similar to: Adding text to a plot

Hello, I have a csv-file which looks like: #### pwt6_r.csv #### code;year;rgdpch AGO;1998;1234 ALB;1998;3576 ARG;1998;#NA SVN;1996;13439 SWE;1996;21492 AGO;1960;#NA ALB;1960;2345 ARG;1960;4634 #### pwt6_r.csv #### To import this file i call: pwt6<-read.csv("d:/pwt6_r.csv",header=T,na.strings="#NA",sep=";") Now I want to generate a new data.frame which include

Hello, I am sure this is a trivial question, but I don't get it... Having a dataframe (b.70) like that: > b.70[1:4,2:3] ARG AUS 1960 19041 25949 1961 19675 25451 1962 19302 26463 1963 18121 27644 Now I want to calculate the log for each year and save the result in a new dataframe called 'x'. x<- data.frame(w=NULL) for(i in 1:3)

Hello, I would like to switch this dataframe: > k country 1960 1961 1962 1963 99 ARG 7493 7733 7581 7108 246 AUS 10484 10342 10809 11357 295 AUT 7438 7808 7938 8212 393 BDI 587 502 555 608 442 BEL 8223 8638 9021 9311 in this structure: year ARG AUS AUT BDI BEL 1960 7493 10484 7438 587 8223 1961 7733 10342 7808 502 8638 1962 7581 10809 7938 555

Dear list, I've got some more question. # Number 1: If I run this: #---------------------------- Per.Start <- c(1950,1973) Per.End <- c(1973,2001) for(i in 1:2) { age <- Per.End-Per.Start } age #---------------------------- I'm getting: [1] 23 28 But I want to save the result in two different variables. Something like this: #----DON'T WORK------------- Per.Start

Hi, i'm a newbie with latex and postscript but recognize the power in combination wit R . ...current i don't now how i have to "inform" R1.5.0(patched) about my MikeTex installation on windows 2000 and get following latex(table) Warning messages: 1: cat not found 2: cd not found 3: xdvi not found P.S. maybe i must define in Rprofile something ??? Thanks for help and

Hi there, I have a data.frame (pwt6) which I would like to transform: country year gdp MEX 1950 2 MEX 1951 5 BOL 1950 4 BOL 1951 12 ITA 1950 45 ITA 1951 2 This should be the result: year MEX.gdp BOL.gdp ITA.gdp 1950 2 4 45 1951 5 12 2 Right now I have this code (better - no code): country.label<-names(table(pwt6$country)) result<-data.frame(year=NULL) for(i in country.label) ?

Hi, I want to read some Times Series of GDP from OECD-Countrys. First I call: > oecd96<-ts(read.csv("oecd96.csv",header=T,sep=";"),start=1950,freq=1) > summary(oecd96) gdpcausb gdpcautb gdpcbelb gdpccanb Min. : 8567 Min. : 4533 Min. : 6616 Min. : 8966 1st Qu.:10771 1st Qu.: 8717 1st Qu.: 9440 1st Qu.:11694 Median

Hello everyone! If this message was posted twice, my apologies. I'm having issues with my webmail today... I am using the testing version of NUT from SVN at changeset 582. I have successfully created a stub for newhidups driver for my Dynex DX-800U UPS, but I am completely lost on the customization of it. I've followed the hid-subdrivers.txt instructions and I understand I need to

Hello, Is there an option I can easily set to put labels next to the points in a simple plot? The closest I got to it was to use the option pch, but this replaces the point symbol with the character specified, and it is not what I want. Thanks -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read

Is it possible to konfigure a passwordless authentifikation in kombination with ssh. for example: to a specific folder on a server named server1 has only user1 access. the user1 only exists on server1. server2 wants to replicate a foler from server1 to himself. the rsync process uses the rsync_user, which exists on both machines. the rsync process asks every time the job runs for the password

I have a question regarding a thread in June called "Distinct transactions", which I have included below. It seems to me that the solution is not atomic for daemons opening the file as there is a moment where the filename is not in the directory (i.e. unlink then link). In summary, poster Charlie Woloszynski wanted to update a configuration file in a safe manner (i.e. as a

Hello together i want to execute different commands that are saved in strings (eg: "d <- 4+7" and some more complicated things). How can i execute/evaluate them. I know i could save them to a temp-file a read this with source. But is there a way without a file in the middle? I know also the 'assign' command but I think it would only the simply cases. thanks and gruess joerg

Hi all This seems like a very easy question, but I have not found a simple answer to it: If you have a dataframe, how to you plot two of then in different colors depending on a third variable? All help appreciated! /Fredrik -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send

Dear All! my data is on pairs of countries, i and j, e.g.: y,i,j 1,AUT,BEL 2,AUT,GER 3,BEL,GER I would like to create a dummy (indicator) variable for use in regression (using factor?), such that it takes the value of 1 if the country is in the pair (i.e. EITHER an i-country OR an j-country). Thank you for your help, Serguei ________________________________________ Austrian Institute of

Hello everybody, a question that connect to the question of Frederik Karlsons about 'how to stand. betas' With the stand. betas i can compare the influence of the different explaning variables. What do i with the betas of factors? I can't use the solution of JohnFox, because there is no sd of an factor. How can i compare the influence of the factor with the influence of the numeric

Hi there, i got into some trouble after updating my samba installation to 3.0.27a. My installation uses Samba-3.0.27a,OpenLDAP-2.2.13,smbldap-tools-0.9.2 as a PDC NT4-domain.Originally I used the installation-guide from smbldap-tools and everything worked fine. I also limited the access to LDAP as told in the installation-guide with no problems. After updating to 3.0.27a i realized that when

Hello All, I have a panel date - here a small-scale example: df <- data.frame(cbind(rep(c("AUT","BEL","DEN","GER"),4),cbind(rep(c(1999,2000,2001,2002),4)),sample(10,16,replace=T))) names(df) <- c("country","year","x") SORT <- c("GER","BEL","DEN","AUT") I need to compute the

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 I have a stock market trading values time series. What's the best way to extract the "last day of month" values. I looked at function window() but doesn't appear suitable for this since it expects regular dates. Thank you. lukas - -- Lukas Kubin lukas.kubin at permonik.com phone: 00420603836180 -----BEGIN PGP SIGNATURE-----

Dear list, # I have a DF like this: sleep$b <- c(rep(8,10), rep(9,10)) sleep$me <- with(sleep, ave(extra, group, FUN = mean)) sleep # I would like to create a new variable # holding the b-th value of group 1 and 2. # This is not what I want, it takes always the '8' from group '1' # and not the '9' sleep$gr <- with(sleep, ave(extra, group, FUN = function(x)

How can locate in my program an error of that kind (Error: subscript out of bounds)? -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch