similar to: += assignment operator

Greetings -- coming from Python/Ruby perspective, I'm wondering about certain features of R as a programming language. Say I have a huge table t of the form run ord unit words new 1 1 6939 1013 641 1 2 275 1001 518 1 3 3314 1008 488 1 4 14154 1018 463 1 5 2982 1006 421 Alternatively, it

Dear all, what is the proper way to make the assignment operator generic and define methods depending on the class of the assigned value? Best regards Jens Oehlschl?gel P.S. I vaguely remember that this was possible in S+. In R I tried to no avail: # using this like h<-1:3 gives Error: in `<-.default`(h, 1:3) : invalid (do_set) left-hand side to assignment

Is there a way of removing all rows with missing values from a data frame? I usually use subset(x, var1!="NA") and repeat for each variable. It would be nice to be able to do it in one fell swoop. Also, surprisingly, it doesn't always work. Sometimes I'm left with an empty set even though not all rows have missing values for the variable. Cheers, mikkel Mikkel Grum,

i've written a function to coerce a matrix (e.g. from numeric to logical), but i'd like to know if someone has a more elegant method for this: > m <- matrix(c(0, 1, 1, 0), ncol = 2) > m <- as.logical(m) > m [1] FALSE TRUE TRUE FALSE i'd like 'm' to still be a matrix with the original dimensions. in my function to do this, i coerce 'm' to a logical,

Hi All, If given a dataframe (long form) with Year, Species, and Location, How would I write a function that would create a unique matrix of Species & Location for each Year? What I've tried doing is the following: data #dataframe dataT<-table(data$Species,data$Location,data$Year) #creates tables of Species vs Location for each Year But I'm encountering issues individually

Having just upgraded to 063.3 reminds me of a wish I have had for a long time. Could we not have libraries (sorry, packages) other than for the base distribution in a subdirectory [Rpath]/library/local/ or perhaps /library/packages. This tiny change would make administration so much simpler; I could move all the old packages into the new library in one fell swoop. Granted it's not hopelessly

More principled would be to use a lasso-type approach, which combines selection and estimation in one fell swoop! Ravi ________________________________ From: Ravi Varadhan Sent: Tuesday, June 6, 2017 10:16 AM To: r-help at r-project.org Subject: Subject: [R] glm and stepAIC selects too many effects If AIC is giving you a model that is too large, then use BIC (log(n) as the penalty for adding

On Mon, 11 Oct 2004, John Criswell wrote: > I believe the two best things that we can do to shorten releases is the > following: > > 1. Re-arrange the LLVM and LLVM-GCC builds to build in one fell swoop. > I checkout out, I type make, and it all builds. This requires moving > parts of llvm/runtime into llvm-gcc, or making llvm-gcc an LLVM project, > or some other approach.

Has anyone fed a Nortel BCM from Asterisk? I'm interested in switching our company over, but don't want to replace all the handsets in one fell swoop. I imagine some of the PRI cards can "emulate" a switch? I'd still like to pass CallerID into the Nortel, etc but all the external traffic would be VOIP, not TDM.

Dear All! If I pass an object to an assignment function I cannot get it's name by deparse(substitute(argument)), but I get *tmp* and I found no way to get the original name, in the example below it should be "va1". Is there a way? Thanks, Heinz ## example 'fu1<-' <- function(var, value) { print(c(name.of.var=deparse(substitute(var))))} fu1(va1) <- 3 name.of.var

Hello all: I have a protein sequence alignment in a data frame (align1, 72 x 236), where each row is a protein and each column a site in the alignment. AA is vector of amino acid symbols plus "-" (gap). I can calculate amino acid frequencies at each site by: >align1.F <- matrix(0,nrow=22,ncol=236,dimnames=list(AA,seq(1:236))) >for(i in 1:236) >

Any doubts about R's big-league status should be put to rest, now that we have a Sudoku Puzzle Solver. Take that, SAS! See package "sudoku" on CRAN. The package could really use a puzzle generator -- contributors are welcome! -- David Brahm (brahm at alum.mit.edu) [[alternative HTML version deleted]] _______________________________________________ R-packages mailing list

Any doubts about R's big-league status should be put to rest, now that we have a Sudoku Puzzle Solver. Take that, SAS! See package "sudoku" on CRAN. The package could really use a puzzle generator -- contributors are welcome! -- David Brahm (brahm at alum.mit.edu) [[alternative HTML version deleted]] _______________________________________________ R-packages mailing list

Hi, My apologies if this appears to be a very trivial question -- I have tried to solve this on my own and I am stuck. Any assistance that could be provided would be immensely appreciated. What is the absolute bare minimum that I need to do to disassemble an array of, say, ARM machine code bytes? Or an array of Thumb machine code bytes? For example, I might have an array of unsigned chars -- how

as.character.factor contains this line (where cx=levels(x)[x]): if ("NA" %in% levels(x)) cx[is.na(x)] <- "<NA>" Is it possible that this is no longer the desired behavior? These two results don't seem very consistent: > as.character(as.factor(c("AB", "CD", NA))) [1] "AB" "CD" NA > is.na(.Last.value)[3] [1] TRUE

The following code produces 6 plots on a page, but the first is distorted and different from the others: par(mfrow=c(3,2), las=2) for (i in 1:6) { frame() par(mar=c(7, 7, 1, 1)) axis(2); box(); abline(h=seq(0,1,.5), col=2:4) } The first plot's axes are mis-aligned with the plotting area implied by the box. It seems to be a result of calling par(mar) after frame(). Is this expected

Thanks to David Meyer [david.meyer@ci.tuwien.ac.at] and David Brahm [brahm@alum.mit.edu] who suggested: m[ cbind(index.i, index.j) ] <- vals This works fine for the example I gave. Unfortunately, this approach doesn't extend to using the row and column names to make assignments: > m <- matrix("",ncol=3,nrow=3) > dimnames(m) <-

R> x <- 0. + 1:8000 R> y <- outer(-x, x, pmin) Error: cannot allocate vector of size 1000000 Kb Why does R need to allocate a gigabyte to create an 8000 x 8000 matrix? It doesn't have any trouble with outer(-x, x, "+"). Thanks. -- David Brahm (brahm at alum.mit.edu) Version: platform = i686-pc-linux-gnu arch = i686 os = linux-gnu system = i686, linux-gnu status =

After upgrading to R-2.3.1 on Linux Redhat, I was suprised by this: R> x <- c(721.077, 592.291, 372.208, 381.182) R> sum(x) - 2066.758 [1] 4.547474e-13 Now I understand that floating point arithmetic is not precise, but 1) the result is exactly 0 in R-2.2.1 (patched) on the same machine, 2) .Machine$double.eps = 2.2e-16, so the error seems quite large. Also note I get the same

I sent a message to <r-announce at stat.math.ethz.ch> last Thursday ("New package: colSums"), and still haven't seen it echoed on r-help or on the web archive (in fact there is no r-announce web archive for 2002). Is something broken? Did I need to use <r-announce at lists.R-project.org> instead? -- -- David Brahm (brahm at alum.mit.edu)