Displaying 20 results from an estimated 6000 matches similar to: "Persp plotting of kernel density estimate."
2004 Mar 17
1
(no subject)
Dear All,
I am trying to visualize the surface of a bivariate kernel density
estimate.
I have a vector of bivariate observations(x,y), and a function which
computes the kernel density estimate z corresponding to each
observation. I cannot generate the (x,y) data in the ascending order
needed by persp(x,y,z).
I was wondering whether there is an R version of the S function interp.
Would anybody
2006 Jun 28
1
persp/ scatterplot3d
Dear WizaRds,
I would like to create a 3d-plot with persp(). I sampled 17 points
with xyz-coordinates (real-life example!), representing the peaks of the
whole plane with "zero coordinates" x=3,y=3,z=3. My intention is to show
which entries are above or below the "zero" level with persp() on a
nicely created grid. I also tried scatterplot3d(), but, alas, I am
unable
2005 Mar 07
1
plot gam object
Dear R help,
I am fitting a gam model with package GAM ( I use lo() to fit 2 non-parametric
additive components).
When I plot the GAM object, along with the graphics window displaying plots of
each components, I read the following warnings at the prompt:
3: the condition has length 1 and only the first element will be used in: if
(scale2 < scale) rep(mean(ylim), 2) + ((ylim - mean(ylim))
2003 Jan 14
4
density plot - beginner's question
Hi,
I am trying to plot densities given on a two dimensional grid. My
data is in the an external file, and is arranged in three columns:
x, y, density
how may i get a plot of this? i would like to get (1) a three
dimensional plot and (2) a color coded two dimensional plot.
I have tried using
image(x, y, density)
but i am asked to put the data in ascending order. i am not sure
how i may
2009 Nov 09
1
persp function question
Hello,
I have a question about persp function:
I made my classical matrix with x, y and z variables and I dont know why I obtain a 3D image with overestimate heights.
Here is my script:
microtopo = read.csv2("topo2.csv", dec=".")
attach(microtopo)
require(akima) # for persp or
zz <-interp (x, y, z)
persp(zz)
See also my attach file
Thanks,
Best regards
JS
2012 Feb 29
2
Contour plot
Hi, I would like to make a contour plot with the data below, x-axis= Day
(increasing order, day number is out of 365 days of a year), y-axis= Depth
(varies), and z=pH. I tried to use filled.contour function, but not sure the
proper way to ordinate my z results into a matrix with different x and y
length. After that, if I attempted to plot the data, the x and y values are
not in ascending
2006 Feb 13
2
transforming data frame for use with persp
Hi,
This is probably documented, but I cannot find the right words or
expression for a search. My attempts failed.
I have a data frame of 3 vectors (x, y and z) and would like to
transform this so that I could use persp. Presently I have y-level
copies of each x level, and a z value for each x-y pair. I need 2
columns giving the possible levels of x and y, and then a
transformation of
2003 Sep 20
4
persp graphs
Hi,
I am doing my way on R, with much experimenting. So, I am trying to plot a 3d
graphic ussing "persp" and entering a data set (attached) of UTM coordinates
as x,y and a pH values as z. However when I try an error message comes out
telling that increasing x and y values are expected. Jus ordering the first
vector does not help, and, of course, order the first two independently
2007 Apr 11
2
persp Error. x,y,z with the same length
Hello,
I have a problem in drawing a 3d graphic. I simplified the program to show you the problem.
I have a text file with hundreds of entries in 3 columns. I scaned these columns with matrix(scan). Then, I transformed some datas. Now I have the datas in h,x,y.
I created a new matrix to use persp . But I got an error. The reason is probably the same length of x,y,z.
But what can I do the draw
2003 May 30
1
bootstrapping data.frame and matrix
Dear All,
When bootstrapping a statistics based on more than one vector, from a
data.frame or a matrix object, it looks like I am not able to pass the
data to R. What am I doing wrong?
I use the library "bootstrap".
Here is an example with a data.frame called "data"
"boot2_bootstrap(data, theta, nboot)
I get the following error message:
Error in inherits(x,
2011 Aug 04
3
persp()
Hello
I am trying to draw a basic black and white map of two European countries.
