similar to: Cutting heatmap dendrogram

Hi, I have a gene expression experiment with 20 samples and 25000 genes each. I'd like to perform clustering on these. It turned out to become much faster when I transform the underlying matrix with t(matrix). Unfortunately then I'm not anymore able to use cutree to access individual clusters. In general I do something like this: hc <- hclust(dist(USArrests), "ave")

I generated a heatmap in R using the following commands: > mydata <- read.csv(file="Data.csv", header=TRUE, sep=",") > mydata <- mydata[rowSums(mydata[,-1]^2) >0, ] > rownames(mydata)=mydata$Name > mydata <- mydata[,2:253] > mydatamatrix <- data.matrix(mydata) > mydatascale <- t(scale(t(mydatamatrix))) > hr <-

I generated a heatmap in R using the following commands: > mydata <- read.csv(file="Data.csv", header=TRUE, sep=",") > mydata <- mydata[rowSums(mydata[,-1]^2) >0, ] > rownames(mydata)=mydata$Name > mydata <- mydata[,2:253] > mydatamatrix <- data.matrix(mydata) > mydatascale <- t(scale(t(mydatamatrix))) > hr <-

Hi When I give the command: > heatmap.2(as.matrix(d),Rowv=as.dendrogram(hc.gene),Colv=FALSE,scale="row ",trace="none",col=greenred.colors(79)) The resulting heatmap has re-ordered my columns! This is time-course data, and I don't want my columns re-ordered! Note from the help: Rowv: determines if and how the _row_ dendrogram should be reordered.

Hi Sorry to revisit an old problem, I seemed to solve this in 2004, only for it to resurface :-S I am trying to plot a heatmap, and I don't want the columns of my matrix re-ordered. The function doesn't seem to behave as the help would have you believe: a <- matrix(rnorm(100),nr=20) a.d <- dist(a) a.hc <- hclust(a.d) a.de <- as.dendrogram(a.hc) # columns are re-ordered

Hello all, I am using the heatmap.2 function in the gplots package. I want to supress the reordering of the columns of the data matrix i pass to the function. I used the statement, heatmap.2(z,Colv=FALSE,dendrogram="row",col=redgreen(75)) where z, is the matrix of data. The output i want should have the rows reordered along with the dendrogram and the columns should be in the original

Using the heatmap.2 function, I am trying to generate a heatmap of a 2 column x 500 row matrix of numeric values. I would like the 1st column of the matrix sorted from the highest to the lowest values - so that the colors reflected in the first column of the heatmap (top to bottom) go from red to green. After sorting the matrix (z), I tried the following command, but the data remains

Full_Name: Shane Neph Version: 2.2.1 OS: mac os x Submission from: (NULL) (71.113.43.247) While I found the names of the package authors and maintainer, I was unsuccessful in finding any contact information. The preliminary documentation for heatmap.2 is inconsistent in at least a couple of places when discussing the suppression of one or more dendrograms (and column/row ordering in general).

I have used heatmap to visualize my microarray data. I have a matrix of M-values. I do the following. #The distance between the columns. sampdist <- dist(t(matrix[,]), method="euclidean") sclus <- hclust(sampdist, method="average") #The distance between the rows. genedist <- dist(matrix[,], method="euclidean") gclus <- hclust(genedist,

Hi, I'm trying to build dendrograms to pass to heatmap(). The dendrograms I build plot properly, but when I pass them to heatmap() I get the error message "row dendrogram ordering gave index of wrong length" (see output log below). I looked in the code of heatmap() and saw that the error was due to a NULL return value from order.dendrogram(), which in turn got a NULL return value

Hello, I have come across some unexpected behaviour of the function heatmap in the stats package. This looks like a bug to me, but I might have misunderstood something. When calling the function in symmetric mode, the ColSideColors are plotted correctly, but RowSideColors appear in reverse order. This code (modified from the example on the help page) demonstrates the problem: cU <-

Thanks a lot, Michael! I cc to R-help, where this question really belongs {as the 'Subject' suggests itself...} -- please drop 'bioconductor' from CC'ing further replies. >>>>> "michael" == michael watson (IAH-C) <michael.watson at bbsrc.ac.uk> >>>>> on Thu, 17 Jun 2004 09:16:59 +0100 writes: michael> OK, admittedly it

Hi,   I need to generate a heatmap on a square matrix and wouldn't want to reorder the columns and the rows on the heatmap display.    I have used the options Rowv=NULL and Colv=NULL but doesn't seem to work. Following is a snippet of the heatmap function i am using. args <- commandArgs(); inputfile <- args[2] imgfile   <- args[3] bitmap(imgfile, height=15, width=15, res=100,

Hi, I have a question about the heatmap dendrogram in R. I loaded my data matrix in command heatmap(), and it gave me a heatmap accordingly, and the rows (genes) also were clustered accordingly. But now I don't want the genes clustered in that way, I have a new order of these genes, and want the rows of the heatmap are drawed as the order I give. Could anybody help me on that? Thank you!

I would like to organize my data as follows: I have a table that contains various data, and the numbers represent a level of similarity between these data, eg RF00013 has 100% similarity with the data RF00014. I would leave my table as a heatmap where darker colors represent higher similarity, and the lighter colors represent less level of similarity. I'm using version 2.11 of R. these

Dear all, I've been trying to find how to compare tow different heatmaps but I'm having trouble getting the colors bar to be the same. I'm doing something like the following: library(gplots) dat<-cor(matrix(rnorm(100, m=10), nrow=10)) mat<-cor(matrix(rnorm(100), nrow=10)) dev.new() heatmap.2(mat, Rowv=NA, Colv=NA, col=redgreen(75), symm=TRUE, trace="none",

I would like to use gridBase to place four separate heatmaps (actually, a stripped-down heatmap.2 from ght gregmisc package that contains only the "image" part) into four different viewports. I can get the placement correct, but I keep 'losing' the previous plot. Any suggestions? Here is some quick example code trying to put a heatmap into the left viewport and then

Hi all, By default, the heatmap function gives an image with a dendrogram added to the left side and to the top. Is it possible to only add the dendrogram to the left side and let the order of the columns unchanged ? I tried heatmap(mat, col=rbg,Rowv=res.hclust$order,Colv=1:dim(mat)[[2]]). In this case, the order of the columns are unchanged but a dendrogram is added to the top. How can I

Good afternoon, I ran heatmap and hclust on the same matrix x (strictly, I ran heatmap(x), and hclust(dist(t(x))), and realized that the two dendrograms were slightly different, in that the left-right arrangement of one pair of subclusters (columns) was reversed in the two functions (but all individual columns were grouped correctly). Looking through the code for heatmap as a most definite

I have a data set with 6 variables and 251 cases. The people who supplied me with this data set believe that it falls naturally into three groups, and have given me a rule for determining group number from these 6 variables. If I do scaled.stuff <- scale(stuff, TRUE, c(...the design ranges...)) stuff.dist <- dist(scaled.stuff) stuff.hc <- hclust(stuff.dist)