similar to: AW: ISOdate() and strptime()

Dear R-people! I am using R 1.8.0, under Windows XP. While using ISOdate() and strptime(), I noticed the following behaviour when "wrong" arguments (e.g., months>12) are given to these functions: > ISOdate(year=2003,month=2,day=20) #ok [1] "2003-02-20 13:00:00 Westeurop?ische Normalzeit" > ISOdate(year=2003,month=2,day=30) #wrong day, but returns a value [1]

Dear all, I have found the following (for me) incomprehensible behaviour of ISOdate (POSIXct): > ISOdate(1900,6,16) [1] "1900-06-15 14:00:00 Westeurop?ische Sommerzeit" > ISOdate(1950,6,16) [1] "1950-06-16 14:00:00 Westeurop?ische Sommerzeit" Note that in the first case I get the 15th of June back, not the 16th as I would have expected! This happened under R-1.7.1 on

Hello! I've been trying to get this right for quite a while now and fear there is an easy solution I just don't see. I did not have this problem in Linux, and I searched r-help and Google but did not find a solution, but of course I am grateful for and resources I might not have found our not understood yet. I try to parse a time stamp with time zone. I essentially just want to parse the

Dear all, according to the Help-page of DateTimeClasses {base} I should be able to do time - z with time date-time objects z a numeric vector (in seconds) or an object of class "difftime". However, on R version 2.6.0 (Windows XP) I get > Sys.time() - as.difftime(c("0:3:20", "11:23:15")) Time differences in mins [1] 1191837998 1191837318

Dear Brian and other R-developers, I have to say that I don't understand why what I wrote should have caused any offence. A smile was what I was hoping for. You know I devote more time than I am supposed to, to support R and its users, in partial repayment of my immeasurable debt to all the Developers. It's not much, it's sometimes misguided (I later discover), and my resources

Dear list: working with date/times I have come across a problem that ISOdate and ISOdatetime are too slow on large vectors of data. I was surprised just until I looked at the implementation and the man page: "ISOdatetime and ISOdate are convenience wrappers for strptime". In other terms, they convert data to character representation first in order to create a POSIXlt object that is then

Dear all, in the package its the print() method does not seem to correctly work in all circumstances: > selectMethod(print, "its") Method Definition: function (x, ...) { print(x@.Data <mailto:x@.Data> , ...) } <environment: namespace:its> Signatures: x target "its" defined "its" > fundPME.lst[[1]]$irr An object of

Dear R-people! I am using R 1.8.0, under Windows XP. What I want to do is a date conversion of a character column of a data frame and assign the result as a new column. Simple example: > x <- data.frame(a=c("yesterday","today","tomorrow"), b=I(c("20031111", "20031112", "20031113"))) # convert x$b from character to date: >

Dear R-users! I am using R 1.7.0, under Windows XP. Having some hospital discharge data (admission date and discharge date for each patient), I want to get the number of patients in the hospital on a given date. My data look like (simple example): > x <- data.frame(patid=c("pat1", "pat2"), adm.date = c("15.03.2002", "16.03.2002"),

Hi all; I've already send a similar e-mail to the list and Prof. Brian Ripley answered me but my doubts remain unresolved. Thanks for the clarification, but perhaps I wasn't clear enough in posting my questions. I've got a postgres database which I read into R. The first column is Timestamp with timezone, and my data are already in UTC format. An 'printed' extract of R

Hi all, I'm having difficulty converting a 'dates' object to a POSIXct object: testDATES<-c(35947,35971,36004,36008,36053,36066) testDATES<-chron(dates=testDATES, format = c(dates = "m/d/y"), origin=c(month = 12, day = 30, year = 1899)) >[1] 06/01/98 06/25/98 07/28/98 08/01/98 09/15/98 09/28/98 > as.POSIXct(testDATES) [1] NA NA NA NA NA NA

Hi, The solution to my problem is to use lattice:::calculateAxisComponents to calculate appropriate labels for the time axis in trellis plots. # For example, given x <- seq.POSIXt(strptime("2003/01/01", format = "%Y/%m/%d"), strptime("2003/10/01", format = "%Y/%m/%d"), by = "month") y <- rnorm(length(x)) dat <-

Works for me: > strptime("17_35_14.01234.mp3","%H_%M_%OS")$sec [1] 14.01234 > strptime("17_35_14.mp3","%H_%M_%OS")$sec [1] 14 Just leave off the ".mp3" in your time pattern. Relevant section from the help ("Details") for strptime: strptime converts character vectors to class "POSIXlt": its input x is first converted by

I'm trying to proess date/time fields from files that were given to me to analyze. Any clues what I'm doing wrong with strptime? This seems to fail the same way under Linux or Windows. For ?strptime would it make sense to explain %OS3 somewhere besides the Examples? > # Why does %OS3 work here? > format(Sys.time(), "%H:%M:%S") [1] "16:45:19" >

Dear ALL, Thank you so much for your contributions. I have made some progress. Below is a simple script I gleaned from your kind responses: Sys.setenv(TZ="Etc/GMT") dates <- c("02/27/92", "02/27/92", "01/14/92", "02/28/92", "02/01/92") times <- c("23:0:0", "22:0:0", "01:00:00", "18:0:0",

Hi All In trying to correlate some tide gauge data I need to deal with varying timezones. From the documentation on strptime, it seemed that the tz variable might have some effect on the conversion, but I'm not seeing an effect. > strptime("20061201 1:02 PST",format="%Y%m%d %H:%M",tz="PST")+0 [1] "2006-12-01 01:02:00 EST" >

Dear All, Many thanks for bailing me out. Ogbos On Apr 18, 2016 9:07 PM, "David Winsemius" <dwinsemius at comcast.net> wrote: > > > On Apr 18, 2016, at 10:44 AM, Ogbos Okike <giftedlife2014 at gmail.com> > wrote: > > > > Dear ALL, > > Thank you so much for your contributions. > > I have made some progress. Below is a simple script I

Hi This code should explain what I'm trying to do > strptime("30-Jan-08", "%d-%b-%y") [1] "2008-01-30" > > format(strptime("30-Jan-08", "%d-%b-%y") , "%b-%y") [1] "Jan-08" > > strptime(format(strptime("30-Jan-08", "%d-%b-%y") , "%b-%y") , "%b-%y") [1] NA I have a

Hi, I am having a trouble parsing dates using strptime() that I get in the format of year and week number. The data looks like this "201127" which means year 2011 and week 27. I would like to graph this using ggplot but then I get a gap between 201054 and 201101 so I thought I would just easily convert it. I tried to use strptime and as.Date and the format string of %Y%W but it seems

> On 12 Mar 2016, at 00:05 , Mick Jordan <mick.jordan at oracle.com> wrote: > > This is definitely obscure but we had a unit test that called .Internal(strptime, "1942/01/01", %Y/%m/%d") with timezone (TZ) set to CET. Umm, that doesn't even parse. And fixing the typo, it doesn't run: > .Internal(strptime, "1942/01/01", %Y/%m/%d") Error: