similar to: grep and gsub on backslash and quotes

Displaying 20 results from an estimated 10000 matches similar to: "grep and gsub on backslash and quotes"

2003 Oct 13
4
help with gsub and grep functions
Hi all, Let Names a vector of chatacters. For example, > Names [1] "g 604 be-0 -p1 (602 matches)" "g 606 Phli-0 -p2 (517 matches)" [3] "g 608 alu-0 (659 matches)" I try to use gsub or grep functions for two problems : 1. First, I would like to delete all the characters between parentheses. [1] "g 604 be-0 -p1" "g 606 be-0 -p2" [3] "g
2012 Mar 07
1
gsub: replacing double backslashes with single backslash
Hello everybody, this might be a trivial question, but I have been unable to find this using Google. I am trying to replace double backslashes with single backslashes using gsub. There seems to be some unexpected behaviour with regards to the replacement string "\\". The following example uses the string C:\\ which should be converted to C:\ . > gsub("\\\\",
2004 Aug 27
3
gsub, backslash and xtable
R Version 1.9.1 (2004-06-21) Mac OS X.3.5 Dual 2GHz PowerPC G5 GUI = "AQUA" I have a data.frame comprising percentiles with the column headings containing % characters, e.g. > (pp <- colnames(temp2)) [1] "5%" "10%" "25%" "50%" "75%" "90%" "95%" I use xtable to convert the data.frame to Latex but I want to
2011 Apr 29
1
regular expression in gsub() for strings with leading backslash
Hello, Can anyone help on gsub() in R? I have a string like something below, and wanted to delete all the strings with leading backslash, including "\xa0On", "\023, "\xab", and many others. How should I write a regular expression pattern in gsub()? I don't care how many characters following backslash. txt <- "Is This Thing\xa0On? http://bit.ly/jAbKem
2012 Dec 17
2
Formatting a path for unix with gsub
I have a path: path = "/nfs/users/nfs_n/ns9/ Phenotype Analysis/Results/Run_AmplRatio_neg BinaryAll trained without akapn+tnik.csv" I wish to replace the spaces with "\ " so that it can be read by a system call to unix. Using gsub I try: > gsub(" ","\\ ",path) [1] "/nfs/users/nfs_n/ns9/Phenotype Analysis/Results/Run_AmplRatio_neg BinaryAll
2011 Jul 17
3
gsub() with unicode and escape character
Dear helpers, I'm trying to replace a character with a unicode code inside a data frame using gsub(), but unsuccessfully. > data.frame(animals=c("dog","wolf","cat"))->my.data > gsub("o","\u0254",my.data$animals)->my.data$animals > my.data$animals [1] "d??g" "w??lf" "cat" It's not that a data
2011 Aug 30
2
url prep function (backslash issue)
Greeting R Community, I am a windows user so this problem may be specific to windows. I often want to source files from within R such as: C:\Users\Rinker\Desktop\Research & Law\Data\School Data 09-10. To source this file I need to go through the path and replace all the backslashes (\) with forward slashes (/). I usually do this in MS Word using the replace option, however, I'd like
2006 Apr 24
3
gsub + backslashes
Dear developeRs, I thought that backslashes can be escaped in the usual way (and I think I did this before) but I can't see why R> gsub("\\", "x", "\alpha") Error in gsub(pattern, replacement, x, ignore.case, extended, fixed, useBytes) : invalid regular expression '\' gives an error. Or am I just blind? Best, Torsten R> version
2011 Nov 04
3
replace double backslash with singel backslash
I want to replace \\ with \ in: str <- "C:\\DOKUME~1\\u0327336\\LOKALE~1\\Temp\\RtmpQ5NJ8X\\TIRIS_PICS\\1_Img.jpg" and tried: gsub("\\\\", "\\", str) but this removes the \\ without replacing them by \ Any help much appreciated, Kay ----- ------------------------ Kay Cichini Postgraduate student Institute of Botany Univ. of Innsbruck ------------------------
2009 Apr 03
2
Removing backslashes from data
