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Displaying 20 results from an estimated 3000 matches similar to: "replacing text"

2009 Aug 23
0
[LLVMdev] x86_64 darwin multilib gfortran testresults
Using the proposed patch for enabling the i386 multilib under the x86_64-apple-darwin build... http://lists.cs.uiuc.edu/pipermail/llvmdev/2009-August/025040.html the following gfortran testsuite results are obtained... Native configuration is x86_64-apple-darwin10 === gfortran tests === Running target unix/-m32 FAIL: gfortran.dg/aint_anint_1.f90 -O (internal compiler error) FAIL:
2009 Jan 19
2
[LLVMdev] llvm-gfortran test results
The current llvm/llvm-gcc4.2 svn is now fixed with respect to the extra warnings that were being emitted by the gfortran compiler. The gfortran testsuite results under Intel Darwin9 are appended below. Jack Native configuration is i686-apple-darwin9 === gfortran tests === Running target unix/-m32 FAIL: gfortran.dg/aint_anint_1.f90 -O (internal compiler error) FAIL:
2008 Nov 02
1
[LLVMdev] llvm-2.4 prerelease gfortran results
Building the prerelease of llvm-gcc 2.4 on Intel darwin9 with the following patch... --- llvm-gcc-4.2-2.3.999-20081024.source/gcc/stub-c.c.org 2008-10-30 18:55:45.000000000 -0400 +++ llvm-gcc-4.2-2.3.999-20081024.source/gcc/stub-c.c 2008-10-30 18:57:29.000000000 -0400 @@ -157,3 +157,27 @@ { gcc_assert(0); } + + +bool cvt_utf8_utf16 (const unsigned char *, size_t, unsigned char **, +
2008 Jun 09
1
Cross-validation in R
Folks; I am having a problem with the cv.glm and would appreciate someone shedding some light here. It seems obvious but I cannot get it. I did read the manual, but I could not get more insight. This is a database containing 3363 records and I am trying a cross-validation to understand the process. When using the cv.glm, code below, I get mean of perr1 of 0.2336 and SD of 0.000139. When using a
2012 Dec 11
1
Rprof causing R to crash
I'm trying to use Rprof() to identify bottlenecks and speed up a particullary slow section of code which reads in a portion of a tif file and compares each of the values to values of predictors used for model fitting. I've written up an example that anyone can run. Generally temp would be a section of a tif read into a data.frame and used later for other processing. The first portion
2013 May 27
0
choose the lines
Hi, Try this: dat1<- read.csv("dat7.csv",header=TRUE,stringsAsFactors=FALSE,sep="\t") dat.bru<- dat1[!is.na(dat1$evnmt_brutal),] fun1<- function(dat){??? ? ??? lst1<- split(dat,dat$patient_id) ??? lst2<- lapply(lst1,function(x) x[cumsum(x$evnmt_brutal==0)>0,]) ??? lst3<- lapply(lst2,function(x) x[!(all(x$evnmt_brutal==1)|all(x$evnmt_brutal==0)),]) ???
1999 Sep 02
1
count of factors
Hello, I was used to count how many times every factor is found the following way : (assuming 'vect' is a vector of factors) tapply(vect,vect,length) but recently I experienced weird results with this In fact, my command line was tapply(ORGMORE[[1]][vect],ORGMORE[[1]][vect],length) where - 'vect' is a vector of indices - 'ORGMORE[[1]]' is a slightly long vector of
2018 May 06
1
adding overall constraint in optim()
Hi Michael, A few comments 1. To add the constraint sum(wgt.vect=1) you would use the method of Lagrange multipliers. What this means is that in addition to the w_i (the components of the weight variables) you would add an additional variable, call it lambda. Then you would modify your optim.fun() function to add the term lambda * (sum(wgt.vect - 1) 2. Are you sure that you have defined
2018 May 03
0
adding overall constraint in optim()
You can't -- at least as I read the docs for ?optim (but I'm pretty ignorant about this, so maybe there's a way to tweak it so you can). See here: https://cran.r-project.org/web/views/Optimization.html for other R optimization capabilities. Also, given your credentials, the r-sig-finance list might be a better place for you to post your query. Cheers, Bert Bert Gunter
2008 Jun 10
1
[LLVMdev] llvm-gcc4.2-2.3 gfortran failures
Building llvm 2.3 and llvm-gcc4.2-2.3 on Mac OS X 10.5, I am seeing the following failures remaining in the gcc 4.2.1 gfortran testsuite... LAST_UPDATED: Native configuration is i686-apple-darwin9 === gfortran tests === Running target unix FAIL: gfortran.dg/actual_array_constructor_1.f90 -O1 execution test FAIL: gfortran.dg/actual_array_constructor_1.f90 -O2 execution test FAIL:
