similar to: Request help writing a function

Hello R folks. 1) The question that generated the data, which I call Qx: Which of the following 5 items have you performed in the past month? (multipe response) 2) How the data is coded in my current dataframe: The first item that a person selected is coded under a field called Qxfirst; the second selected under Qxsecond, etc. For the first Person, the NAs mean that that person only selected

hello, i'm facing strange problem asterisk13.5 + chan_sip wss transport + SIPML5 1.5.230 person1 to person3 are behind different NATs audio devices double checked call from person1(chrome) to person2(chrome) works call from person1(chrome) to person 3(chrome) - no audio on both side (RTP flowing only in one direction) call from person2(chrome) to person 3(chrome) - no audio on both side

Hi all. I am currently thinking about how to do the following: I have the following models. Team Person Team has various positions (manager, programmer etc.) I would like each one of those positions to reference one or more Person records. A single Person record could be on 6 different teams at the same time in different roles. the same person could even be on the same team multiple times

Dear colleagues, there is a behaviour with S4 (virtual) classes that I find very hard to understand: Depending on the position of setAs(), the tree of inheritance changes. This is my baseline example that defines the classes "grandma", "mother", "daughter" and a virtual class "mr_x". For a new instance if "daughter", "mr_x" is betweeen

Dear community, I am having a class, let's say Person, Person <- R6Class("Person", public = list( idPerson = NULL, name = NULL, age = NULL, initialize = function(idPerson = NA, name = NA, age = NA) { self$idPerson <- idPerson

See below. On Wed, 15 Nov 2017, Cristina Pascual wrote: > Dear community, > > I am having a class, let's say Person, > > Person <- R6Class("Person", > public = list( > idPerson = NULL, > name = NULL, > age = NULL, > initialize =

Hey All, I need to forward an extension to an other depending on the current time but I could not get it done with GotoIfTime. What I'm trying to do is ring on the extension 1 if time is between 8:00AM and 2:00PM and on extension 2 if is between 2:01PM 11:00PM. exten => 111,1,GotoIfTime(8:00-14:00|*|*|1-12?333) exten => 111,2,Dial(${Person1}) exten => 111,3,Dial(Hangup) exten

Is there such a thing? I am thinking of an application that has something like this: 1. person has many things - there is a ''persons'' table 2. the things he has are stored in a table that is something like this person_id, thing_table_name, thing_id For example, it may map to person1, books, 23 #Person 1 owns book 23 person1, books, 25 #Person 1 owns book 25

Dear community, I want to use conformal prediction to measure how good are my svm-regression predictions (having used library e1071). I have gone through the conformal package documentation. But I'm pretty newer and need some more and detailed examples. Can anybody help me? Thanks in advance, [[alternative HTML version deleted]]

Hello List, I created a self-referential many-to-many relationship (as described in the book Rails recipe #18), where I have a model that has many-to-many relationships with itself. In this case, it''s person who can become friends. The join table looks like this: mysql> select * from friends_people; +-----------+-----------+-----------+ | person_id | friend_id | confirmed |

Hello R-Masters, I have a list 's' with three elements, as shown below. I want to recode a.a, a.a2, and a.a3 to NA if the value in a.a is less than 3. I reivewed my Modern Applied Statistic Book, the online help and did some searching of R-help on the internet. I explored unlist and as.list.data.frame in an attempt to isolate the third element of the list s, but this was not helpful.

Hello, I have spent considerable time trying to figure out that which I am about to describe. This included searching Help, consulting my various R books, and trail and (always) error. I have been assuming I would need to use a loop (looping over columns) but perhaps and apply function would do the trick. I have unsuccessfully tried both. A scaled down version of my situation is as follows:

Hello, I have problems with people having different groups who access a shared directory via samba. The requirements are: 1. There are people with group "group1" and group "group2" in /etc/passwd 2. 3 people from group "group1" and 2 people from group "group2" are allowed to access a shared directory and have read/write access to that directory. Our

This is a "long" way; i.e., not necessarily efficient: > qs2 [1] 2 1 1 4 4 4 1 1 1 4 2 4 3 1 4 3 3 2 4 3 > qs9 [1] 4 4 1 3 4 3 1 3 1 4 1 2 3 3 4 4 1 4 2 3 > decision <- function(a, b) { + if (a == 1 || b == 1) return(1) + if (a == 2 || b == 2) return(2) + if (a == 3 || b == 3) return(3) + if (a == 4 || b == 4) return(4) + NA + } > mapply(decision,

Hello R experts, The following problem outstrips my current programming knowledge. I have a dataframe with two fields that looks like the following: ID Contract 01 1 01 1 02 2 02 3 02 1 03 2 03 2 03 2 03 1 03 1 03 1 etc... I would like to end up with a dataframe with one row per ID where the value in the contract field would be the

Dear R Masters, I have searched high and low (the help archives and my various R reference material and help files) for a solution to what appears to me to be quite a simple problem. In the following syntax, variable n10 has three levels. I would like the symbols that appear in the graph for these three levels to be different colors. The best I have been able to do is to have the Key display

(Apologies the previous version was sent as rich text) Hello, I'm new to R, but I've read the intro to R and successfully connected it to an instance of mysql. I'm trying to perform multiple linear regression, but I'm having trouble using the lm function. To start, I have read in a simply y matrix of values(dependent variable) and x matrix of independent variables. It says both

Hello, In the Hmisc package, functions describe and summarize can explicitly take a weight variable. My question is can a weight variable be applied when using 'summary'? For example, using...summary(var1 ~ var2) I would like to weight the data by var 3 (same length). Is this possible? Thanks a lot. Greg Blevins The Market Solutions Group, Inc.

Hello, I have a data frame that has three fields. Resp# ActCode ProdUsed 100 3 2 100 3 2 100 4 3 100 4 3 101 3 6 102 2 1 102 3 1 103 5 1 103 5 1 103

Hello, R 2.3.0 Windows XP I have spent quite a bit of time trying to resolve my problem below, which included a R site search. The "vertical bars" syntax below produces a vertical bar chart with the values displayed above each bar. I want to cast this graphic horizontally, but I have not been able to arrive at a suitable outcome. The best I have been able to do, using the second block