I am trying to check for backslashes in data, then remove them when I find them, but am having a difficult time figuring out the best way to do it. I know the backslash is the escape character in R, and I should be able to use 'gsub' to accomplish this, but I all I seem to be getting are errors. For example: If entry is: "Hello\World" I want: "HelloWorld"
2006 Feb 01
3
inserting one backslash
Hello, I am not very familiar with regular expressions and escaping. I need to replace the %-signs in a character vector with elements as "income 0%-33%# to be replaced by "income 0\%-33\%" (for later use in LaTeX). Using gsub("%","\\%","income 0%-33%") does not give the desired result. However, gsub("%","\\\\%","income
2004 Nov 29
4
escaping backslash in a string
How can I get a single backslash in a character string? My goal is to escape dots in a string that will be used as a regular expression. I thought I could do it this way: gsub(".", "\\.", x) Unfortunately, "\\" does not represent a literal backslash as I expected, but rather a pair of backslashes: > "\\." [1] "\\." > "\\" [1]
2005 Jun 09
3
dir() and RegEx and gsub()
Dear R-Users, I have two questions: a) in a directory there are 3 files: [1] "Data.~csv" "Kopie von Data.~csv" "VorlageTradefile.csv" The command "dir( fold, pattern = "\.csv" )" gives back *all* the 3 files With dir( fold, pattern = "\\.csv" ) I get back only VorlageTradefile.csv. I don't understand this behaviour,
2024 Apr 11
3
Regexp pattern but fixed replacement?
I noticed this issue in stringr::str_replace, but it also affects sub() in base R. If the pattern in a call to one of these needs to be a regular expression, then backslashes in the replacement text are treated specially. For example, gsub("a|b", "\\", "abcdef") gives "def", not "\\\\def" as I wanted. To get the latter, I need to escape
2009 Feb 06
3
Sweave and backslashes
Hello Everyone, I am an avid Sweave user and I am trying to pretty print floating point numbers for latex output. For example in my document, I would like: 4.2\cdot 10^-{8} Instead of: 4.2e-08 The Hmisc package has a nice function for doing this- but Hmisc has a ton of dependencies and has proved very unportable to the various machines I work on. So, I set out to write my own function that
2008 Sep 23
3
How to convert backslash to slash?
How to use sub, gsub, etc. to replace "\" in a string to "/"? For example,convert "C:\foo\bar" to "C:/foo/bar". Thanks, Shengqiao Li
2003 Nov 18
4
address for bug reports? (PR#5171)
bug.report() tells me to email to r-bugs@r-project.org, whereas the Web site http://www.r-project.org/ points me to r-bugs@biostat.ku.dk. Which should I believe? Simon Fear Senior Statistician Syne qua non Ltd Tel: +44 (0) 1379 644449 Fax: +44 (0) 1379 644445 email: Simon.Fear@synequanon.com web: http://www.synequanon.com Number of attachments included with this message: 0 This
2003 Aug 12
8
capturing output from Win 98 shell
How can I best achieve the following (works in Splus): filenames <- dos("dir *.sasb7dat /b") What I am asking, more generically, is: how can I capture the output of a DOS command in R? I have tried using system("COMMAND.COM /c dir /b", intern=T, show.output.on.console=T) where intern: a logical, indicates whether to make the output of the command an R
2009 Jan 19
1
sub and gsub treat \\ incorrectly (PR#13454)
Sub and gsub treat \\ replacement pattern incorrectly I expect sub("a","\\", "a", perl=T) to produce [1] "\" instead it generates [1] "" On the other hand, if I run sub("a","\\\\", "a", perl=T) it correctly outputs [1] "\\" The same issue applies to gsub. --please do not edit the information
2003 Nov 18
3
plot, plot, methods, crash (PR#5173)
(If this only happens in Win 98, I'm sure I could live with it. Just may be helpful to report it, I hope.) Start up R GUI, then > plot(1:4,1:4) # then close manually by clicking X > plot(1:4,1:4) # ditto > methods(plot) sometimes produces normal output and even the following prompt, but then crashes immediately, or more often, crashes immediately with no output. I can do any