After searching some key words in google and reading many pages I arrived to the conclusion that persp() could be used to draw that map.
I have prepared three small example files, which are supposed to be the files required for running that function.
xvector is a vector with the longitudes
yvector is a vector with
2004 Mar 29
2
Problems with "optimize"
Dear All,
I'm trying to maximize a likelihood with respect one parameter using
"optimize" on simulated data (without error component).
I've iterated the maximization procedure 1000 times and I should always
obtain the same estimate of the parameter (equal to the simulated one) but,
instead, i obtain different results (the likelihood function shouldn't be
flat). Does
2010 Jan 01
2
How to calculate density function of Bivariate binomial distribution
Am trying to do some study on bivariate binomial distribution. Anyone knows
if there is package in R that I can use to calculate the density function of
bivariate binomial distribution and to generate random samples of it.
Thanks,
--
View this message in context: http://n4.nabble.com/How-to-calculate-density-function-of-Bivariate-binomial-distribution-tp992002p992002.html
Sent from the R help
1999 Nov 16
1
spikes in contour and persp (PR#327)
The following matrix of normed likelihoods should give a smooth
surface but instead gives a series of spikes in both persp and contour
(the dim labels are the axes values). I know an algorithm cannot be
infallible but it would be nice to have some parameters to control the
smoothing. (It takes close to an hour to produce this matrix on a
Pentium II 300mh. It was after that that it crashed with the
2008 Jan 24
1
surface plot
Hi, there is following issue, which I encounter when doing data analysis. Say
we have data in form of the matrix x:
> x
[,1] [,2] [,3]
[1,] 0.1 4 10
[2,] 0.2 5 11
[3,] 0.1 5 12
[4,] 0.1 6 13
[5,] 0.2 4 14
[6,] 0.3 5 16
now I want to do surface plot of x[,3] with respect to axes OX:x[,1] and OY:
x[,2] in ascending orders of course.
Thanks in advance,
2012 Apr 30
3
R2 in multilevel modelling
Goodmorning everybody,
i'm an italian statistician and i'm using R for research.
Could someone tell me some indices to see the goodness of fit in multilevel
modelling?
I'm using the lmer function, and I want to know if my model fit well my
data.
I actually want to justify the use of multilevel model instead the classical
one.
Hope someone can help me.
Thank you.
Greetings
2004 Dec 08
2
Surface graph.
What package/code could I use to create a 3-d surface graph of the predicted
values over two of the explanatory variables' coefficients?
Jim
James Bang
Department of Economics
University of Illinois
Well I AM missing the back of my head.you COULD cut me a little slack!
-Homer Simpson
2003 Jul 12
2
help with bivariate density plot question
Dear R users:
I have a dataset with two variables (>20000 observations, two samples from same subject) and I used "kernSur" from library(Genkern) to
get a estimated bivariate density and corresponding plots as follows:
new.data.normal<-data.normal[!is.na(data.normal[,2]),]
x<-new.data.normal[,2]
y<-new.data.normal[,3]
op <- KernSur(x,y, xgridsize=50, ygridsize=50,
2023 Jan 26
1
akima interp results to zero with less than 10 values
The akima package has a problematic license (it doesn't allow commercial
use), so it's been recommended that people use the interp package
instead. When I use interp::interp instead of akima::interp, I get
reasonable output from your example.
So that's another reason to drop akima...
Duncan Murdoch
On 26/01/2023 9:35 a.m., PIKAL Petr wrote:
> Dear all
>
> I have this
2023 Jan 26
1
akima interp results to zero with less than 10 values
Dear all
I have this table
> dput(mat)
mat <- structure(c(2, 16, 9, 2, 16, 1, 1, 4, 7, 7, 44.52, 42.8, 43.54,
40.26, 40.09), dim = c(5L, 3L))
And I want to calculate result for contour or image plots as I did few years
ago.
However interp does not compute the z values and gives me zeros in z matrix.
library(akima)
> interp(mat[,1], mat[,2], mat[, 3], nx=5, ny=5)
$x
[1] 2.0 5.5