similar to: Use of nls command

Displaying 20 results from an estimated 300 matches similar to: "Use of nls command"

2011 Oct 29
0
[LLVMdev] [llvm-commits] [PATCH] BasicBlock Autovectorization Pass
On Sat, 2011-10-29 at 15:16 -0500, Hal Finkel wrote: > On Sat, 2011-10-29 at 14:02 -0500, Hal Finkel wrote: > > On Sat, 2011-10-29 at 12:30 -0500, Hal Finkel wrote: > > > Ralf, et al., > > > > > > Attached is the latest version of my autovectorization patch. llvmdev > > > has been CC'd (as had been suggested to me); this e-mail contains > >
2011 Oct 29
4
[LLVMdev] [llvm-commits] [PATCH] BasicBlock Autovectorization Pass
On Sat, 2011-10-29 at 14:02 -0500, Hal Finkel wrote: > On Sat, 2011-10-29 at 12:30 -0500, Hal Finkel wrote: > > Ralf, et al., > > > > Attached is the latest version of my autovectorization patch. llvmdev > > has been CC'd (as had been suggested to me); this e-mail contains > > additional benchmark results. > > > > First, these are preliminary
2012 Dec 16
3
how to handle NA values in aggregate()
Dear All: I am trying to calculate four columns' means in a dataframe like this: FID MID IID EW_INCU EW_17.5 EMW EEratio 1 4621 TWF2H5 45.26 NA 15.61 NA 1 4621 TWF2H6 48.02 44.09 13.41 0.3041506 2 4630 TWF2H19 51.44 47.81 NA NA 2 4631 TWF2H21 NA 52.72 16.70
2011 Oct 29
4
[LLVMdev] [llvm-commits] [PATCH] BasicBlock Autovectorization Pass
Ralf, et al., Attached is the latest version of my autovectorization patch. llvmdev has been CC'd (as had been suggested to me); this e-mail contains additional benchmark results. First, these are preliminary results because I did not do the things necessary to make them real (explicitly quiet the machine, bind the processes to one cpu, etc.). But they should be good enough for discussion.
2011 Oct 29
0
[LLVMdev] [llvm-commits] [PATCH] BasicBlock Autovectorization Pass
On Sat, 2011-10-29 at 12:30 -0500, Hal Finkel wrote: > Ralf, et al., > > Attached is the latest version of my autovectorization patch. llvmdev > has been CC'd (as had been suggested to me); this e-mail contains > additional benchmark results. > > First, these are preliminary results because I did not do the things > necessary to make them real (explicitly quiet the
2012 Dec 15
2
troubles reading a text file
Dear R experts, For quite some time I have been trying to solve a mistery of reading a seemingly trouble-free text file. The data is temperature reconstruction arranged as a huge grid, preceded by seven "header lines" (which you see better if file is opened in Firefox or Chrome). This is the data (gridded temperature reconstruction)
2010 Aug 18
3
How to read ANOVA output
Hi folks, Where can I find document re "how to read anova output"? Google found many of them. But seemingly non of them can explain to me following output:- > tabA = c(5.67, 5.67, 5.55, 5.57) > tabB = c(5.75, 5.47, 5.43, 5.45) > tabC = c(4.74, 4.45, 4.65, 4.94) > tabs = data.frame(tabA, tabB, tabC) > tablets = stack(tabs) > anova(lm(values ~ ind, data =
1998 Apr 07
3
R-beta: spline problems(?)
