similar to: problem formatting data frames

Dear R-guRus: I have 2 questions 1) I have 2 variables, e.g. x<-5; y<-"Char" How do I create a new variable which would have both these values in a string (e.g. "5Char", or "5 Char", etc ) ?? 2) if i have an array x[1:100], and I do x[x==345.123], how do I get position j in the array of those x[j] which are equal to 345.123 ? Thank you very much, Vlad.

In a .Rnw file I want to insert the R command pairs(mydataframe) and achieve the following effects 1. the command itseld is echoed into the tex document generated by Sweave <<fig=TRUE,echo=TRUE>>= 2. The graphics generated appears in the tex document, with the graphics centred. 3. The R command > pairs(mydataframe) is not centered. Sweave-manual.pdf gives the following code chunk

Dear R-gurus: How do I overlay 2 plots in the same frame in R? Or, if I have a histogram, and I want to plot a function in the same frame - how do I do it? Thank you very much, Vlad -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or

Hello, I would like to know if this behaviour in R is as expected. I have a data frame 'dat' with column var1 being character (and not factor). Then I create a new column 'var2' by: > dat[,"var2"] <- dat$var1; Column var2 is now a factor. But if I do: > dat$var2 <- dat$var1; Then column var2 is character (and not factor). I don't want to have

My samba4.11 server will only replicate one way: windows -> samba. Replication from samba -> windows fails. Details follow. I have a Samba 4.11 domain controller (fs1) that was added to an existing domain that had a Windows Server 2003R2 domain controller (fs) and Windows Small Business Server 2011 (sbs). fs1 is running on Debian 7.6 My issues seems similar to

Dear R-guRus: I would like to pass variables to a function in R in "by reference", e.g Fortran style. For example, suppose I have the following code x<-c(1:10) y<-1 MyFunc<-function(x,y) {y<-sum(x); return(NULL)} MyFunc(x,y) print(y) in this case print(y) will produce "1" instead of 55 (which is sum(x)) - how do I make sure that afte the function is run, y

Dear R-guRus: I would like to pass variables to a function in R in "by reference", e.g Fortran style. For example, suppose I have the following code x<-c(1:10) y<-1 MyFunc<-function(x,y) {y<-sum(x); return(NULL)} MyFunc(x,y) print(y) in this case print(y) will produce "1" instead of 55 (which is sum(x)) - how do I make sure that afte the function is run, y

Listers, I have a question regarding correlation matrices. It is fairly straight forward to build a correlation matrix of an entire data frame. I simply use the command cor(MyDataFrame). However, what I would like to do is construct a smaller correlation matrix using just three of the variable out of my data set. When I run this: cor(MyDataFrame$variable1,

Dear R-guRus: I am stuck with the following problem in R: Let's say i have a data.frame with columns X,Y & Z. X is a column of numbers, Y is a column of N factors "A", "B", "C", "D", etc and Z is a column of n factors "a", "b", "c", etc if i do MyLm<-lm(X~Y*Z - 1) i get all N coefficients for Y-factors, but only

I'm having trouble using split on a very large data-set with ~1400 levels of the factor to be split. Unfortunately, I can't reproduce it with the simple self-contained example below. As you can see, splitting the artificial dataframe of size ~13MB results in a split dataframe of ~ 144MB, with an increase memory allocation of ~10 fold for the split object. If split scales linearly, then my

Hi All, I'm looking for ways to compute aggregate statistics (with the aggregate function) but with an option for sorting and selecting a subset of the data frame. For example, I have would like to turn this : aggregate(myDataframe$TargetValue,list(SomeFactor = myDataframe$SomeFactor),mean) into something like aggregate(myDataframe$TargetValue,list(SomeFactor =

Hi guys, here is a list of names that I have: MyList: > myList<-list("A", "B","C","D") > myList [[1]] [1] "A" [[2]] [1] "B" [[3]] [1] "C" [[4]] [1] "D" I want to turn this list into a matrix of 1 row and 4 columns with those four components (A, B, C, D) so here is what I do: myDataFrame <-

Dear r-help members I posted this message already yesterday, but don't know whether it reached you since I joined the group only yesterday. I would like to estimate the boxcox transformed model (y^t - 1)/t ~ b0 + b1 * x. Unfortunately, R returns with an error message when I try to perform this with the call nls( I((y^t - 1)/t) ~ I(b0 + b1*x), start = c(t=1,b0=0,b1=0), data = mydataframe)

Hi, Sorry to bother, but I checked around and did not succed creating a bundle from six existing packages (which are checkable, installable, etc. individually). I carefully followed the procedure given in ch. 1.1.5 Package bundles. However, I am getting hoffmann at fluke:~/R/Sources >R CMD check cwhmisc * checking for working latex ... OK * using log directory

I am new to R and have tried for a good while to figure out how to code this in R. The dataset below: FTIStandKey State County FTITract CoverType Ver_CT V_Origin V_SpGrp NAH6005-001 Texas Jasper NAH6005 PPLB-2000-U PPLB-2000-U P P NAH6005-002 Texas Jasper NAH6005 NHHX-1950-O NHHX-1950-I N H NAH6253-001 Texas Tyler NAH6253 PPLB-2001-U PPLB-2001-U P P

Hello, I have RNAseq data, which I am trying to analyze with DESeq. My file (tab delimited .txt) appears to be correct: >head(myfile) VZ_w13 VZ_w14a VZ_w14b VZ_w15a VZ_w15b VZ_w16a ENSG00000253101 0 0 0 0 0 0 ENSG00000223972 0 0 0 0 0 0... However, when I try to analyze the data with >cds <-

Dear people, I am including an example of a dataframe: mydataframe<-data.frame(X=c(1:4),total_bill=c(16.99,10.34,21.01,23.68),tip=c(1.01,1.66,3.50,3.31),sex=c("Male","Male","Male","Female")) When I use the sapply function getting the information about the factors works: sapply(mydataframe,function(x)is.factor(x)) X total_bill tip

I'm trying to bootstrap resample from a repeated measures dataset. I sample a vector of "ID"'s from my dataframe with replacement. Then I merge this back with my dataframe. I'm re-sampling subjects in the dataset rather than rows of the data. I thought I could use the left/right join features of the merge to select the records I want from the dataframe (mydataframe), like

hello R-Users, I have this simple but not for me question: I do: > res<-dbSendQuery(con, "SELECT * FROM tabellaProva") > myDataFrame<-fetch(res) > myDataMatrix<-as.matrix(myDataFrame[,-1]) > namerows(myDataMatrix)<-as.character(myDataFrame[,1]) and I have: io tu io "0" "1" tu "1" "0" my problem is that the

Dear r-users! I would like to cross two data frame which have the same row number but different in the number of column. Can anybody help me for this case ? Thanks a lot in advance -------------------------------------------------------------------------------- Majid Iravani PhD Student Swiss Federal Research Institute WSL Research Group of Vegetation Ecology Z?rcherstrasse 111