similar to: Mixed effects model help

Dear R-devel & Translation Teams, In order to monitor the progress of the translation for the pt_BR team I wrote a script to summarize the status of the translations. It wasn't difficult to extend it to the other languages so I decided to set up a page with the summaries of the translation for all languages for which currently exist a translation.

Full_Name: Fernando Henrique Ferraz Pereira da Rosa Version: 1.8.0 OS: Linux 2.4.21 Submission from: (NULL) (200.206.211.169) After installing R 1.8.0, the R DBI interface stopped working. I tracked it down as a problem in the 'methods' package, that comes in the default installation. Somehow the function '.valueClassTest' which is defined on package 'methods',

Hi, I'd like to get away from SAS, but I don't really know R well enough at this point to know if it would be good for this project. I tried to describe the essence of the project below without getting bogged down in details. It starts when I receive a data flat file. There's lots of columns, but the relevant ones are: custid (customer ID number) saledt (date of sale)

Dear r-useRs, After a couple of years in a 'R exile' of sorts, I've recently changed jobs and my current employer (an American multinational in the food manufacturing industry) is much more open than my past employer (which wouldn't even want to hear about anything that didn't begin with SAS...). So, after my insistence corporate IT is now considering adopting R as part of our

Dear r-useRs, After a couple of years in a 'R exile' of sorts, I've recently changed jobs and my current employer (an American multinational in the food manufacturing industry) is much more open than my past employer (which wouldn't even want to hear about anything that didn't begin with SAS...). So, after my insistence corporate IT is now considering adopting R as part of our

Hi, I'd like to know if it's possible to specify different contrast matrices in lm() for a factor that is nested within another one. This is useful when we have a model where the nested factor has a different number of levels, depending on the main factor. Let me illustrate with an example to make it clearer. Consider the following data set: set.seed(1) y <-

Hi Now a more theoretical question. I have two correlation matrices - one of a set of variables under a particular condition, the other of the same set of variables under a different condition. Is there a statistical test I can use to see if these correlation matrices are "different"? Thanks Mick

Full_Name: Adriano Azevedo Filho Version: 2.9.0 OS: Windows Vista Submission from: (NULL) (201.68.79.62) The error message produced when the function name typed in the console is misspelled in the Portuguese translation. This is not a new issue but as it is around for sometime I've decided to report. As this is a frequent message when beginners start using R, it gives an unfortunate bad

Hello, I have problems using lattice graphics together with Sweave under Windows XP and R 2.0.0; 2.0.1 Patched; 2.1.0 devel respectively. Base graphics are o.k., but for lattice graphics empty files (.eps and .pdf) are generated. The only workaround I found was to write and read the respective figures explicitely using postscript() and includegraphics{}. Have I missed something to solve this

I want to specify a two-factor model in lme, which should be easy? Here's what I have: factor 1 - treatment FIXED (two levels) factor 2 - genotype RANDOM (160 genotypes in total) I need a model that tells me whether the treatment, genotype and interaction terms are significant. I have been reading 'Mixed effects models in S' but in all examples the random factor is not in the main

Dear R-developeRs, Attached follows a patch against svn 34959 that adds the printing of p-values to the TukeyHSD.aov function in stats package. I also updated the corresponding documentation file and added a 'see also' reference to the simint function of the multcomp package. As it was already brought up in a previous thread [1] in R-help, one can obtain the adjusted

Hello list, I suspect this is more a linux question than an R question, but I'll describe my situation in case anyone here knows of an elegant solution. I'm using Sweave and R to create thousands of customized reports. Within an R loop, I have R create a table.tex file using the CAT function which, for each iteration, creates a unique table.tex file in a subdirectory of the directory

This pre-announcement is being sent for information to both R-help and BioC. Please use R-devel at r-project.org for any follow-up discussion. ----------------------------------------------------------------------- We are about at the end of a several-week process of adding support for non-Latin character sets and non-Western-European languages to R. - For Linux users, R works in the UTF-8

This pre-announcement is being sent for information to both R-help and BioC. Please use R-devel at r-project.org for any follow-up discussion. ----------------------------------------------------------------------- We are about at the end of a several-week process of adding support for non-Latin character sets and non-Western-European languages to R. - For Linux users, R works in the UTF-8

Hi, I happen to re-write my codes to save memory and my approach is write my obj into file first and later I load it. However, it seems like: load(filename) can load the object but the function returns the name of the object instead of the reference to it. For example, I have an object called r0.prune, which is saved by save(r0.prune, file='r0.prune') and later, I want to load it by

Dear R-devel, There seems to be a bug in the Startup section, regarding the R_PROFILE environment variable in Windows. If not a bug in the Startup itself, perhaps a bug in the documentation. According to ?Startup: Then R searches for the site-wide startup profile unless the command line option '--no-site-file' was given. The name of this file is

Hi, If I have a vector: junk <- c(2,0,0,3,0) and want to access, say, all the elements that are greater than zero. I just do: junk[which(junk>0)] Now, If I have a list: jlist <- list(NULL,c(1,0),NULL,c(1,2,3), NULL) and want to access all the elements that have length greater than zero, I know how to find the elements with: which(sapply(jlist,length)>0) But how do I get a

Hi everyone, I'm hoping you can give me some pointers. I have a requirement to draw multiple (103) xy line plots onto one output device. Ideally the plots should be displayed in a hexagonal grid (example at www.maladmin.com/example.jpg). I can calculate the locations for each waveform but am wondering how to create multiple plotting areas. I have come accross references to a package grid

Back in January there was a mail thread on this subject ( http://lists.xensource.com/archives/html/xen-devel/2005-01/msg00659.html ), however I see that blkfront still does not include ioctl support for disk geometry. So, any application that uses "sfdisk -g" to get the geometry of a partition, or disk, will fail when run in DomU. Is this a deliberate omission? Nick Logan

Hi, Imagine a vector x with elements (1,2,1,1,3,5,3,3,1) and a vector y with elements (2,3). I need to find out what elements of x match any of the elements of y. Is there a simple command that will return a vector with elements (F,T,F,F,T,F,T,T,F). Ideally, I would like a solution that works with dataframe colums as well. I have tried x==y and it doesn't work. x==any(y) doesn't work