similar to: curves with shaded areas?

Widows XP R 2.3.1 I have been trying to make a data structure that will contain both the coefficients from a linear regression along with column and row titles AND the call, i.e. myreg<-lm(y~x+y+z) whatIwant<-cbind(c(summary(myreg)$call,"",""),summary(myreg)$coefficients) Neither the statement above, nor any one of twenty variations I have tried work. I would appreciate

Hi I would like to plot the variation of some mean values with time, and have the standard deviation around the mean shaded on the plot. I could not find a way to have the shaded area on the curve with the default R commands, do I need a special package to do that? Or any idea of a way with the default R commands? Many thanks Thomas -- Thomas Loridan King's College email: thomas.loridan

I am trying to store regression objects in a data.table df <- data.frame(x = rnorm(20)) df[, "y"] <- with(df, x + 0.1 * x^2 + 0.2 * rnorm(20)) mydt <- data.table(mypower = c(1, 2), myreg = list(lm(y ~ x, data = df), lm(y ~ x + I(x^2), data = df))) mydt #?? mypower??? myreg #???? <num>?? <list> #1:?????? 1 <lm[12]> #2:?????? 2 <lm[12]> But mydt[1, 2]

Hi all, I want to generate an assembly instruction for my target using target description representation of the instruction. The problem is that I want to add direct register to be chose as an output register for my target. Does it possible to do with an instruction definition in TARGETInstrInfo.td file? May be someone could help with an example? Currently I have seen that we can pass the name

Hello! I have run a simple regression - lm and created a regression object "myreg". I can see all the coefficients when I print(myreg). Then I tried to run vif(myreg) from the package "car". However, it's giving me an error: in vif.lm(regr.f) : there are aliased coefficients in the model Very sorry for my question: Is there any way to get the vif's for all predictors?

Well, you may have good reasons to do things this way -- and you certainly do not have to explain them here. But you might wish to consider using R's poly() function and a basic nested list structure to do something quite similar that seems much simpler to me, anyway: x <- rnorm(20) df <- data.frame(x = x, y = x + .1*x^2 + rnorm(20, sd = .2)) result <- with(df,

I really like to use R for all my graphs, and as I work with stable isotopes I want to have a proper chemical notation in my plots I have looked at ?plotmath, but didn't find the answer and also searched the R website. ------------------------------------------------------------------------ -- plot(1:10,xlab=expression(^{14}*C)) # I want to have a superscript with nothing in front, but it

Hello, I would like to know if (as the usa map with Splus), it is possible with R to plot the french map and to add points (representing towns for instance) on the figure in the appropriate (x,y) system. Thank you. Nathalie Peyrard

Hi, today, I noticed a problem in focus handling for shaded windows which is pretty easy to reproduce: - Disable "Click to focus" - Shade a window - Hover another window - Hover back to the window frame of the shaded window - Press Ctrl+Alt+S Expected behaviour would be that the shaded window is unshaded. What happens is that the last active window is shaded. I investigated this a

Thanks everyone for their responses. My data is organized in a data.table.? My goal is to perform analyses according to some groups.? The results of analysis are objects.? If these objects could be stored as elements of a data.table, this would help downstream summarizing of results. Let me try another example. carsdt <- setDT(copy(mtcars)) carsdt[, unique(cyl) |> length()] #[1] 3

Hi all, suppose there is a vector y with rownames: > y cond1 cond2 cond3 cond4 78.952 87.308 86.490 74.040 how can I easily plot this vector using the rownames? plot(y) gives me a plot with a x-axis from 1 to 4 in 0.5 steps, also plot(rownames(y), y) and plot(y ~ rownames(y) don't work. I know I can build a x-axis with axis(1, ...), but in this case I need a character string like

Hello, I would like to place shaded boxes on different areas of a phylogenetic tree plot. Since I can not determine how to find axes on the phylogenetic tree plot I am not able to place the box over certain areas. Below is example code for the shaded box that I have tried to use, and the first four values specify the position. rect(110, 400, 135, 450, col="grey",

--- src/paint.c | 14 ++++++++++++-- 1 files changed, 12 insertions(+), 2 deletions(-) diff --git a/src/paint.c b/src/paint.c index 00cbf73..4ddd332 100644 --- a/src/paint.c +++ b/src/paint.c @@ -193,7 +193,12 @@ paintOutputRegion (CompScreen *screen, if (w->destroyed) continue; - if (!w->shaded) + if (w->shaded) + { + if (w->id < 2) + continue; + } + else

>> today, I noticed a problem in focus handling for shaded windows which is >> pretty easy to reproduce: >> >> - Disable "Click to focus" >> - Shade a window >> - Hover another window >> - Hover back to the window frame of the shaded window >> - Press Ctrl+Alt+S >> >> Expected behaviour would be that the shaded window is

In the 'RWeaveLatexSetup' function in the 'tools' package in R 1.6.0 , the code below does not work (pdflatex can't find 'Sweave.sty'): if (stylepath) styfile <- file.path(R.home(), "share", "texmf", "Sweave") else styfile <- "Sweave" In R 1.5.1, that was: if(stylepath) styfile <-

Hi, does anyone know how do I plot confidence intervals as a shaded band around a curve, rather than as errors bars? many thanks, ulisses. [[alternative HTML version deleted]]

Hi all, I?m trying to plot confidence intervals for the fitted values I get with my lme model in R. Is there any way I can plot this in the form of a shaded band, like the output of geom_smooth() in ggplot2 package. ggplot2 seems to use only lm, glm, gam, loess and rlm as smoothing methods. Any advice on the functions I should use to accomplish this will be very helpful. Thank you very much.

Dear list members, I would like to plot a time series, with grayshaded background in time phases were the value of the timeseries exceeds the mean value. For example, if the temperature from 1995-1998 exeeds the mean value between 1980 and 2005, the background in the plot from 1995-1998 shall be shaded. Can anybody help me? Thanks Thomas H.

say, I am plotting x=seq(0,5,len=100) y=-(x-5)^2 plot(x,y) how can I put some color or verticle lines below the plotted curve? [[alternative HTML version deleted]]

Dear R users, I have an xlsx file (attached to this mail) that shows the values of a "der" series observed on a daily basis from January 1, 2017 to January 25, 2017. This series is strictly positive during two periods: from January 8, 2017 to January 11, 2017 and from January 16, 2017 to January 20, 2017. I would like to plot the series with two shaded areas corresponding to the