similar to: different results depending of variable position.

Hi, in Latex I get the table using: \begin{table}[H] \centering \renewcommand{\arraystretch}{1.3} \setlength{\tabcolsep}{18pt} \begin{tabular}{cc} \hline Idade & Frequ?ncia \\ \hline $18 \vdash 26$ & 11 \\ $26 \vdash 34$ & 8 \\ $34 \vdash 42$ & 26 \\ $42 \vdash 50$ & 20 \\ $50 \vdash 58$ & 23 \\ $58 \vdash 66$ & 30 \\ $66

Hello all, I want to use the "table" function, but for every id I have a different no. of rows (obs.). If I write: table(x$class, x$infec) I don't get the right frequencies because I should count every id once, if id 1 has 20 observations It should count as one. can I use unique func. here? Hope it's clear. thank you, Sigalit. [[alternative HTML version

Full_Name: Chien-yu Peng Version: 2.0.1 OS: Windows XP Professional Submission from: (NULL) (140.109.72.181) Dear all: Although I don't know you, I am thankful for your help. When I use the function mantelhaen.test for R x C x K (R, C > 2) table, the output is not the same as SAS's. I don't know that the result consist with one of SAS's. But it works correctly for 2

Hello R helpers, I would like to automate this code for many files of the same type. But I don´t know how to make it. In particular, i don´t know how to read many files each one as an r object with the name of the file. Then a for loop would be sufficient, right? Many thanks and a happy new year. Dominic datos <- read.table('global2001.csv',head=T,sep=';',stringsAsFactors=F)

Hello, I am having a problem specifying the correlation structure in lme which leads to the error: Error in getCovariate.corSpatial(object, data = data) : Cannot have zero distances in "corSpatial". I have specified a grouping variable which is the only fix I could find by searching this error on R-help. ISee the below example. When my samples (tran) - which are transects

Hi, I have some simple statistics to calculate for a large number of variables. I created a simple function to apply to variables. I would like the variable name to be placed automatically. I tried the following function but is not working. desc = function(x){ media = mean(x, na.rm=T) desvio = sd(x, na.rm=T) cv = desvio/media*100

Hi all Can anybody help me with this? I am trying to include in an automatic way the argument in arg.names in a barplot. I generate the labels I want to appear below the bars with a for loop, and they contain subscripts, so I need to use expression anch<-0.05 esp<-4 for (i in 1:dim(Ntot)[1]) { naux<-Ntot[i,] naux2<-naux[naux>0] nind<-which(naux>0)

In a package, i type a function name and got the following message: ... tmp <- .Fortran("master", x = as.double(x), y = as.double(y), sort = as.logical(sort), rw = as.double(rw), npd = as.integer(npd), ntot = as.integer(ntot), nadj = integer(tadj), madj = as.integer(madj), ind = integer(npd), tx = double(npd), ty = double(npd),

R helpers, I am working with the R program performing multivariate regression trees (MRT). I have a matrix with species and environmental variables saved as a CSV file (sprot_matrix.csv), I have 42 species and 8 environmental variables (SECCHI+PH+TA+PTOT+NTOT+CHLA+AREA+ MEANDEP) for 104 samples Title SpA SpB SpC SpD Varible1 Variable2 Variable3 Sample1 Sample 2

For block effects with small variance, lmer will sometimes estimate the variance as being very close to zero and issue a warning. I don't have a problem with this -- I've explored things a bit with some simulations (see below) and conclude that this is probably inevitable when trying to incorporate random effects with not very much data (the means and medians of estimates are plausibly

Hello, I'm trying to use adabag to make bagging and boosting with bagging() and adabost.M1(), respectively, but in both cases it produces an abnormal termination of R. My code is: bagging(I.NOSOCO~EDAD+SEXO+ESTANCIA+ADMISI?N+T.CIRUG?+DURACI?N+CONTAMIN +PROFILAX+E.PREOPE+V.PERIFE+V.CENTRA+S.VESICA+S.NASOGA+DREN.ABI+DREN.CER

Dear R list, I'm having some problems with font encodings when using R+Sweave+Latex in my native language: Portuguese. My environment: Kubuntu 5.10 Linux $> uname -a Linux nassa 2.6.12-9-686 #1 Mon Oct 10 13:25:32 BST 2005 i686 GNU/Linux R> R.version _ platform i486-pc-linux-gnu arch i486 os linux-gnu system i486, linux-gnu

Hello I wonder how to change the font of chart to Times New Roman and size 9. plot(c(0,100,20),c(0,600,50), xlab= 'Idade(meses)', ylab="Peso(kg)", type = "n", axes=F) axis(1, pos=0, at=seq(0,100,20)) axis(2, pos=0, at=seq(0,600,100)) t<- seq(0,100,1) TA=543.56*(1-0.8976*exp(-0.0522*t)) NI=498.97*(1-0.9259*exp(-0.0494*t)) RC=514.57*(1-0.9112*exp(-0.0499*t))

Hi I have tryed to do the meta-regression in metafor package, but I would like to get the standardized coefficients for each variable, however in command:   Ø  res<-rma.uni (yi, vi, method="REML", mods=~cota+DL+uso+gadiente+idade, data= turbidez)   I just have the coefficients no standardized (estimate) of the multiple regression. What I need to do? Thanks Fernanda Melo

Dear all, I am reading the cch function source code. But I can not understand the following codes. Please help me. What's the fitter here? fitter <- get(method) out <- fitter(tenter = tenter, texit = texit, cc = cc, id = id, X = X, ntot = nn, robust = robust) [[alternative HTML version deleted]]

Hi Mark: I had also used sample and tabulate for generating multinomial and found it to be quite slow. So I had written a multinomial random numbers generator based on the GENMUL subroutine from "ranlib", which in turn is based on the algorithm from Luc Devroye's book on "Non-Uniform Random Variate Generation" You may want to compare this with your hybrid algorithm and

This is an OpenPGP/MIME signed message (RFC 2440 and 3156) --------------enig5A700CC15DEABD01445A1B70 Content-Type: text/plain; charset=ISO-8859-1 Content-Transfer-Encoding: quoted-printable Hi, I have modified the code originally posted to include capability for arbitrary weightings for the rows and columns (which apply in the nominal-ordinal and the ordinal-ordinal cases). The code is pasted

Hi r-devels, I am a bit puzzled by the behaviour of cat() --- any help is appreciated... At least AFAICS, cat() for vector-valued '...' argument behaves in contradiction to what I understand from the note in the help to cat() which reads " Despite its name and earlier documentation, 'sep' is a vector of terminators rather than separators, being output after every

Hi, I am trying to run analyzes incorporating sample weight, strata and cluster (three-stage sample) with PNS data (national health survey) and is giving error. I describe below the commands used. I could not make the code reproducible properly. Thanks, ################################################# library(survey)####change to 0 and 1 variable

Hello, I'm new using R and developing tables. I have a problem in developing a table. In a questionaire I made I ask this question "Please tell me the first three sympthoms caused by Respiratory tract infection you've caught this year", then the people answer three sympthoms, the first mention (Top of mind) is saved in a variable called "P2_A", the second mention in