similar to: chron problem: extracting days and years

Displaying 20 results from an estimated 7000 matches similar to: "chron problem: extracting days and years"

2011 May 30
1
CLI command 'database deltree' doesn't remove family with space in its name
While playing with DB function in Dialplan, I have added some garbage in AstDB. These are some family names with space in them. See this, demo*CLI> database show /18-05-2011 00:00:0052011175221575/TESTDATE : 2011-05-14 21:33:46 /18-05-2011 00:00:0052011175221575/TEST1 : 410 /18-05-2011 00:00:0052011175221575/TEST2 : 155 /18-05-2011 00:00:0052011182614252/TEST3 :
2006 Aug 11
1
more on date conversion differences in 2.2.1 vs 2.3.1
With dates I get different results with 2.2.1 and 2.3.1. From my somewhat naive point point of view, the 2.2.1 behaviour seems more sensible. Running the code below in 2.2.1: V1 2006-08-01 2006-08-01 1 1 With 2.3.1 I get: V1 1154354400 1154440800 1 1 # testdate.R t <- read.csv2('testdate.csv', header=FALSE) t$V1 <- as.POSIXct(t$V1)
2008 Jul 24
2
Can R fill in missing values?
Hi, I know this can be done in Stata (which is quite messy) but I wanted to know if it can be done in R. So lets say I have a merged data set (I used the merge function by date for the attached two files), where all the missing values are filled with NAs (which is what the all.x=TRUE does). Is there any way to replace those NAs with the value of the latest row that contains a value? For
2008 Mar 03
1
Tapply for Group Specific Means and Proportions
UseRs, I am working on a dataset (see small example below) where individuals were followed on a specific date-time combo and multiple repeated measurements were taken (e.g., height in meters, behavior class in 2 letter code). Observation numbers varied between individual (ranging from 1 observation for each date-time combo to >50) I am trying to summarize the data into 1 row per
2011 May 24
2
Extracting day of month from Date objects
I've always found the chron library to be useful for tasks like this: > x <- round(runif(10)*100000, digits=0) > y <- as.Date(x, origin="1970-01-01") > library(chron) > days(y) [1] 7 25 26 25 10 24 1 31 12 8 31 Levels: 1 < 2 < 3 < 4 < 5 < 6 < 7 < 8 < 9 < 10 < 11 < 12 < 13 < ... < 31 Notice that it returns the days as
2006 Aug 10
2
day, month, year functions
Hi list, I'm trying to turn a date into something productive. (Not what you may be thinking....) I want three functions so I could take a "date" object and get the day of week, month, and year from it. xx <- as.Date("2006-01-05") month(xx) equal 1 day(xx) equal 5 year(xx) equal 2006 I'm aware of the weekdays() and months() functions in the base package. But
2004 Jun 07
7
Vectors of years, months, and days to dates?
The interface for dates in R is a little confusing to me. I want to create a vector of Date objects from vectors of years, months, and days. One solution I found is: years <- c(1991, 1992) months <- c(1, 10) days <- c(1, 2) dates <- as.Date(ISOdate(years, months, days)) But, in this solution the ISOdate function converts the vectors into characters, which can cause serious
2008 Jul 23
2
Can't Load Text Files
Hi, I've completely forgotten how to do R, and it seems I can't even load simple files correctly. I have two tab deliminated text files (attached, these were test files of the larger data files I'm trying to work with) that I am trying to load into R so that I can merge them. They were originally excel files but I used "saved as" to reformat to text. I don't know if
2010 Oct 19
4
Chron object in time series plot
Dear R users, I have the following script to create bins of specified time intervals bin_end=60/bin_size bin_size=bin_size*100 h=seq(070000,180000,by=10000) breaks=c() for (i in h) { for (j in 0:(bin_end-1)) { value=i+(bin_size)*j breaks=append(breaks,value) } } I would like to plot then using the time as x-axis. I tried the following prova=zoo(myseries,times(breaks)) but of
2005 Jul 19
2
Problems with date-format (R 2.1.1 + chron)
Hello, today I've updated on the newest R-Version. But sadly a function I needed didnt want to work: The input is e.g. days(as.Date("21-07-2005","%d-%m-%y")) the error is: Fehler in Math.Date(dts): floor nicht definiert f??r Date Objekte (Error in Math.Date(dts): floor not defined for date objects) Same for year. Only months gives me the correct output. In Version
2001 Aug 20
2
interrupting Sys.sleep (PR#1063)
On Linux R1.3.0 (and current pre1.3.1 and pre1.4.0) Sys.sleep(30) interrupt with CTRL-C Sys.sleep(30) causes a segmentation fault. It doesn't happen under Windows (2000). -thomas -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-devel mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or
2007 Nov 23
1
formatting POSIXlt object as strip labels in lattice plot
Dear list, I'm plotting a lattice plot xyplot(Volume ~ Weight | as.character(DateTime)) where DateTime is a POSIXlt object. This produces strip labels in the format e.g. "2007-11-15 23:15:00" and panels are plotted in the correct order. I'd prefer a format "15 Nov 23:15", but if I use format(DateTime,format="%d %b %H:%M") to do the conversion, then the
2001 Oct 12
2
adding text to persp
Any ideas on adding text to persp plots? The perspp function from S-plus is not implemented. I'm using R1.3.0 on Win2000. Thanks, Sundar -- Sundar Dorai-Raj, Ph.D. Assistant Professor Discrete & Statistical Sciences Office: (334) 844-3647 231 Allison Lab Fax: (334) 844-3611 Auburn University Email: dorairaj at dms.auburn.edu Auburn AL 36849-5307
2001 Aug 19
2
system.file("",package) (PR#1062)
system.file("",package") is documented to return the root of the package (as it did in the past). It actually returns "" (Win98, R1.3.0), breaking the SJava package Omitting the first argument does work correctly and so is a workaround if the argument is explicitly "" but not if it is the value of a variable. -thomas
2004 Mar 01
6
Find out the day of week for a chron object?
I know that this is correct: library(chron) x = dates("01-03-04", format="d-m-y", out.format="day mon year") print(x) It gives me the string "01 Mar 2004" which is correct. I also know that I can say: print(day.of.week(3,1,2004)) in which case he says 1, for today is monday. My question is: How do I combine these two!? :-) I have a
2001 Oct 08
2
Rcmd
Hola! I have problems running Rcmd check (windows 98, R1.3.0) It ckoks on an example running a function which calla bringToTop(). This makes an error because Rcmd check runs the examples with the postscript device, and bringToTop does not make sense with that device. Howevere, my function is for interactive use, and needs bringToTop. How can this be used in examples and still have the
2012 Jun 15
2
time zones and the chron to POSIXct conversion
Hey R folks, i found some strange (to me) behaviour with chron to POSIXct conversion. The two lines of code result in two different results, on ewith the correct time zone, one without: library(chron) as.POSIXct(chron('12/12/2000'), tz = 'UTC') as.POSIXlt(chron('12/12/2000'), tz = 'UTC') Only the code below would give me a POSIXct object with the correct time
2012 Jun 08
3
day of the year for chron objects
Hi! Is not there an standard R function to retrieve the day of the year (since 1st Jan of the same year)? I know I can make my own using julian, but find it weird that having days(), months() etc doy() does not exist as an standard function. Also, is the following not a bit inconsistent? > a <- chron("20100506",format="ymd") > a [1] 100506 > years(a) [1] 2010
2011 Aug 30
3
having trouble extracting week from chron object
Running R 2.13.1 on Windows XP. I would like to get week of the year (1-52) for each date. library(chron) dts <- dates(c("02/27/92", "02/27/92", "01/14/92","02/28/92", "02/01/92")) dts dts.chron <- as.chron(dts) dts.chron class(dts.chron) # all of these component extractions work: months(dts.chron) weekdays(dts.chron) years(dts.chron)
2004 Mar 05
3
as.POSIXct problem
Hi all, I'm having difficulty converting a 'dates' object to a POSIXct object: testDATES<-c(35947,35971,36004,36008,36053,36066) testDATES<-chron(dates=testDATES, format = c(dates = "m/d/y"), origin=c(month = 12, day = 30, year = 1899)) >[1] 06/01/98 06/25/98 07/28/98 08/01/98 09/15/98 09/28/98 > as.POSIXct(testDATES) [1] NA NA NA NA NA NA