similar to: pasting "\" into character strings

Dear Help, Suppose I have a character vector. x <- c("Bob", "loves", "Sally") I want to combine it into a single string: "Bob loves Sally" . paste(x) yields: paste(x) [1] "Bob" "loves" "Sally" The following function combines the character vector into a string in the way that I want, but it seems somewhat inelegant.

Dear R-Help, Suppose I have a character matrix, e.g., (ch.mat <- matrix(c('a','s','*','f','w','*','k','*','*','f','i','o'), ncol=3)) When I convert 'ch.mat' to a dataframe, the columns are converted to factors: (d1 <- data.frame(ch.mat)) mode(d1[,1]) is.factor(d1[,1]) To prevent

Dear R Help, I am trying to create a boolean vector that is TRUE whenever a particular value occurs in a numeric vector, and FALSE otherwise. For example, suppose that > y <- c(5, 2, 4, 3, 1) > y [1] 5 2 4 3 1 and suppose that I want to find where 3 occurs in y. Then, the following yields the solution: > y == 3 [1] FALSE FALSE FALSE TRUE FALSE My problem arises when the

I have run into a general problem with subsetting of which the following is a simple example. Suppose that x <- c(5, NA, 7, 5, NA, 3) y <- c(1, 2, 3, 4, 5, 6) I want to extract the values of y for which x = 5, but y[x==5] yields > y[x==5] [1] 1 NA 4 NA I find that y[!is.na(x) & x==5] yields the desired result: > y[!is.na(x) & x==5] [1] 1 4 but I am wondering whether

Dear R Users, I want to write a function that applies to the dataframe and variables that were used in a previous call to lm or aov. In order to do this, I need to write a function that applies to the output of lm or aov, and yields the names of the dataframe and variables that were used in the lm or aov analysis. For example, suppose that I give the command: aov.out <- aov( Rt ~

A student of mine wants to use R to do some nonmetric multidimensional scaling. According to the R FAQ, there's a package called pcurve that computes multidimensional scaling solutions, but I was not able to locate it the contrib page (I am a Windows user with R version 1.4.1). Can anyone tell me whether it is possible to do nonmetric multidimensional scaling with R, and if so, how? John

Dear R-users, I am learning to use R 1.3.1 on a Pentium running Windows '98. I'm puzzled that several statistical procedures, t.test and chisq.test, do not appear to be available on R version 1.3.1. For example, if I type "t.test", I get the reply, "Object "t.test" not found". Is there a package that I have to load in order to have access to these

Greetings, I have a question pertaining to the concept of "environment variables" that is mentioned in the R documentation for "Startup" and also in the discussion of the Windows configuration of R in the recent book "An Introduction to R" authored by Venables, Smith, and the R Development Core Team (referred to as VS in this message). The Startup documentation and

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I sent a query to R-Help about the availability of nonmetric multidimensional scaling (MDS) algorithms in R. I would like to thank Tony Rossini, Jonathan Baron, Sundar Dorai-Raj, and Brian Ripley for helpful replies. The gist of the replies is that isoMDS in the MASS library provides Kruskal's method for nonmetric MDS, sammon in the MASS library provides Sammon's nonlinear mapping method

Dear R-Help, I am using the studres function from the MASS package to compute studentized deleted residuals in a oneway anova. I'm having trouble interpreting the results in situations where a factor level has only one observation. Sometimes studres yields an NaN and sometimes it produces a numeric value for cases where a factor level has only one observation. I would think it should

Hi, How can I partitioned an example vector like this > print(myvector) [1] 30.9 60.1 70.0 73.0 75.0 83.9 93.1 97.6 98.8 113.9 into the following pairwise partition: PAIR1 part1 = 30.9 part2 = 60.1 70.0 73.0 75.0 83.9 93.1 97.6 98.8 113.9 PAIR2 part1 = 30.9 60.1 part2 = 70.0 73.0 75.0 83.9 93.1 97.6 98.8 113.9 .... PAIR9 part1 = 30.9

Hi, I have this kind of output. > str(nw) List of 3 $ :List of 2 ..$ part1: num 30.9 ..$ part2: num [1:78] 60.1 70.0 73.0 75.0 83.9 ... $ :List of 2 ..$ part1: num [1:2] 30.9 60.1 ..$ part2: num [1:77] 70.0 73.0 75.0 83.9 93.1 ... $ :List of 2 ..$ part1: num [1:3] 30.9 60.1 70 ..$ part2: num [1:76] 73.0 75.0 83.9 93.1 97.6 ... My question are: 1. What kind of data structure

Hey List, Firstly I am sorry for the length of this email and that you are all having too receive it but the point is that this email will now go into the archive and be indexed by Google (hopefully) and thusly, people will be able to find these links through Google. My goal is to mirror CentOS on RapidShare. "Why you fool there are loads of mirrors?" you might ask; simply for

Hello, I'm trying to do the following and encountering problems with the generated arm assembly code: I've got an application in two parts that i've compiled into llvm bitcode using: llvm-gcc -emit-llvm -c part1.c -o part1.bc llvm-gcc -emit-llvm -c part2.c -o part2.bc Then I link them together: llvm-ld part1.bc part2.bc -o combined.bc Now I use the ARM backend via llc to

Colleagues, I am encountering difficulty adding formatted text to a graphic. Specifically, I want to add a superscript in the middle of a text string but I would like to format the text string on the fly. The commands: plot(1,1) ARG <- bquote('TEXT'^'\u00ae') mtext(ARG, line=-2, side=1) yield the desired output. However, my goal is to paste together a string, then pass

Hello; I am trying following but getting a warning message : Warning in rbind.zoo(...) : column names differ, no matter whatever I do. Also I do not want to specify column names manually, since I am just writing a wrapper function around getSymbols to get chunks of data from various sources - oanda, dividends etc. I tried giving col.names = T/F, header = T/F and skip = 1 but no help. I think

I am trying to merge two data frames, but one of the column headings are different in the two frames. How can I rjoin or rbind the tho frames? Johnny # Generate 2 blocks by confounding on abc d1 <- conf.design(c(1,1,1), p=2, block.name="blk", treatment.names = c("A","B","C")) d2 <- conf.design(c(1,1,1), p=2, block.name="blk",

Hey guys, i have a strange problem reading a .csv file. Seems not to be covered by the usual read.csv techniques. The relevant data i want to use, seems to be saved as the label of the data point. Therefore i can not really use it spec<-"EU2001"

Hello, I have written the function I would like to integrate in two ways: denfxn <- function(yy,vv,a2,b2,mu2) { pp <- 1-pnorm(yy/sqrt(vv)) part1 <- pp^(a2-1) part2 <- (1-pp)^(b2-1) part3 <- dnorm(yy,mu2,sqrt(vv)) return(part1*part2*part3) } denfxnorg <- function(yy,vv,a2,b2,mu2) { pp <- 1-pnorm(yy/sqrt(vv)) pp <- if (pp < .001) .001 else