2018 May 03
4
adding overall constraint in optim()
Hi ? This is giving me a headache. I?m trying to do a relatively simple optimization ? actually trying to approximate the output from the Excel Solver function but at roughly 1000x the speed. ? The optimization parameters look like this. The only trouble is that I want to add a constraint that sum(wgt.vect)=1, and I can?t figure out how to do that in optim. Mo.vect <-
2001 Feb 19
0
[PATCH]: Broken scp -p option
Hi, I have found an serious problem when using 'scp -rp'. The usage of the static buffer "namebuf" together with calling `sink()' recursively results in overwriting the buffer np points to. This in turn results in a broken call to `ulimits()' and `chmod'. This patch solves the problem: Index: scp.c ===================================================================
2018 May 25
1
MSP430: interrupt vector number out of bounds error in v6/trunk (with patch)
When building with Clang for the MSP430 architecture against headers distributed with TI MSP GCC, interrupt service routine interrupt(vector_number) attribute is rejected: __attribute__ ((interrupt(USCI_A0_VECTOR))) void ISR(void) { } error: 'interrupt' attribute parameter 48 is out of bounds This is due to the check in tools/clang/lib/Sema/SemaDeclAttr.cpp:5104 unsigned Num
2006 Sep 04
3
Subsetting vectors based on condition
Hello, I have a question regarding subsetting of vectors. Here's an example of what I'm trying to do: vect.1 <- c(76,195, 290, 380) vect.2 <- c(63, 95, 133, 170, 215, 253, 285, 299, 325, 375) I would like to subset vect.2 so that it has the same length as vect.1, and its numbers are the first corresponging higher value compared to vect.1. The output should be: final.output =
2018 May 04
0
adding overall constraint in optim()
On Thu, May 3, 2018 at 2:03 PM, Michael Ashton <m.ashton at enduringinvestments.com> wrote: > Thanks Bert. But everyone on that forum wants to use finance tools rather than general optimization stuff! And I am not optimizing a traditional Markowitz mean-variance problem. Plus, smarter people here. :-) > I'm very confused by these statements. Most of the "finance tools"
2007 May 30
0
manova permutations and pair-wise contrasts
Hi, I have a function for doing permutation tests for Manovas, written with the help of folks here on the list. It seems to work ok, and I've found that there is indeed a significant difference among groups in my analysis. I want to follow up on this by testing for which pairs of groups are significantly different. Reasoning that since Wilks Lambda is a generalization of the Hotelling T test,
2018 May 03
2
adding overall constraint in optim()
Thanks Bert. But everyone on that forum wants to use finance tools rather than general optimization stuff! And I am not optimizing a traditional Markowitz mean-variance problem. Plus, smarter people here. :-) > On May 3, 2018, at 3:01 PM, Bert Gunter <bgunter.4567 at gmail.com> wrote: > > You can't -- at least as I read the docs for ?optim (but I'm pretty > ignorant
2013 Jun 04
0
choose the lines2
Hi, May be this helps: dat1<- read.csv("dat7.csv",header=TRUE,stringsAsFactors=FALSE,sep="\t") dat.bru<- dat1[!is.na(dat1$evnmt_brutal),] fun2<- function(dat){?? ????? lst1<- split(dat,dat$patient_id) ??? lst2<- lapply(lst1,function(x) x[cumsum(x$evnmt_brutal==0)>0,]) ??? lst3<- lapply(lst2,function(x) x[!(all(x$evnmt_brutal==1)|all(x$evnmt_brutal==0)),])
2003 Nov 14
7
Vector indices and minus sign
Hi, I got caught out by this behaviour in 1.8.0 and I wondered why this happens: I have a list of vectors and was using lapply and grep to remove matched elements that occur in only a subset of the elements of the list: locs <- lapply(locs, function(x){x[- grep("^x", x)]}) The problem is that where the grep finds no matches and hence returns a vector of length 0, all the
2009 Aug 04
2
can a key of a list be a variable
Hi, I search a solution to record data in dynamic structures in R. I have an algorithm that will be executed each step and whose output is an array of doubles with unknown size. The solution I found is to use lists 1) I initialise my list l <- list() 2) and at a step numbered i I conacatain the new tab to the list vect <- algorithm() l <<--c( l , list(stepi=vect)) The problem is