similar to: R memory allocation error - Unix

I'm trying to figure out how to allow an extension to register more than once. For instance, I have all of these 4 line IP phones that I use with Asterisk and I would like to have a persons extension (say 101) ring at all four lines so that if the person is on the phone they can take another call, but it appears as though if you try to register the same extension more than once then the most

I am writing code in C and would like to call R's functions samin and vmmin (optimization routines: simulated annealing and BFGS) I do not understand how to create and pass in the function (as well as the extra arguments it needs) I am optimizing. I have read the R Extensions manual but it is still unclear to me. Could you give me some pointers and/or direct me to some example code which

I have a set of data that comprises genome numbers in single eggs from three different parasite clones - 3D7, HB3, and MIX. I can draw a boxplot of the genome numbers for each clonefed but how do I carry out a t test or ANOVA to compare if the means are signifcantly different? (Data is listed below) Many thanks, Georgina Humphreys clonefed genomes HB3 21.3 HB3 23.5 HB3 25.9 3D7 27.2 HB3 28.1

Hi, I have some data I want to fit with a non-linear function using nls, but it won't solve. > regresjon<-nls(lcfu~lN0+log10(1-(1-10^(k*t))^m), data=cfu_data, > start=(list(lN0 = 7.6, k = -0.08, m = 2))) Error in nls(lcfu ~ lN0 + log10(1 - (1 - 10^(k * t))^m), data = cfu_data, : step factor 0.000488281 reduced below 'minFactor' of 0.000976562 Tried to increase minFactor

Hi all, I have a question about finalizers... I have a package that manages state for a few connections, and I'd like to ensure that these connections are 'cleanly' closed upon either (i) R quitting or (ii) an unloading of the package. So, in a pared-down example package with a single R file, it looks something like: ##### BEGIN PACKAGE CODE ##### .CONNS <- new.env(parent =

R users, I am having a problem with the modulus operator for large numbers as follows, a <- 2 n <- 561 ## n is the first Carmichael number, so by Fermat's Little Theorem the below should equal zero. (a^(n-1) - 1) %% n [1] 2.193172e+152 ## Seems that R and Fermat disagree ## Also, 1000000000000000000 %% 11 [1] -32 This seems like a bug. Should I be avoiding integer math for large

Hi!I've 2 asteriskAtHome; How can I copy one database where are put all the sip authentificated registration to another one database on one other asteriskAthome so I've always the same Sip registrated and if one linux falls down I can run the other one without problems? Which files must I copy?then..I'll use a ssh scritp for this, I want only know which files I must copy...

R Developers, 1000000000000000000 %% 11 [1] -32 I now understand that integers cannot be larger than .Machine$integer.max, but because the above produces a result than is patently wrong instead of an error, I'm reporting this as a bug. Thank you for the incredible contributions all of you have made in developing the R platform. Best, Robert Robert McGehee Geode Capital Management, LLC 53

Dear R users, I have more of a statistical/econometric question than straight R one. I have a data set with the discrete hazard rate of small firms survival on 400 counties over a period of 9 years. This data was generated using census information from the VAT registration number of each one of these business. I would like to analyze the effect of regional factors (deprivation index, real

Good Morning, I would like to run a question by your technical support team. My employer is currently using Samba server (Samba 2.0.5a) Solaris 8 sun4u sparc SUNW,Ultra-4. Samba is configured to communicate through port 139. However we have been asked to change Samba configuration in order to change the communication from port 139 to 445. This configuration change is requested to improve

An evolution of: https://www.redhat.com/archives/libguestfs/2018-August/msg00155.html

To the R development team: First of all, thank you so much for maintaining wonderful R software. Perhaps, Dr. Ahn has just reported an error on the wilcox.test() function, and suggesting that an error may arise from abs() and rank(). I just had a quick check that the problem may come from the precision of the results of arithmetic functions. 87.7-89.1+1.4 # > 87.7-89.1+1.4 # [1]

I have a asterisk server running on site listening on a public ip. Tonight I attempted to connect a Cisco 7960 phone from my home location via sip but failed. My home network is simple, Cox cable connection hooked to a linksys wrt router. The firewall on the linksys router is disabled and I even setup dmz to the phones ip as a last resort. I removed the linksys router and plugged the phone

Hello, I am trying to get the 'rank' function to work for me, but not sure what I am doing wrong. Please help. I ran the following commands: data = read.table("test1.csv", head=T, as.is=T, na.string=".", row.nam=NULL) X1 = as.factor(data[[3]]) X2 = as.factor(data[[4]]) X3 = as.factor(data[[5]]) Y = data[[2]] model = lm(Y ~ X1*X2*X3, na.action = na.exclude) fmodel =

First, many thanks to Frank Harrell for once again helping me out. This actually relates to the next point, which is my contribution to the 'why don't social scientists use R' discussion. I am a hybrid social scientist(child psychiatrist) who trained on SPSS. Many of my difficulties in coming to terms with R have been to do with trying to apply the logic underlying SPSS, with dire

Hello, dear R-community. This is a question about TukeyHSD between factor combinations of a Three-Way ANOVA, which is - since it is a multi measure ANOVA - not a simple ANOVA but a Generalised Linear Mixed Model (GLMM), calculated with "lmer". > growth <- groupedData(length~meas|box_id,outer=~spec*comp*water,data=all.spec) > model <-

Goodmorning, This is a documentation related question about the B-spline function in R. In the help file it is stated that: "df degrees of freedom; one can specify df rather than knots; bs() then chooses df-degree-1 knots at suitable quantiles of x (which will ignore missing values)." So if one were to specify a spline with 6 degrees of freedom (and no intercept) then a basis

Code: write.table(MU.Cost,paste("C:/RAU/R",as.character(MU.Cost$Run.Id[1]),"." ,as.character(MU.Cost$MU.Id[1]),".MU.PRICE.OUTPUT.txt",sep=""),append = FALSE,quote = FALSE,sep = ",",row.names=FALSE) Output: Run.Id,MU.Id,Class,Av,lower,upper,Count.WO,Count.Seq,Total.WO.Value,Note s 32,158, 1, 0.00, 0.00, 0.00, 0, 0, 0.0,notes 32,158,

Hi Everyone, I've got a question about data representation. I have some psychometric data with 5 scores for 15 different groups. I've been asked to show some kind of mean plots. The data below is the mean and SD for a given group, unfortunately my employer doesn't want me posting full datasets. :( The groups V,W,X,Y,Z are divided into Bottom, (B), Middle (M) and Top (T). An

I have the following timeseries "tab" ===================================== > str(tab) mts [1:23, 1:2] 79.5 89.1 84.9 75.7 72.8 ... - attr(*, "dimnames")=List of 2 ..$ : NULL ..$ : chr [1:2] "Ipex...I" "Omel...E" - attr(*, "tsp")= num [1:3] 2006 2008 12 - attr(*, "class")= chr [1:2] "mts" "ts" > tab