similar to: lines(aline, type = 'b', col = "blue) does not work for POSIXct plot.

Here are the beginning of a R program. I hope it can help you writing the rest of the program. Regards Martin M. S. Pedersen ---- filename <- "university.data" lines <- readLines(filename) first <- T for (ALine in lines) { ALine <- sub("^ +","",ALine) ALine <- sub(")","",ALine, fixed = T) if

Me encantaría saber pensar así de una. Creo que entiendo bien lo que me decís, pero no lo puedo poner en marcha en mi computadora, por algo que no sé qué será. Cuando llego a: > cosa<-aline(w1=x,w2=y) En RStudio me dice que R sufrió algo. Probé directamente desde la consola linux y también: > cosa<-aline(w1=x,w2=y) *** stack smashing detected ***: /usr/lib/R/bin/exec/R terminated

¡Buenas, listeros! Supongo que lo que planteo es muy básico, pero estoy trabado y no lo veo. Tengo una función que da la distancia lingüística ALINE, alineR::aline(), pero que no genera matrices. Tengo que hacer matrices de distancias ALINE de unos datos tipo esto: A cansado B cansadísimo C cansau D reventado E reventao F NA G canso alineR::aline("cansado", "cansado") # 0

Hi, I have a data frame, > df=rnorm(1000) > dim(df)=c(100,10) > And i can get the boxplot, > boxplot(data.frame(df)) So how can add a line (aline) on the existing boxplot,eg, aline=apply(df,2,max) Thanks in advance. [[alternative HTML version deleted]]

Hello: What is the recommended method for retaining the tzone attributes when concatonating POSIXct objects? > (d1 <- ISOdate(1970,1,1)) # Sets the tzone attribute = GMT [1] "1970-01-01 12:00:00 GMT" > (d1.2 <- c(d1, d1)) # c(..) strips the tzone attribute, displays in the time zone of the operating system [1] "1970-01-01 04:00:00 PST" "1970-01-01

a closer look to the help on predict.glm will reveal that the function accepts a 'type' argument. In you case 'type = response' will give you the results in probabilities (that it seems to be what you are looking for). There also is an example on use of the 'type' argument at the end of the page. Stefano -----Messaggio originale----- Da: r-help-bounces at r-project.org

Good Morning! My apologies for what may be considered an infantile question: I have data that I would like to plot, positive integers for the y-axis, and time coordinates of the "Sun Apr 20 22:45:27 PDT 2003" format for the x-axis. I have tried: x1 <- 1050352610 x2 <- 1050352999 x3 <- 1050858319 class(x1) <- "POSIXct" class(x2) <- "POSIXct"

Dear R Discussion Group, Thanks for making such an interesting and capable Statistics package available. It certainly "saved my bacon" during this past academic quarter. I have had no trouble at all installing the sources on my linux box: The configure and make scripts work perfectly. I have had no luck attempting to install these at work, though. My workplace uses a Solaris 8

Hi All, I'm trying to build klibc against my own kernel source tree. The build goes fine, the problem is to install it. As usr/klibc/README asks, I've create a symlink called linux pointing to my kernel tree: lrwxrwxrwx 1 root root 25 Jul 2 16:18 linux -> /usr/src/linux-2.6.22-rc6 anderson-herzer:/usr/local/src/klibc-1.5# export LANG=C anderson-herzer:/usr/local/src/klibc-1.5#

I've upgraded laptops and have put a new version of R on the new machine as well as the tools for building packages. I know R has required a "non-broken" version of tar for some time now and was hoping to not have to install any cygwin tools. Since building packages requires the use of MinGW and MSYS, why can't we simply use the tar that's part of msys? After looking at

Hello I'm working with mixed effects models using lmer() and have some problems to get all variance components of the model's random effects. I can get the variance of the random effect out of the summary and use it for further calculations, but not the variance component of the residual term. Could somebody help me with that problem? Thanks a lot! Below an example. Aline ## EXAMPLE

SSweibull() :  problems with step factor and singular gradient Hello I am working with growth data of ~4000 tree seedlings and trying to fit non-linear Weibull growth curves through the data of each plant. Since they differ a lot in their shape, initial parameters cannot be set for all plants. That’s why I use the self-starting function SSweibull(). However, I often got two error messages:

Hello everyone, I'm having a problem with the replication of the Active Directory from a Windows Server 2003 r2 DC to a Samba 4.1.6 (Ubuntu 14.04) DC. The problem we have is that the *memberOf* attribute is missing on two users in the Samba ldap database after adding them to a group on the Windows DC. I can't easily add these through a Ldap administration tool and can't add them to

Dear friends, Is there a way to read data files written in lisp into R? Here is the file: https://archive.ics.uci.edu/ml/machine-learning-databases/university/university.data I would like to read it into R. Any suggestions? Thanks very much in advance for pointers on this and best wishes, Ranjan -- Important Notice: This mailbox is ignored: e-mails are set to be deleted on receipt. Please

Although the documentation is somewhat sketchy, I() can be used to create objects of class AsIs: > I("a") [1] "a" attr(,"class") [1] "AsIs" "character" > I(4) [1] 4 attr(,"class") [1] "AsIs" "numeric" > I(4 + 0i) [1] 4+0i attr(,"class") [1] "AsIs" "complex" > This

I am using R-1.7.0 and have some data which consist of one vector of numbers and a second corresponding vector of dates belonging to the POSIXct class. I would like to plot the numbers against the dates. What is the best way to do this? It almost works to just call `plot.' However if I do this while using the `ylab' parameter I get a warning message: parameter "ylab"

I have some data that was created for import into a Lotus 1-2-3 spreadsheet and on of the columns is time. The time is akin to Julian were the value 1 is mapped "01-Jan-00 12:00:00 AM" in Lotus 1-2-3. Is there a function in an R package that can convert this numeric vector to a POSIXct vector? With best wishes and kind regards I am Sincerely, Corey A. Moffet Instructor Department

R developers, The "tzone" attribute is stripped from a POSIXct object when the subscript command is called ("[.POISXct"). This results in dates being printed in the locale specific format after a subscript operation is applied to a POSIXct object which has cause several problems for me in the past. Here is an example of this problem under R 1.9.1: > x <-

Hallo all I have a question regarding POSIX class objects. I try tu use as.POSIXct for creating and plotting some time series. To be able to set labels for time (x) axis I started with plot(..., axes=FALSE) but although it suppressed all other axes, x axis is still plotted together with labels. Is it a bug? see datum.vyber<-seq(ISOdate(2000,1,1), ISOdate(2003,1,1), by="3

Hi all, I'm having difficulty converting a 'dates' object to a POSIXct object: testDATES<-c(35947,35971,36004,36008,36053,36066) testDATES<-chron(dates=testDATES, format = c(dates = "m/d/y"), origin=c(month = 12, day = 30, year = 1899)) >[1] 06/01/98 06/25/98 07/28/98 08/01/98 09/15/98 09/28/98 > as.POSIXct(testDATES) [1] NA NA NA NA NA NA