similar to: cat function within a loop

'barplot' doesn't seem to work with vcd library. Am I supposed to detach vcd when I want to use barplot? Here's an example. Say I have the following matrix, > m <- matrix(c(1,2,3, 4,5,6, 3,4,5, 2,3,4), ncol=4) > m [,1] [,2] [,3] [,4] [1,] 1 4 3 2 [2,] 2 5 4 3 [3,] 3 6 5 4 Then > barplot(m) gives a barplot of the data. However,

Hi all, Easy question for you (which I failed to find the answer to in the FAQ etc). I've recently been forced to switch from linux to windows (currently windows NT), and my usual habit of putting lots of "cat" statements in slow functions to get an idea of the progress rate is no longer useful. Why -- because R waits until the function is completely finished before printing the cat

All, Does anyone know if there is an option I can set to turn screen-buffered output on and off with the win32 rgui? (Apart from the point and click method). I am running some simulations where it is useful to watch output but it gets mildly tiresome having to manually switch things on and off via the gui. Thanks Toby. > version _ platform i386-pc-mingw32 arch

Full_Name: Markus Liedgens Version: Ever since 1.6 OS: Windows 98 / Windows Xp Submission from: (NULL) (81.63.111.226) To control the progress of a function one can consider to use print() to issue a message in the command window. However, using Win98 / R 1.9 or WinXP / R 2.0, this approach is of little usefulness, since all the print() commands are issued at once, just before the control

a warning message appears when i use the chisq.test ,but it doesnt appear everytime, why? "Warning message: Chi-squared approximation may be incorrect in: chisq.test(matrix(c(20.1, 18.5, 2.6, 32.9, 23.5, 5.4), nc = 2)) " why does the warning message appear, please? Thank you very much here is the data which I have tried appear and not appear warning message have warning message

Hello, I have a problem concerning logistic regressions. When I add a quadratic term to my linear model, I cannot draw the line through my scatterplot anymore, which is no problem without the quadratic term. In this example my binary response variable is "incidence", the explanatory variable is "sun": > model0<-glm(incidence~1,binomial) >

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Dear R helpers, I would like to have abline, for a lm model for example, lying within data range. Do you know how to get it? Thank in advance Nguyen D Nguyen #CODE x<- rnorm(200, 35,5) y<- rnorm(200, 0.87,0.12) plot(y~x, xlim=c(0,50), pch=17, bty="l") abline(lm(y~x)) # I would like abline is between min(x) and max(x) [[alternative HTML version deleted]]

Hello, I'm looking for a function that counts the occurences of a given character within a string. f('|','ab|c|d') => 2 More precisely, I need to complete a vector of strings to ensure that all elements have the same count of a "separator": a|b|c a |a|b|c|d => a|b|c|| a|||| |a|b|c|d I guess that scan makes use of an internal function that would do

Hi all, Quick question, is it possible to take an existing /etc/passwd file and run it through mksmbpasswd.sh (or some other script) to update a smbpasswd file? I am asking this because everytime we change a password or add or delete usernames on a machine, it would seem we have to do the same thing to change th samba password file, and I'm hopeing there is an easier way..... thanks, jeff

Greetings. These days I find myself writing a lot of functions to handle routine things. One of these is a function to create a scatterplot of variables and draw a lowessed line so I can get some idea if there's any relationship between them. lowessed.plot <- function(x, y) { plot(x, y) lines(lowess(x, y)) } However, there's a slight problem: the plot axes come out labeled

Dear R helpers, I am having trouble with an array inside a loop. I wish to accumulate the results of a function in an array within the function, over several loops of a program outside the function. The problem is that the array seems to re-set at every entry to the function. Here is an example, so you can see what I mean.

I'd like to remove duplicated rows within a matrix, with missing data being treated as wildcards. For example > x <- matrix((1:3), 5, 3) > x[4,2] = NA > x[3,3] = NA > x [,1] [,2] [,3] [1,] 1 3 2 [2,] 2 1 3 [3,] 3 2 NA [4,] 1 NA 2 [5,] 2 1 3 I would like to obtain [,1] [,2] [,3] [1,] 1 3 2 [2,] 2 1 3

Hi, I was wondering if anybody can help me. In the small data set below I would like to select the index which doesn't contain the letter 'N' in the variable 'letters'. How can I discard these rows when the letter has a different position everytime (but the same letter for the whole column)? index<-c(1,2,3) letters<-c("CCTTGGAA", "NNTTGGAAT",

Hello, When I launch a script under windows it does not display sequentially my cat calls or maybe the console is not refreshed at every line of my script. For instance with that code cat("\n\n================== IMPORT DATA FROM FILE ===================\n\n") fileschosen <- choose.files(caption="Select gpr files", filters = matrix(c("genepix

I was wondering if someone could help me! Here is what I don't understand! Why the text in the function isn't showing up before the locator action? ########### plot(1:10) toto<-function(){ cat("Why this text isn't showing up before the point selection !!!!!!!!") point<-locator(2) return(point) } toto() P.S.: I am using the most recent version of R for mac Thanks

Hi all, I am a begginer in R and I have been trying to use the Conditioned Latin Hypercube to choose sample points only in areas close to roads due to the difficult thorough access in the study area. I could use a code to create the points throughout the area, but I need to create a code to make the R only comes up with points close to this road. I've been using the packages

Hello all, Sorry if this question has been answered in the past, but I could not find an answer. I am trying to print quotes within a cat output. The arguments are: file= "Data labels" directory= "/home/mylaptop/" The function returns: cat("The file", file, "is located in directory", directory, sep=" ") The output R prints is The file Data

Hi there Does anyone know, why this is not working?: par(mfrow = c(5, 5)) for (i in 1:10){ plot(x=time, y=Var.i) } (x-variable is time y-variable is Var out of matrix with columns Var.1 Var.2 Var.3 etc...) even for (i in 1:10){ plot(x=time, y=paste("Var", i, sep=".") } does not work Thanks marc

Dear Rusers, Trying to reduce my for loops addiction, could somebody tell me if there are ways to simplify (and perhaps accelerate ?) the following line for (i in 1:N) for (j in 1:N) m[i,j] = b[i]-b[j]; (where m is a NxN matrix and b a vector of length N) Thanks for any hint.