similar to: how to keep functions while remove all other commands

Dear all can anybady tell me how to seperate R's input and output screen?I mean just like SAS or some others, the commands does not mixed with results. thank you

How can I best achieve the following (works in Splus): filenames <- dos("dir *.sasb7dat /b") What I am asking, more generically, is: how can I capture the output of a DOS command in R? I have tried using system("COMMAND.COM /c dir /b", intern=T, show.output.on.console=T) where intern: a logical, indicates whether to make the output of the command an R

Hi, I just encountered a problem in R that may easily be fixed: If one uses attach for a data.frame e.g. 10000 times and forgets detach, then R gets incredibly slow (less then 10% of the original speed). My system: platform powerpc-apple-darwin6.0 arch powerpc os darwin6.0 system powerpc, darwin6.0 status major 1 minor 6.1 year 2002

(If this only happens in Win 98, I'm sure I could live with it. Just may be helpful to report it, I hope.) Start up R GUI, then > plot(1:4,1:4) # then close manually by clicking X > plot(1:4,1:4) # ditto > methods(plot) sometimes produces normal output and even the following prompt, but then crashes immediately, or more often, crashes immediately with no output. I can do any

bug.report() tells me to email to r-bugs@r-project.org, whereas the Web site http://www.r-project.org/ points me to r-bugs@biostat.ku.dk. Which should I believe? Simon Fear Senior Statistician Syne qua non Ltd Tel: +44 (0) 1379 644449 Fax: +44 (0) 1379 644445 email: Simon.Fear@synequanon.com web: http://www.synequanon.com Number of attachments included with this message: 0 This

Dear all, I have found the following (for me) incomprehensible behaviour of ISOdate (POSIXct): > ISOdate(1900,6,16) [1] "1900-06-15 14:00:00 Westeurop?ische Sommerzeit" > ISOdate(1950,6,16) [1] "1950-06-16 14:00:00 Westeurop?ische Sommerzeit" Note that in the first case I get the 15th of June back, not the 16th as I would have expected! This happened under R-1.7.1 on

I've searched on CRAN for axes, axis, and other terms I've already forgotten, without (re)discovering the reason for S using "non-joining" axes by default, instead of box("l"). MASS points me towards Cleveland (1993) but I don't have ready access to this any more. Could someone give me a one-liner to justify this choice to a sceptic? It's something to do

Hello Anyone that now of any function in R that can calculate copulas? Or if anyone have any code avaible I would be more than interested. Thank you in advance /Thomas ______________________________________________ R-help at stat.math.ethz.ch mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help

Greetings everyone, I am new at R. My questions is rather basic. Looking R manuals looks like there should be a way to read MS excel files into R. Could somebody tell me which library should I use for that? Thanks in advance Victor H. Marín Laboratorio de Modelación Ecológica Depto. de Ciencias Ecológicas, Fac. de Ciencias, Universidad de Chile Casilla 653 Santiago, Chile

R version 1.8.1, OS Windows 98 Dear colleagues, if I import vegetation data (first row with column labels and first column with row labels) like 7MYRGERM;7AGRGIGA;7DRYOCTO;5MYRGERM;7SALELEA;7CHOCHON;7SALNIG?;....... t401;5;2;2;3;4;2;2;2;1;2;1;2;2;1;2;2;2;1;2;1;0;0;...... t403;3;0;0;6;4;0;3;0;0;3;0;0;0;0;3;0;0;0;2;0;2;0;..... with read.table("data.file", header=TRUE,

Dear R users, I want to share my joy with you. Please see the following excellent introduction to R "Statistiques avec R " by Vincent Zoonekynd http://zoonek2.free.fr/UNIX/48_R/all.html In paticular, you can see a lot of fascinating graphics examples of R from which you can get many hints. Soryy if this is already well-known, but the CRAN search did not show nothing with the keyword

Hi all, I hope this isn't a naive newbie question again. Here you can see column 264 of a data frame containing data of the same interview in May and September. Column 264 contains the answers of 49 persons to a question in May. > fbhint.spss1[,264] [1] teils/teils sehr wichtig <NA> <NA> sehr wichtig [6] sehr wichtig sehr wichtig sehr wichtig <NA>

Dear R users, I want to retrieve "..." argument values within a function. Here is a small exmaple: myfunc <- function(x, ...) { if (hasArg(ylim)) a <- ylim plot(x, ...) } x <- rnorm(100) myfunc(x, ylim=c(-0.5, 0.5)) Error in myfunc(x, ylim = c(-0.5, 0.5)) : Object "ylim" not found > I need to retrieve values of "ylim" (if it is defined

For reasons which I'll spare you, I'm writing a program to analyse R source code. This has led me to probe some of the darker corners of R syntax to find out what is supposed to happen. Now, from reading the R documentation (and the New S book &c) I know perfectly well that f(a, b, etc) <- x is supposed to turn into a <- "f<-"(a, b, etc, value=x) Except,

The following code works, to gsub single quotes to double quotes: line <- gsub("'", '"', line) (that's a single quote within doubles then a double within singles if your viewer's font is not good). But The R Language Manual tells me that Quotes and other special characters within strings are specified using escape sequences: \' single quote \"

# Your mailer is set to "none" (default on Windows), # hence we cannot send the bug report directly from R. # Please copy the bug report (after finishing it) to # your favorite email program and send it to # # r-bugs@r-project.org # ###################################################### scan() (and so also of course read.table, read.csv etc) crashes right out of R (GUI) if it

I tried to define a function like: fnx <- function(x, by.vars=Month) print(by(x, by.vars, summary)) But this doesn't work (does not find x$Month; unlike other functions, such as subset(), the INDICES argument to "by" does not look for variables in dataset x. Is fully documented, but I forget every time). So I tried using "with": fnxx <- function(x, by.vars=Month)

Try the following function (the name is supposed to be a joke, by the way), which will also do the right thing with NAs and characters. Use it as if(equal.enough(x,y)) rather than if(x==y), e.g. > equal.enough(0.1+0.2, 0.3) [1] TRUE My default of 15 significant figures may be overkill in many applications; be prepared to reduce this. Simon Fear "equal.enough" <- function(x, y,

Why does > curve(function(y) y^2, from=0,to=1) not work, whereas > myf <- function(y) y^2 > curve(myf, from=0,to=1) work? For the former, I get the error message Error in curve(function(y) y^2, from = 0, to = 1) : 'expr' must be a function or an expression containing 'x' I'm using R1.7.0 under Windows XP. Damon Wischik.

Hi R-people I have a question concerning subsetting. I have a dataframe which contains among other variables the variable "subject". For each subject number there are several rows, e.g.: subject treatment concentration day 19 a 15,4 1 19 a 18,3 2 19 a 2,3 3 etc. Im trying to subset the dataframe to get for