similar to: error "evaluation nested too deeply" {was "Heatmap"}

I have used heatmap to visualize my microarray data. I have a matrix of M-values. I do the following. #The distance between the columns. sampdist <- dist(t(matrix[,]), method="euclidean") sclus <- hclust(sampdist, method="average") #The distance between the rows. genedist <- dist(matrix[,], method="euclidean") gclus <- hclust(genedist,

Ladies and Gentlemen, As Johan Lindberg points out, the documentation for handling dendrograms is sparse....Does anyone know who is responsible for or working on development of tree methods and objects? I've written a couple of scripts for my own use to translate between parenthetical (A(B(CD))) or binary A00 B10 C11 D11 tree formats and cluster objects in R, but as an inexperienced

Hi all, By default, the heatmap function gives an image with a dendrogram added to the left side and to the top. Is it possible to only add the dendrogram to the left side and let the order of the columns unchanged ? I tried heatmap(mat, col=rbg,Rowv=res.hclust$order,Colv=1:dim(mat)[[2]]). In this case, the order of the columns are unchanged but a dendrogram is added to the top. How can I

Hi, Trying to plot a large dendrogram, I get the recursion limit error Error in match.fun(FUN) : evaluation nested too deeply: infinite recursion / options(expression=)? but setting options(expressions = 10000) or something large enough to solve the infinite recursion limit problem, I get Error: protect(): stack overflow Is there anything that can be done? Thanks Claudio Donati

Hi, I get following error when trying to plot a heatmap on a very large matrix (808 x5000). heatmap(ctab) Error: evaluation nested too deeply: infinite recursion / options(expressions=)? Call to heatmap function is not contained within any other function or so. Upon searching the R mailing list, I found that someone had the same problem and the suggested solution was to set an option using

Hi netters, I have a matrix X of the size (1000,100). The values are from -3 to +3. When I tried heatmap(X, distfun=function(c),dist(c,method="bin"),hclustfun=function(m),hclust(m,method="average")) I got the error message: Error: evaluation nested too deeply: infinite recursion / options(expressions=)? However, if I used default parameters for distfunction:

Thanks a lot, Michael! I cc to R-help, where this question really belongs {as the 'Subject' suggests itself...} -- please drop 'bioconductor' from CC'ing further replies. >>>>> "michael" == michael watson (IAH-C) <michael.watson at bbsrc.ac.uk> >>>>> on Thu, 17 Jun 2004 09:16:59 +0100 writes: michael> OK, admittedly it

Hi, I am trying to create a heatmap with some specific requirements. Specifically, I need to be able to center the color-scale around 0, and I need to truncate the data so that a few extreme values do not cause the rest of the heatmap to appear black (on a red/green scale). After reading through and experimenting with heatmap, heatmap.2, heatmap_plus, and heatmap_2, I believe heatmap.2 will

Dear list, I am trying to plot a radial dendrogram using the ape package, which requires my data to be of class 'phylo'. Currently I have my dendrogram stored as an object of class 'dendrogram' which was produced from an outside bit of C code, but was made into an object of class 'igraph.eigenc' and converted to a dendrogram using 'as.dendrogram()' from the igraph

I am having trouble displaying a dendrogram of evolutionary relationships (a phylogram imported from the ape package) as the vertical component of a heatmap, but keeping the hierarchical clustering of the horizontal component. The relationships of the vertical component in the generated heatmap are not that of the dendrogram, although the ordering is. In more detail, I am attempting to generate

Dear all, I generated a heatmap with the heatmap() function with the default "complete" linkage method, but when I add the argument Rowv=as.dendrogram(hclust(dist(matrix), method="complete")), The dendrogram generated is different from the dendrogram produced by heatmap() with default settings. Could someone kindly point out where my mistakes are? P.S. When I did

Dear R users, I'm trying to create images of 2 symmetrical matrices using heatmap.2 of the 'gplots' library. Both matrices have the same row and column names For the first matrix I'm using the default clustering and column denrogram options: heatmap.2(Matrix1, symm=T, breaks=20, col=rich.colors(19), main="matrix1", density.info="histogram",

Hi I am having some problems getting my heatmap to be the right size! Let me explain. I am experienced at getting an hclust or a dendrogram object to be the right size. For example, I have a dataset which has 4000 rows, which I clustered using hclust and I wanted to plot it as a horizontal dendrogram. So I used jpeg(), set the image height to be 4000 and plotted the dendrogram and got the

Hi Kevin, >>>>> "krc" == krc <krc at odin.mdacc.tmc.edu> >>>>> on Mon, 27 Jun 2005 21:55:37 +0200 (CEST) writes: krc> Full_Name: Kevin R. Coombes krc> Version: 2.1.0 krc> OS: Windows XP krc> Submission from: (NULL) (143.111.224.169) krc> When revC = TRUE and RowSideColors is set to a list of krc>

Full_Name: Kevin R. Coombes Version: 2.1.0 OS: Windows XP Submission from: (NULL) (143.111.224.169) When revC = TRUE and RowSideColors is set to a list of colors in heatmap, then the image and dendrogram are inverted, but the row-side color map does not change. The following script illustrates the problem. ############## set.seed(1023) # generate columns of two different types d1 <-

Hi, I am a beginner for R. I had use gplots to generate a heatmap as following: >heatmap.2(matrix, col=topo.colors(75), dendrogram="column", Rowv=FALSE, trace="none", key=TRUE, keysize=0.8, density.info="none", cexRow=0.2, cexCol=0.6) It work well. It generate heatmap whith rcolumn clustering dendrogram and I can export a very nice graph. But I don not know how

Hello, I would like to display a heatmap with dendrograms and allow the user to click on either dendrogram to choose a sub-dendrogram. The function heatmap() uses layout() and image() and the plot method of dendrogram to plot the heatmap and dendrograms, but if locator() is then called and the user clicks, the coordinates returned from locator() are with respect to the last thing plotted (e.g.,

Full_Name: Shane Neph Version: 2.2.1 OS: mac os x Submission from: (NULL) (71.113.43.247) While I found the names of the package authors and maintainer, I was unsuccessful in finding any contact information. The preliminary documentation for heatmap.2 is inconsistent in at least a couple of places when discussing the suppression of one or more dendrograms (and column/row ordering in general).

Hi , I am trying to plot a heatmap with a correlation matrix and trying to highlight significant correlations . i am using my matrix d874n has 78 columns ex2<-corAndPvalue(data.matrix(d874n),use = "pairwise.complete.obs") ##creating a matrix of true false using p values sig<-ex2$p<0.05 nx=78 ny=78 makeRects <- function(tfMat,border){ cAbove =

Hi Sorry to revisit an old problem, I seemed to solve this in 2004, only for it to resurface :-S I am trying to plot a heatmap, and I don't want the columns of my matrix re-ordered. The function doesn't seem to behave as the help would have you believe: a <- matrix(rnorm(100),nr=20) a.d <- dist(a) a.hc <- hclust(a.d) a.de <- as.dendrogram(a.hc) # columns are re-ordered