Hi, I am a total beginner with this whole thing so please have patience! I am trying to run an S-plus program with a certain line: spline(1:nrow(y), y[,1],n=100); This crashes with: Error: NAs in foreign function call (arg 8) Apparently, this is caused by the last command of spline: u <- seq(xmin, xmax, length.out = n) .C("spline_eval", z$method, length(u), x = u, y =
2008 May 29
1
plotting zoo using datetime as xlim
is there a way to use the actual index value for plotting zoo objects this is the way that the index is set up and a sample range of what I would like to plot 01/01/06 00:00:00 - 01/01/06 23:45:00 { library(zoo) # chron library(chron) fmt.chron <- function(x) { chron(sub(" .*", "", x), gsub(".* (.*)", "\\1:00", x)) }} x <- structure(c(15.57, 15.5,
2012 Nov 19
6
loop to subtract arrays / error
Hi everyone, I am having trouble with creating a loop to subtract arrays. In R, this is what I have done: > Vobsr <- read.csv("Observed_Flow.csv", header = TRUE, sep =",") # see data > below > Vsimr <- read.csv("1000Samples_Vsim.csv", header = TRUE, sep =",") # see > data below > Vobsr <- as.matrix(Vobsr[,-1]) # remove column 1 from
2003 Jan 22
1
Intercept in model formulae
Hi, I'm a new user of R and I'm trying to make a linear model from this kind of dataset x [1] 16.87 19.93 25.85 20.94 17.06 19.49 19.93 25.45 27.74 20.15 25.81 21.06 17.17 20.03 25.50 27.79 20.44 16.88 19.93 25.79 z<-x-10 y [1] 0.80 1.27 2.22 1.32 0.90 1.18 1.84 2.41 2.97 1.25 2.07 1.41 1.14 1.66 2.59 3.51 1.53 0.81 1.26 2.30 plot(x,y) I want to be able to force the line of
2014 Sep 01
1
Correlation Matrix with a Covariate
R Help - I'm trying to run a correlation matrix with a covariate of "age" and will at some point will also want to covary other variables concurrently. I'm using the "psych" package and have tried other methods such as writing a loop to extract semi-partial correlations, but it does not seem to be working. How can I accomplish this? library(psych) > set.cor(y =
2009 Aug 13
3
shading between two smoothed curves
I have a set of 52 weekly values, one is the desired high lake stage for a week, and the other is the desired low lake stage for each week. It looks like this: week High Low 1 16 14.5 2 16 14.5 3 15.95 14.45 4 15.84 14.34 5 15.73 14.23 6 15.61 14.11 7 15.5 14 8 15.38 13.88 9 15.25 13.75 10 15.13 13.63 .... 52 15 13.5 I can plot out two nice curves
2004 Jul 18
2
bootstrap and nls
Hi, I am trying to bootstrap the difference between each parameters among two non linear regression (distributed loss model) as following: # data.frame > Raies[1:10,] Tps SolA Solb 1 0 32.97 35.92 2 0 32.01 31.35 3 1 21.73 22.03 4 1 23.73 18.53 5 2 19.68 18.28 6 2 18.56 16.79 7 3 18.79 15.61 8 3 17.60 13.43 9 4 14.83 12.76 10 4 17.33 14.91 etc... # non
2007 Dec 08
0
help for segmented package
Hi, I am trying to find m breakpoints of a linear regression model. I used the segmented package. It works fine for small number of predicators and breakpoints.(3 r.v. 3 points). However, my model has 14 variables it even would not work even for just one breakpoints!. The error message is always estimated breakpoints are out of range. Since my problem is time related problem. So I
2013 Aug 26
2
Partial correlation test
Dear all, I'm writing my manuscript to publish after analysis my final data with ANOVA, ANCOVA, MANCOVA. In a section of my result, I did correlation of my data (2 categirical factors with 2 levels: Quantity & Quality; 2 dependent var: Irid.area & Casa.PC1, and 1 co-var: SL). But as some traits (here Irid.area) are significantly influenced by the covariate (standard length, SL), I
2010 Apr 22
1
Odd behavior
Hi Y'all, I'm seeing some interesting behavior that I was hoping someone could shed some light on. Basically I'm trying to rsync a lot of files, in a series of about 60 rsyncs, from one server to another. There are about 160 million files. I'm running 3 rsyncs concurrently to increase the speed, and as each one finishes, another starts, until all 60 are done. The machine
2010 Jan 04
1
log-normal overlay
Hello, Using the following lines of code, I created the following graph:
2010 Jan 04
1
log normal overlay
Hello, Using the following lines of code, I created the following graph:
2004 Feb 16
0
error in nls, step factor reduced below minFactor
Hello, I am trying to estimate 4 parameters of a non-linear model using nls. My model function is a Fourier integral and is very expensive to calculate. I get the following error: > theta0 <- c(0.045, 1.02*10^(-4), 0.00169, 5.67*10^(-4)) > res <- nls(log(y) ~ log(model(theta,r,t)), data=dataModel, + start=list(theta=theta0), trace=TRUE, + control=nls.control(tol=1e-2))