similar to: segmentation fault with chron.times()

Displaying 20 results from an estimated 3000 matches similar to: "segmentation fault with chron.times()"

2009 Mar 02
2
R-code help for filtering with for loop
Dear Sir / Madam, I am new for R coding. Kindly help me out in sorting out the following problem. There are 50 rows with six coloumns(you could see in the attached .txt file). I wish to go for filtering this 50 rows for any one of the six coloumns satisfying the value >= 64. I need to have a final table with rows having >= 64 value in any one of the six coloumns and the rest could be
2003 Oct 16
1
princomp with more coloumns than rows: why not?
As of R 1.7.0, princomp no longer accept matrices with more coloumns than rows. I'm curious: Why was this decision made? I work a lot with data where more coloumns than rows is more of a rule than an exception (for instance spectroscopic data). To me, princomp have two advantages above prcomp: 1) It has a predict method, and 2) it has a biplot method. A biplot method shouldn't be too
2011 Feb 08
2
Extrcat selected rows from a list
Hi, I have two lists 1) List1- 30,000 rows and 104 columns 2) List2- a list of 14000 selected rownames  from List 1 Now, I want to extract all the 104 columns of List1  matching with the 14000 selected rownames from List2.  Psedocode will be something like this: match rownames(List2) with rownames(List1) extract selected matched 104 coloumns from (List1) strore in-> List3 So the
2001 Aug 02
1
Package GSS for interpolation in more than 2D?
Dear all, There has been some time since I asked about interpolation in higher (>2) dimensions, and I must admit I failed to write a function to do this myself the last time, but eventually ended up doing it in MATLAB. I tried to translate the MATLAB code, but MATLAB code is so much more opaque than R (S) code, so I failed that too, mainly because I could only get one MATLAB session, I would
2000 Feb 11
1
new chron problems in RW0990
Dear all, In RW0901 I could > dates("01/01/2000") [1] 01/01/100 where only the printing was wrong, but the double numeric representation of the chron object was calculated correctly but now in RW0990 > dates("01/01/2000") Error in fun(yy, ...) : must be 2-digit (numeric) year specification and also the followig doesn't help > dates("01/01/2000",
2005 Sep 16
2
help required on read.table
Hi all i am facing a peculiar problem for data input using read.table which i never faced previously. i have a data file by name abnew.txt with two coloumns data as depicted below. A B 420 422 314 321 the txt file is created using the excel save as option. i issued the statement as > a <- read.table("abnew.txt", header=TRUE) > a X.??S 1 NA 2 2 3 2
2000 Feb 16
1
chron and mysql
R 0.90.1 chron 2.2-2 MySQL 3.22.30 Attempts to create a chron object fail when using date and time data from a mysql database. It appears that chron does not like 4 digit years. Is this the problem? my data look like: > c.time[1:10,] Date Time 1 2000-02-14 10:15:02 2 2000-02-14 10:17:03 3 2000-02-14 10:18:03 4 2000-02-14 10:19:03 5 2000-02-14 10:20:04 6 2000-02-14
2011 Feb 16
2
distance between consecutive points
Dear R users, I have two coloumns of data, say x and y, referring to a list of points in 2D space. I am trying to develop a code that will give me the distances (using Pythagoras) between consecutive points (xi,yi) and (xi+1,yi+1). So far I have come up with the following: for (i in 1:length(x)) d<-sqrt((x[i+1]-x[i])^2+(y[i+1]-y[i])^2) For example, if I use the two points (note, I have
2005 Nov 09
2
how to convert strings back to values?
Dear All, It's Eszter from Hungary, a total beginner with R. My problem is the following: I have a dataset with binary values as a comma separated textfile. The samples are in the coloumns and the species are in the rows. I have to transpose it for the further PCoA analysis. There is no problem with reading the dataset. When I transpose the dataset, the original values become
2010 Feb 16
3
converting character vector "hh:mm" to chron or strptime 24 clock time vectors
Hi All, I am attempting to work with some data from loggers. I have read in a .csv exported from MS Access that already has my dates and times (in 24 clock format), (with StringsAsFactors=FALSE). > head(tdata) LogData date time 1 77.16 2008/04/24 02:00 2 61.78 2008/04/24 04:00 3 75.44 2008/04/24 06:00 4 89.43 2008/04/24
2012 Apr 30
2
Matrix transposition
Hi everyone. I want to transpose a data frame. Lets say the following DF: df = data.frame(matrix(ncol=4, nrow = 10)) df[,1] = c(rep(1,5),rep(2,5)) df[,2] = c(rep('a',4),rep('b',3),rep('c',3)) df[,3] = c(letters[5:14]) df[,4] = runif(10) I would like to form a data frame with each line corresponding to colon X1 and create a variable with columns X2 and X3. This would
2007 Apr 22
1
How to add e.g. lines to a zoo plot?
