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Have a look at ?optim. I don't think it has the BHHH algorithm as an option, though. =========================================== David Barron Jesus College University of Oxford -----Original Message----- From: r-help-bounces at stat.math.ethz.ch [mailto:r-help-bounces at stat.math.ethz.ch]On Behalf Of Harold Doran Sent: 10 July 2003 15:43 To: Fohr, Marc [AM]; R-help at stat.math.ethz.ch

>I am interested in R as an alternative for a statistical tool >at our firm. Ditto... I have recently moved to this agency from a company where I had access to Splus. There is also a coworker here who had used Splus at a previous employer. We both would like some access to the S language. We are considering either begging loud and long to try to get the agency to purchase two copies of

>>>>> "Jens" == Jens Oehlschlaegel <oehl at Psyres-Stuttgart.DE> writes: Jens> I just saw a beta version of WinS+4.0 last week: Good and bad Jens> news: MATHSOFT has substantially improved graphic handling and Jens> user interface. Bad news is: The version I saw needed 50 MB Jens> RAM, so our equipment should have 64 MB RAM minimum. This is

Dear list subscriber (R-Core), there is a minor typo in the Windows specific NEWS for R 2.9.0: http://cran.at.r-project.org/bin/windows/base/CHANGES.R-2.9.0 There is no function 'memory.limits() but memory.limit() (see below). Secondly, I am kind of irritated by the function's behaviour. It returns an Error, but as it seems the memory limit is set according to the numeric value for

Dear list subscriber, suppose, I do have a minimal Sweave file 'test.Rnw': \documentclass{article} \begin{document} <<printx>>= x @ \end{document} Within R, I define the following function: f <- function(x){ Sweave("test.Rnw") } The call: f(x = 1:10) results in the following error message: > f(x = 1:10) Writing to file test.tex Processing code chunks

Hi All! I am interested in testing whether the means for the data I am investigating are equal to a specific value - let's say 0.01. I have already run a one-way ANOVA and know that the differences in the means are not significant, so now I want to know what values the means take on. "otestme" is the data I am working with (it would be hard for me to get into a form that would be

Hi, Can anyone shed any light on why "reaper" (whilst seemingly working re restarting my mongrel ruby process) does not pick up changes to my application? (e.g. changing a title in a view for example). It''s like the "mongrel_rails start etc..." is just restarting the current process but ignoring the new details re where the new application directory is. That is

Hi All! I have been messing around with this problem for about a week but to no avail! The following data has been cut down in order to make my question reproducible. The alldat data frame includes 2 columns: 1 date column and 1 factor column (equity names)).

Dear list, I encounter an error when I try to use ddply to generate means as follows: fun3<-structure(list(sector = structure(list(gics_sector_name = c("Financials", "Financials", "Materials", "Materials")), .Names = "gics_sector_name", row.names = structure(c("UBSN VX Equity", "LLOY LN Equity", "AI FP Equity",

The other day, CNN had a story on working at Google. Out of curiosity, I went to the Google employment web site (I'm not looking, but just curious). In perusing their job posts for statisticians, preference is given to those who use R and python. Other languages, S-Plus and something called SAS were listed as lower priorities. When I started using Python, I noted they have a portion of the

Basic question but still learning .... How do I plot two lines (f$equity and f$bh.equity) on one of the three graphs under mfrow ? I tried putting brackets around the first plot and lines command but that didn't work. par(mfrow=c(3,1)) {plot(f$Date,f$equity, col="blue", type="l", main="equity") lines(f$bh.equity, col="gray")} plot(f$Date,f$indicator,

On Thu, 6 Jul 2023 at 15:21, Anupam Tyagi <anuptyagi at gmail.com> wrote: > > Btw, I think "lattice" graphics will provide a better solution than > "ggplot", because it puts appropriate (space saving) markers on the axes > and does axes labels well. However, I cannot figure out how to do it in > "lattice". You will need to convert Income to a

Hi John: Thanks! Below is the data using your suggestion. I used "ggplot" to make a graph. I am not too happy with it. I am looking for something simpler and cleaner. Plot is attached. I also tried "lattice" package, but nothing got plotted with "xyplot" command, because it is looking for a numeric variable on x-axis. ggplot(TrialData4, aes(x=Income, y=Percent,

Anupa, I think your best bet with your data would be to tidy it up in Excel, read it into R using something like the readxl package and then supply some sample data is the dput() function. In the case of a large dataset something like dput(head(mydata, 100)) should supply the data we need. Just do dput(mydata) where *mydata* is your data. Copy the output and paste it here. On Thu, 29 Jun 2023

Btw, I think "lattice" graphics will provide a better solution than "ggplot", because it puts appropriate (space saving) markers on the axes and does axes labels well. However, I cannot figure out how to do it in "lattice". On Thu, 6 Jul 2023 at 15:11, Anupam Tyagi <anuptyagi at gmail.com> wrote: > Hi John: > > Thanks! Below is the data using your

Hallo Anupam I do not see much difference in ggplot or lattice, they seems to me provide almost identical results when removing theme part from ggplot. library(ggplot2) library(lattice) ggplot(TrialData4, aes(x=Income, y=Percent, group=Measure)) + geom_point() + geom_line() + facet_wrap(~Measure) xyplot(Percent ~ Income | Measure, TrialData4, type = "o", pch = 16, as.table =

Thanks! You are correct, the graphs look very similar, except ggplot is scaling the text font to make it more readable. Is there a way to scale down the x-axis labels, so they are readable? On Fri, 7 Jul 2023 at 12:02, PIKAL Petr <petr.pikal at precheza.cz> wrote: > Hallo Anupam > > I do not see much difference in ggplot or lattice, they seems to me > provide almost identical

Hi, I am using sendmailR package to send mails from R. I am not able to make carbon copy work properly. If I specify multiple recipients in to field, then they all receive individual emails and not carbon copies My sample code is require(sendmailR) header <- list(cc="b.mali@abc.com") to <-

Hi, Complete newbie to R here. Just getting started reading manuals and playing with data. I've managed to successfully get my *.csv files into R, however I have to use header=FALSE because the real header starts in line #2. The file format looks like: PORTFOLIO EQUITY TABLE TRADE,MARK-SYS,DATE/TIME,PL/SIZE,PS METHOD,POS SIZE,POS PL,DRAWDOWN,DRAWDOWN(%),EQUITY 1,1,1/8/2004 12:57:00

Dear all, in the package its the print() method does not seem to correctly work in all circumstances: > selectMethod(print, "its") Method Definition: function (x, ...) { print(x@.Data <mailto:x@.Data> , ...) } <environment: namespace:its> Signatures: x target "its" defined "its" > fundPME.lst[[1]]$irr An object of