similar to: vector of center of

Displaying 20 results from an estimated 4000 matches similar to: "vector of center of"

2003 Apr 02
4
randomForests predict problem
Hello everybody, I'm testing the randomForest package in order to do some simulations and I get some trouble with the prediction of new values. The random forest computation is fine but each time I try to predict values with the newly created object, I get an error message. I thought I was because NA values in the dataframe, but I cleaned them and still got the same error. What am I
2003 Apr 25
2
R compilation problem on Sun Solaris 2.5.1
Dear members, I'm not very used with Unix systems, but I got an old Sun/UltraSparc workstation running Solaris 2.5.1 and I tried to install R on it to able able to do some batch R processing while working on my pc. I downloaded and installed following required and recommanded programs before installing R : perl 5.8.0, readline 4.3, gzip 1.3.5, zlib 1.1.4, make 3.80, jpeg 6b, libpng 1.2.4
2002 Jun 18
2
Line width in graphs
Hi, I'm using R to plot some data and associated linear models, and I was wondering if there was a parameter to fix the line width in the graphs (for axis, lines, ...) because I explored the associated help pages and could not find it. Thx in advance, -- Ir. Yves Brostaux - Statistics and Computer Science Dpt. Gembloux Agricultural University 8, avenue de la Facult? B-5030 Gembloux
2004 Nov 30
3
Creating a factor from a combination of vectors
Dear list, Here's a little problem I already solved with my own coding style, but I feel there is a more efficient and cleaner way to write it, but had no success finding the "clever" solution. I want to produce a factor from a subset of the combination of two vectors. I have the vectors a et b in a data-frame : > df <- expand.grid(a=c(0, 5, 10, 25, 50), b=c(0, 25, 50,
2002 Nov 13
4
[Newbie] Is there any support for work with grouped frequencies?
Hi, I have this table (BTW, published by FBI and representing age distribution of the WTC tragedy victims): "LABEL" "FREQ" "MIDPOINT" "1" "Infant (under 1)" 0 "2" "1 to 4" 5 "3" "5 to 8" 1 "4" "9 to 12" 3 "5" "13 to 16" 0 "6" "17 to
2005 Mar 22
3
Lattice : factor levels in the margins
Hello ! I'm struggling again against lattice graprhics. ;) I'm trying to produce a conditionnal xyplot with two conditionning factors (let's say A and B). I want the levels of those factors (A1, A2, etc) to show in the margins of the lattice plot, not in the strips between the panels. A1 A2 A3 plot11 plot12 plot13 B1 plot21 plot22 plot23 B2 I managed to remove the
2002 Nov 22
3
simple test on slope of lm()
Hello I want to compare the slope (let's say 'b') of a linear model obtained with lm() to a theoretical value (let's say 'th'). To do so, I think I should compute a 't value' using something like : (b - 'th')/standard.deviation(b) and then look at the p-value of this computed t. I don't understand how to do this in a simple way, just using lm()
2002 May 28
4
id & filter problems in data.frame
Hi, a questionaire data-set with more than one row for one Person make me problems. (1) i want create a function which count the used row for the relevant id ! example: id c.row 1 1 1 2 1 3 2 1 2 2 4 1 4 2 4 3 4 4 4 5 (2) i have got a problem to filter & analyse , because the filter criteria is unlucky a row above or under the ratings which i would like to
2001 Oct 30
2
creating chron object aggregates (e.g. sums by day)
What is the recommended/optimal way to perform aggregates on data frames with chron objects? Here is an example: >raw.data 1 07/09/01 4000 2 07/09/01 2000 3 07/11/01 1000 4 07/13/01 800 5 07/13/01 700 6 07/16/01 600 7 07/17/01 500 I'm trying to construct a function that would first aggregate the data (second column) by day (grouping by the first column) according to a
2003 May 28
3
Slow computation in for loop
Dear members, I'm using R to do some test computation on a set of parameters of a function. This function is included in three for() loops, first one for replications, and the remaining two cycling through possible parameters values, like this : for (k in replicates) { data <- sampling from a population for (i in param1) { for (j in param2) { result <- function(i,