Hi all, a problem I encounter again and again: I plot a zoo object using "plot" and then want to add lines or points to this plot. I usually circumvent this problem by adding artificial coloumns to the zoo object before plotting, but I am sure there's a better solution. To be specific: Assume I did x <-
2011 Sep 16
1
Mystified - comparing chron times
I have two local variables: startTime and expectedStartTime. Both are chron related objects. When I look at the class for the objects I can see they are of class "times". When I print them to the console, they both read: "09:30:00" When I print them as.numeric(), they both read: 0.3958333 When I try and compare them: (as.numeric(startTime) == as.numeric(expectedStartTime)) it
2005 Mar 11
1
reading in data problems
Hi I have a dataset (.txt file and .dat file) in which the length of one record is 144. There is no header in the .txt or .dat file itself. When I read this file using the read.table command, and want to drop some coloumns by setting the argument colClasses to "NULL" for the columns that I want to drop, it does not work, because the entire record of the length 144 is being treated as
2004 May 12
1
convert.times in chron, error when 59 < seconds < 60 (PR#6878)
Full_Name: Dennis Wolf Version: 1.9.0 OS: Mac OS 10.3.3 Submission from: (NULL) (160.91.76.23) platform powerpc-apple-darwin6.8 arch powerpc os darwin6.8 system powerpc, darwin6.8 status major 1 minor 9.0 year 2004 month 04 day
2006 Jan 19
1
chron library: format.times, parse.format and h:m (PR#8507)
Due to the following lines in parse.format: else if (nf == 3) { sep <- "" fmt <- substring(format, first = 1:3, last = 1:3) } If a format code has 3 characters, it will not use a separator: > library(chron) > mytime = times('7:15:00') > format(mytime,'h:m') [1] "0715" - Phil Spector
2011 Jan 21
4
clustering fuzzy
hello, i'm pete ,how can i order rows of matrix by max to min value? I have a matrix of membership degrees, with 82 (i) rows and K coloumns, K are clusters. I need first and second largest elements of the i-th row. for example 1 0.66 0.04 0.01 0.30 2 0.02 0.89 0.09 0.00 3 0.06 0.92 0.01 0.01 4 0.07 0.71 0.21 0.01 5 0.10 0.85 0.04 0.01 6 0.91 0.04 0.02 0.02 7 0.00 0.01 0.98 0.00 8 0.02
2012 Jun 01
1
Missing times chron
Dear all, As a novice user of R I ran into a problem that's quite hard for me to resolve. I have a database containing data of a clinical trial in which patients are included that survived or died: x <- matrix(data=c(1:5,0, "1/1/2012 00:00:00",0,0,"1/7/2012 00:00:00"), nrow=5, ncol=2, dimnames= list(NULL,c("ID", "dateofdeath"))) My file is a .csv
2010 Jun 29
3
formating chron date times for printing
the date were created with chron with this argument format=c(dates="Y/m/d", times="H:M:S")) so I have the dates being displayed as (10/06/22 12:00:00) I would like to have them displayed as "2010-06-22 12:00:00" or "%Y-%m-%d %H:%M:%S" and then I can convert these for mergeing with another data frame x <- (structure(c(14464, 14464.0104166667,
2006 Jun 23
2
problem with hist() for 'times' objects from 'chron' package
Hello dear useRs and wizaRds, I encountered the following problem using the hist() method for the 'times' classes from package 'chron'. You should be able to recreate it using the code: library(chron) # pasted from chron help file (?chron) dts <- dates(c("02/27/92", "02/27/92", "01/14/92", "02/28/92", "02/01/92")) class(dts)