similar to: stepAIC problem

Dear R-users Could anyone tell me which library contains a function to compute polycoric correlations? I wonder the same question was asked a while ago, but I could not locate the mail in the R-help archives. Sorry for bothering you. Sincerely ------------------------ Hiroto Miyoshi ???? h_m_ at po.harenet.ne.jp

Dear R-users I analysed the same data set by two different ways; analysis of covariance by using lm and anova functions and multiple comparison by using simtest function in the multcomp library. The output from the analysis of covariance is; > y<-lm(D~Cond+Q1,data=x) > anova(y) Analysis of Variance Table Response: D Df Sum Sq Mean Sq F value Pr(>F) Cond 2

Dear R users I have a data frame containing character and numeric variables, whose name is seishin. When I tried to assign NA to "" in the data frame, R, 2.00 showed an error message, such as > seishin[seishin==""]<-NA Error: NAs are not allowed in subscripted assignments This did not happen under R 1.9.0. More oddly, The following commands work just fine under R

Hello. Could someone help me? I can see Japanese language in R when I use RGui. I can use Japanese language in Emacs using Mule option. Now, Can I see Japanese language in R which is run with Emacs(ESS) ? I am using windows 98 second edition. Could someone help me ? Sincerely ----------------------- Hiroto Miyoshi ???? h_m_ at po.harenet.ne.jp

This is obviously not a complete answer, but if you look at the data closely: str(dta) 'data.frame': 40 obs. of 6 variables: $ x : num 0.915 0.937 0.286 0.83 0.642 ... $ y : num 0.3796 0.4358 0.0374 0.9735 0.4318 ... $ z : int 1 1 1 1 1 1 1 1 1 1 ... $ x_axis : int 1 2 3 4 5 6 7 8 9 10 ... $ rslt_without_I: num 0.7657 0.8474

Hi All , Can anybody tell me if there's any way to get the summarized anova values.Now i will explain what i mean , when i say "*summarized*". Below you can see the anova table of recmeanC1 with rest* all* i.e from recmeanC2 to i15(predictors),as shown in table. Df Sum Squares Mean Square F value Significance [Pr(>F)] recmeanC2 1 89.272 89.272

Dear All, I'm getting confused with the concept R uses to do regression using lm. I'm afmiliar with gnuplot and the build-in fit command, but couldn't get R's lm to work on my data. I know that my data follows a powerlaw or maybe an exponential function, and I'd like to determine the best fitting factors for the formula: a*x^b where b < 0. I've tried thge follwoing:

Hi, let me correct my previous post ("zeros in double matrix rather than character matrix"). I have included entries from the .csv file that has 4 columns of 1000 columns and 101 rows. The first column with the "Time (day)" will not be removed, but the row headers are the numbers 1 to 1000 and they will remain in the matrix. In the previous post I mentioned that R makes the

Hi, how are you? I have 1000 total columns with 100 rows and I have shown 4 columns of 100 rows below. I want the zeros to be read in as numerical or integer values rather than a character. Right now I have a 100x0 character matrix rather than a 100x1000 double matrix. What do I need to do to read in a .csv spreadsheet with counting the zeros as a numerical or integer value? Thank-you. Irucka

Hi, I am new in statistics and i manage to make the linear model analysis but i have some difficulties in explaining the results. Can someone help me explalinig the output of my linear model analysis ? My data are with 2 variables habitat (e,s) and treatment (a,c,p) with multiple trials within. Thank you in advance Call: lm(formula = a$wild ~ a$habitat/a$treatment/a$trial) Residuals: Min

Hello R users, For the last few days I am struggling with the following task: my data.frame: A1 A2 A3 B1 B2 B3 58.81 53.292 54.501 13.013 17.39 19.407 56.02 56.251 54.033 20.099 13.15 10.411 55.376 53.099 57.625 13.396 21.031 13.22 58.584 53.194 54.218 13.038 16.854 19.289 55.7 55.921 53.847 19.942 13.153 9.828 55.093 52.934