2002 Jun 19
4
drawing ellipses
Hello again, First I want to thank all the people who answered my question about line width in graphs. I promise I will learn the 'par' help page by heart for the end of the month ! I now want to trace some ellipses to emphasize groups of data. I found how to trace circles with 'symbols()', but no ellipse. I'm planning on writing my own function based on
2005 Jan 21
2
Selecting a subplot of pairs
Hello, I'm trying to plot a set of 3 dependant variables (y) against 4 predictors (x) in a matrix-like plot, sharing x- an y-axis for all the plot on the same column/line : y1/x1 y1/x2 y1/x3 y1/x4 y2/x1 y2/x2 y2/x3 y2/x4 y3/x1 y3/x2 y3/x3 y3/x4 In fact, this plot is a rectangular selection of the result of pairs(), limited to the relations between x's and y's
2005 Jan 10
3
Mixing portrait/landscape in a postscript file
Dear list, I'm stuck with a little graphical problem. I'm generating several lattice plots which are printed in a single postcript device opened by > trellis.device(postscript, theme=canonical.theme("postscript", color=F), file="an_phase2_graph.ps", paper="a4", pointsize = 10, onefile=TRUE, horizontal=TRUE) Everything works fine,but some of these
2001 Nov 20
0
Formulating anova for partially nested model
Hello, I'm trying to analyse data from an incomplete design with four factor : - fr : number of the batch - op : ID of operator - meth : method used - mat : nature of the material used and one variable - mv : mesure - trmv : transformed mesure str(matvol) `data.frame': 120 obs. of 6 variables: $ fr : Factor w/ 30 levels "1","2","3","4",..:
2011 Jan 16
3
rootogram for normal distributions
Using R-2.12.1 and latticeExtra-0.6-14, I would like to understand why a rootogram displaying samples from the Poisson distribution looks like I expected it, whereas a rootogram using the normal distribution does not: library(latticeExtra) rootogram(~rpois(1000, lambda = 50), dfun = function(x) dpois(x, lambda = 50)) rootogram(~rnorm(1000), dfun = function(x) dnorm(x,mean(x),sd(x))) I
1999 Aug 26
1
error bars on barplots
Hello again I'm trying to put error bars onto a barplot. I've tried something that Bill Simpson suggested a while ago, ie: x<-c(1,2,3,4,5) y<-c(1.1, 2.3, 3.0, 3.9, 5.1) ucl<-c(1.3, 2.4, 3.5, 4.1, 5.3) lcl<-c(.9, 1.8, 2.7, 3.8, 5.0) plot(x,y, ylim=range(c(lcl,ucl))) arrows(x,ucl,x,lcl,length=.05,angle=90,code=3) #or segments(x,ucl,x,lcl) but I can't get it to work on a
2009 Nov 06
2
Binning of integers with hist() function odd results (PR#14046)
Full_Name: Gerald Guglielmo Version: 2.8.1 (2008-12-22) OS: OSX Leopard Submission from: (NULL) (131.225.103.35) When I attempt to use the hist() function to bin integers the behavior seems very odd as the bin boundary seems inconsistent across the various bins. For some bins the upper boundary includes the next integer value, while in others it does not. If I add 0.1 to every value, then the
2011 Aug 23
1
histogram with mean for every break
Dear R-users, I need to produce a histogram where for every breaks there are the mean of the data. I tried tu use the function >hist(x, break=20 ... ) but this return the numerosity for every breaks, not the mean. Any hint? Thanks in advance, francesco --------------------------------------- Francesco Nutini CNR-IREA Ist. per il Rilevamento Elettromagnetico dell'Ambiente Via
2011 Jul 29
3
Problems with ks.test()
Hi, I got two data point vectors. Now I want to make a ks.test(). I you print both vectors you will see, that they fit pretty fine. Here is a picture: http://www.jochen-bauer.net/downloads/kstest-r-help-list-plot.png As you can see there is one histogram and moreover there is the gumbel density function plotted. Now I took to bin-mids and the bin-height for vector1 and computed the
2007 Sep 17
3
Histogram with colors
Is there a simple way to plot a histogram with colors? For example, suppose I generate random points in the N(2,1) distribution: x <- rnorm(100000, mean = 2, sd = 1) Now I would like to plot the histogram: hist(x) but I would like to show the bars with x < 0 in red, and the bars with x >= 0 in lightgreen. Is there any simple way to do it? I think I can do it in two steps: