similar to: Error on installation of R-1.8 and R-1.9

Dear R users, I'm trying to automatically generate a *.tex file with the output of an OLS estimation. Some people suggested to use the latex function on the Hmisc package. I'm having a bit of trouble to properly specify this function (I'm not a very experienced R user). Below you will find an example, of what I'm doing. ## Annette Dobson (1990) "An Introduction to Generalized

Hello, Does anyone knows if there is any plugin for Sweave to run on WinEdt, or any other windows Latex editor? Many thanks, JP

Dear R users, I'm starting to get acquainted with R. I've been reading the manual, and I understood that if I wanted to install a user written package on R, I could do it directly from the Internet, by typing the line install.packages("quantreg") in an R session. To my surprise this command did not work, nor did the command "update packages from CRAN..." from the menu

Hello, I am having some problems to use the 'merge' function. I'm not sure if I got its working right. What I want to do is: 1) Suppose I have a dataframe like: height width 1 1.1 2.3 2 2.1 2.5 3 1.8 1.9 4 1.6 2.1 5 1.8 2.4 2) And I generate a second

Hi there, No information was found which version of XFree86 get along with R. I could not compile R version 1.8.1 with XFree86 4.3.99.902. Here is error message. gcc -I. -I../../../src/include -I../../../src/include -DI18N_MB -I/usr/X11R6/include -I/usr/local/include -DHAVE_CONFIG_H -D__NO_MATH_INLINES -mieee-fp -fPIC -O2 -pipe -march=i386 -mcpu=i686 -c dataentry_mb.c -o dataentry_mb.lo In

I am trying to fit a normal linear model with response y and predictor x and two factors sex and group. I would like each combination of sex and group to have individual slopes and then subsequently have parallel slopes. I tried the model y ~ x*sex*group and it seemed to work for the first case.. Is this how it is supposed to be done? For the second the model y ~ sex + group seems to work. In

Is the following developed in my console output a recognized bug or am I using the cat function incorrectly? Thanks, Stan > ifelse(class(data[[n]])!="factor",{print("yes")},{print("no")}) [1] "yes" [1] "yes" > ifelse(class(data[[n]])!="factor",{cat("yes")},{cat("no")}) yesError in ans[test & !nas] <-

Greetings! I'm using the extract command (raster package) with a raster layer (x) and a spatial polygons dataframe (y). I'm using it to extract the sum of raster values by each spatial polygon. However, I'm getting NAs as a result for some polygon IDs, which I know isn't true because that doesn't happen in ArcGIS. Does anyone experienced the same issue? Thanks! Joao

Anyone who can help me with this? I have 48 observations (I dont want to alter their order). I want to group these observations into 16 blocks. So I should have 3 observations for each block. This is what I did in R, but it has warnings. > y #contains my 48 observations [1] 2.4 2.4 2.4 2.2 2.1 1.5 2.3 2.3 2.5 2.0 1.9 1.7 2.2 1.8 3.2 3.2 2.7 2.2 2.2 [20] 1.9 1.9 1.8 2.7 3.0

Hello, I have some data that will be in the form: structure(list(station = structure(c(20L, 2L, 4L, 19L, 3L, 11L, 1L, 5L, 10L, 12L, 17L, 18L, 6L, 9L, 13L, 16L, 7L, 8L, 15L, 14L ), .Label = c("1", "10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "2", "3",

Passenger configuration selects which ruby executable to use via a global configuration variable (at least for Apache, I assume it''s the same for Nginx). I''m in a situation where I''ve got at least one rails app I''d like to run on 1.9 while others remain on 1.8. This is for my development machine running OS X 10.6. Normally I just use the Passenger PrefPane,

Dear R users, I've written a loop to generate Moran's test (spdep package) on serval subsamples of a large dataset. See below a short example. My loop is working fine, however I would like to be able to store the test results as lines of a matrix, that I would latter be able to export as a dataset. My problem is that I'm not sure how I could do this using R. Any help will be much

Hi, i''m going to port my wxruby application from ruby 1.8 to 1.9.x. Everything went smoothly and i''ve got many advantage over the port. With ruby 1.9.x my app run blazingly fast on startup either on MacOSX and Linux while on Windows (xp, vista, win7) it takes longer (~20 sec. more). The problem is on "require ''wx''" instruction (you can test on an

Dear R Users, Could you please help me on the following issue? I have a real large yearly data set. For each year I have 365 flow values. Some of the flow values are not known and that’s why you will see NA written in those slots. I wanted to know, is there a way that I can estimate those values? I tried approx command but it seems least helpful for the kind of issue I am up against.

Dear R Experts, I am trying to produce a legend for a series of plots which are generated in a loop. The legend is supposed to look like this: 2000: gamma=1.8 where gamma is replaced by the greek letter and both the year and the value of gamma are stored in variables. Everything works fine as long as I have only one data series: year = 2001 g = 1.9 plot(1) legend('top',

Hi Everyone, I am doing a project based on "Spatially Lagged Predictor Variable Models", I would like to know which package in R would execute this model. Also, I am new to this field of spatial statistics. Any suggestions for a good book on spatial regression analysis would be appreciated. Thanks Again. Cheers Arun -- View this message in context:

Hi, I'm having trouble with the "which" or the "seq" function, I'm not sure. Here's an example : > lat=seq(1,2,by=0.1) > lat [1] 1.0 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2.0 > which(lat==1) [1] 1 > which(lat==1.1) [1] 2 > which(lat==1.2) [1] 3 > which(lat==1.3) [1] 4 > which(lat==1.4) [1] 5 > which(lat==1.5) [1] 6 >

Hi all I've been getting some emails from the R package maintainers that I need to update some code in a CRAN packge that uses FORTRAN, to comply with (not so recent) changes. I've been a little busy... I'm having trouble adjusting my code. I hope someone can help. The package was working fine, and a few R functions in my package had lines like this: tmp <- .Fortran(

Dear forumites As a newbie I try to figure out whether R can do a certain job quicker than other programs and it seems so, but I don't find a solution to a seemingly simple problem: I have built a matrix of distance with as.matrix(dist()) with several hundred rows and columns 1 2 3 4 1 0 1.3 1.6 2.1 2 1.3 0

Dear arun and all R users, I will first of all try to simply define my issue.. I have data in the following format Year Discharge dd/mm/yyyy x .. … … … There are some NA values in the discharge which I would like to predict by using “predict command”. I cant figure out the way to write the coding for that. Could you please help me on that??? I have also ,written