Any help greatly appreciated, Mikkel

Is there any function in R like is.not.found(x, y) meaning if you can't find object x, then use object y?? Mikkel Grum

Is the following expected behaviour for a date used in an ifelse function? > date <- Sys.Date() > date [1] "2007-12-30" > ifelse(TRUE, date-1, date) [1] 13876 > ifelse(FALSE, date-1, date) [1] 13877 > ifelse(TRUE, as.character(date-1), date) [1] "2007-12-29" > if (TRUE) {date} [1] "2007-12-30" It would seem more natural to me if a date produced

I want to do something like df[df$b %in% df2[i, 2], ] where df$b is a numeric vector and df2[i, 2] is a factor with levels like "7:9, 12:14". For example: a <- c(paste("A", 1:10, sep = ""), paste("B", 1:10, sep = "")) b <- 1:20 df <- as.data.frame(cbind(a, b)) df$b <- as.numeric(levels(df$b))[as.integer(df$b)] f <-

I'm trying to select a subset of a dataframe while dropping some factors. While the dataset gets smaller all Factor levels remain and I need to get rid of them. Strangely enough, I am almost certain that the same code on the same data worked OK earlier today - and it is not the first time that I'm not able to replicate earlier results with this command (I know, I might just be going

Dear useRs, I'm writing regular survey reports using Sweave. Each report has several sections along the lines of: \section*{Disease X} <<MapX,fig=TRUE,echo=FALSE>>= image(vectorx,vectory,matrixz) @ Notes with or without Sexpr{a}. \vfill \pagebreak \section*{Disease Y} <<MapY,fig=TRUE,echo=FALSE>>= ...etc. Often one or more of the diseases is not observed (all

How do I get output with "\color{blue}", i.e. with only one backslash??? > "\color{blue}" [1] "color{blue}" Warning messages: 1: '\c' is an unrecognized escape in a character string 2: unrecognized escape removed from "\color{blue}" > "\\color{blue}" [1] "\\color{blue}" > Any help greatly appreciated. Best regards,

I'm changing some functions from storing data in SQLite (using RSQLite) to storing it in PostgreSQL (using RODBC). When trying to store very long character fields I get the following message: > sqlSave(pg, Grids, rownames = FALSE, append = TRUE) Warning messages: 1: In odbcUpdate(channel, query, mydata, paramdata, test = test, verbose = verbose, : character data truncated in column

I'm running an R script in Rterm and would like the user to be prompted for input as in: id <- readline("Please enter ID: ") myfunction(id) . . . etc. This works when I run one line at a time in RGui, but not when I try to run the script in Rterm (I'm working with R 2.2.0 in Windows Server 2003). Is there any way to do this? Mikkel

Dear R-helpers, I get GPS readings with bug counts (bugs meaning insects in this case) made along rows in crop fields and use these to make maps of bug distribution. The GPS readings are not quite accurate enough for my purpose, so since I know what row each reading is made in, I adjust the latitudinal coordinate using: grd<-lm(lat~lon+Row,data)

I'm trying to insert rows of a data.frame into a database table, or update where the key fields of a record already exist in the table. I've come up with a possible solution below, but would like to hear if anyone has a better solution. # The problem demonstrated: # Create a data.frame with test values library(RODBC) tbl <- data.frame( key1 = rep(1:3, each = 2), key2 =

I've created a chart with times that employees have entered data on named tasks as in the following example: Employee <- c(rep("Tom", 127),? rep("Dick", 121),? rep("Sally", 130) ) Time <- c(seq(as.POSIXct("2011-09-12 07:00:00"), as.POSIXct("2011-09-12 14:00:00"), 200), seq(as.POSIXct("2011-09-12 07:00:00"),

Is there a way of removing all rows with missing values from a data frame? I usually use subset(x, var1!="NA") and repeat for each variable. It would be nice to be able to do it in one fell swoop. Also, surprisingly, it doesn't always work. Sometimes I'm left with an empty set even though not all rows have missing values for the variable. Cheers, mikkel Mikkel Grum,

I have a script that runs as a cron job every minute (on Ubuntu 10.10 and R 2.11.1), querying a database for new data. Most of the time it takes a few seconds to run, but once in while it takes more than a minute and the next run starts (on the same data) before the previous one has finished. In extreme cases this will fill up memory with a large number of runs of the same script on the same data.

Can anyone tell me what's wrong with this command?? xx<-subset(x,LOCAL.NAME==c("Chifumbata","Chikota"),select=c(13,16,19,23,26,2 9,30,33:48)) Warning message: longer object length is not a multiple of shorter object length in: LOCAL.NAME == c("Chifumbata", "Chikota") both of the following commands work fine

Is there a way of extracting mean distance or dissimilarity for a given strata from a 'dist' or 'dissimilarity' object, e.g. extract mean distances for each species in Anderson's iris data? data(iris) iris.dist<-dist(iris[,1:4]) then what? Mikkel Grum, PhD Genetic Diversity Scientist International Plant Genetic Resources Institute (IPGRI) Sub-Saharan Africa Group ***

I'm trying to plot four different sorghum types on a plot using a different colour/symbol combination for each sorghum type (TYPBOTA in the script below). What am I doing wrong?: plot(xx$LATITUDE,xx$SFD1, points(xx$SFD1,xx$LATITUDE, col=1:4[codes(xx$TYPBOTA)],pch=c(4,3,1,2)[codes(xx$TYPBOTA)]) grid() I get the following error message Error in 1:4[codes(xx$TYPBOTA)] : NA/NaN argument

I have two problems where I've come up with some code that will do the analysis that I want, but it looks pretty clumsy. In the first case, I calculate the variance on five different columns for each of 14 clusters and get them into one matrix. I get the job done, but I would have thought that it could be done in one or two lines, not six, and be generalized so that it didn't matter how

I'm trying to plot observations against observation dates and getting julian dates along the x-axis: library(date) Week<-as.date(c("05/02/03","05/09/03","05/16/03","05/23/03","05/30/03","06/0 7/03","06/14/03")) Leafminers<-c(0,2,5,10,4,6,5) Diglyphus<-c(0,0,4,5,7,3,1) LeafDig<-cbind(Week,Leafminers,Diglyphus)

Hi Can anyone explain why a date becomes numeric when you loop over a series of dates? > dt <- Sys.Date() > dt [1] "2017-11-14" > class(dt) [1] "Date" > dts <- dt - 1:0 > class(dts) [1] "Date" > > for (i in dts) { + print(i) + print(class(i)) + print(as.Date(i, "1970-01-01")) + print(class(as.Date(i,