similar to: Matching rows?

I would like to know which rows are duplicates of each other, not simply that a row is duplicate of another row. In the following example rows 1 and 3 are duplicates. > x <- c(1,3,1) > y <- c(2,4,2) > z <- c(3,4,3) > data <- data.frame(x,y,z) x y z 1 1 2 3 2 3 4 4 3 1 2 3 I can't figure out how to get R to tell me that observation 1 and 3 are the same.

I would like to know which rows are duplicates of each other, not simply that a row is duplicate of another row. In the following example rows 1 and 3 are duplicates. > x <- c(1,3,1) > y <- c(2,4,2) > z <- c(3,4,3) > data <- data.frame(x,y,z) x y z 1 1 2 3 2 3 4 4 3 1 2 3 I can't figure out how to get R to tell me that observation 1 and 3 are the same.

I'm trying to: Resample with replacement pairs of distinct rows from a 120 x 65,000 matrix H of 0's and 1's. For each resampled pair sum the resulting 2 x 65,000 matrix by column: 0 1 0 1 ... + 0 0 1 1 ... _______ = 0 1 1 2 ... For each column accumulate the number of 0's, 1's and 2's over the resamples to obtain a 3 x 65,000 matrix G. For those

Hi, I have a dataset in which I would like to select rows based on matching conditions and return the maximum value of a variable else return one row if duplicate counts exist. My dataset looks like this: PGID PTID Year Visit Count 6755 53121 2009 1 0 6755 53121 2009 2 0 6755 53121 2009 3 0 6755 53122 2008 1 0 6755 53122 2008 2 0 6755 53122 2008 3 1 6755 53122 2009 1 0 6755 53122 2009 2 1 6755

I have a matrix such as this, [,1] [,2] [,3] [1,] 1 1 2 [2,] 2 5 5 and a larger matrix such as this, a b [1,] 1 5 [2,] 2 5 [3,] 4 9 [4,] 5 8 [5,] 7 8 [6,] 7 10 [7,] 9 10 what I want to do is check the number of times the columns in the first matrix appear as rows in the second matrix. So for instance in this example 1,5 and 2,5 appear in both so I'd want

While termplot is under discussion, here's another proposal. I'd like to change the default for partial.resid to TRUE, and for smooth to panel.smooth. I'd be surprised if those changes were to break existing code. John Maindonald email: john.maindonald at anu.edu.au phone : +61 2 (6125)3473 fax : +61 2(6125)5549 Centre for Mathematics & Its Applications, Room

Folks, I have three dataframes storing some information about two currency pairs, as follows: R> a EUR-USD NOK-SEK 1.23 1.33 1.22 1.43 1.26 1.42 1.24 1.50 1.21 1.36 1.26 1.60 1.29 1.44 1.25 1.36 1.27 1.39 1.23 1.48 1.22 1.26 1.24 1.29 1.27 1.57 1.21 1.55 1.23 1.35 1.25 1.41 1.25 1.30 1.23 1.11 1.28 1.37 1.27 1.23 R> b EUR-USD NOK-SEK 1.23 1.22 1.21 1.36 1.28 1.61 1.23 1.34 1.21 1.22

Hi, I have a matrix a = matrix (1:16, 4, 4) b = c (2,3) I want to find out which rows of a, where a[,1] equals any values of b? I know that if b is only one value, e.g, b=2, then what I want is a[a[,1] == 2,] But what about if it is not one value but a vector of values? Thanks much in advance. -- Waverley @ Palo Alto

I found writing the following default method the for the generic function "julian" causes R to crash. julian.default <- function(x, ...) { x <- as.Date(x) NextMethod("julian", x, ...) } Here is a test example > m <- as.Date("1972-09-27") + 0:10 > m [1] "1972-09-27" "1972-09-28" "1972-09-29"

> From: "Alan T. Arnholt" <arnholt at math.appstate.edu> > To: Bill Venables <William.Venables at cmis.CSIRO.AU> > Cc: r-help at stat.math.ethz.ch, arnholt at math.appstate.edu > Subject: Re: [R] Lack of Fit test > Date: Wed, 23 Feb 2000 09:40:21 -0500 (EST) > X-Authentication: none > > > I guess my question was not adequately stated when I sent

This is not so much a bug as an infelicity in the code that can easily be fixed. The initialize expression in the quasi family function is, (uniformly for all links and all variance functions): initialize <- expression({ n <- rep.int(1, nobs) mustart <- y + 0.1 * (y == 0) }) This is inappropriate (and often fails) for variance function "mu(1-mu)".

I see Peter has just announced the release of 1.0.0, on time, even here in Australia, in accordance with a timetable privately announced about 6 months ago. At that time it seemed optimistic to put it mildly. I am not a member of the core team, but as an ordinary user of R with a more privileged inside view than most I'd like to offer my personal congratulations and thanks. This is the

> I think we should get rid of source attributes completely, > since they are no longer needed, but your comment still > applies to source references. We should strip them when code > gets modified. > > Duncan Murdoch I would be very concerned about losing source attributes-- it would break a lot of my code :(! It's very useful to have a single portable R object that

Brian, Thanks for doing this. As the primary author, could I have a desk copy, please? Bill Venables. Bill Venables, CMIS, CSIRO Marine Laboratories, PO Box 120, Cleveland, Qld. 4163 AUSTRALIA Phone: +61 7 3826 7251 Fax: +61 7 3826 7304 Mobile: +61 419 634 642 <mailto: Bill.Venables at csiro.au> http://www.cmis.csiro.au/bill.venables/ -----Original Message----- From: Brian

Dear List-mates, I have been trying to set up a 4x8 trellis plot (that is, 4 columns, 8 rows), and would like to have the axis limits set based on the data range of rows (for ylim) and columns (for xlim). I've been using the call: foo<-xyplot(y~x|Epoch+Subject, type=c("l","r"), par.strip.text=list(cex=0.5), ...) and updating to see different effects of scale

Will the real book "S Programming" please stand up. As I searched for this book both on AMAZON.COM and AMAZON.CO.UK, I found two different versions. On AMAZON.COM my search reveals S Programming (Statistics and Computing) by Brian D. Ripley, William N. Venables. Our Price: $59.95. Availability: Usually ships within 24 hours. Hardcover - 264 pages 1st edition (May 15, 2000) Springer

At 18:26 14/10/00 +0100, Prof Brian D Ripley wrote: >On Sat, 14 Oct 2000, niels Waller wrote: > >> Dear colleagues, >> >> I suspect there is a simple answer to this question -- but I cannot find it. >> >> Suppose I have a list of matrices. I want to pull out an element (such as >> row 1, col 2) from each matrix. Do I need a loop to do this? Or is there

My apologies for he very short time before things close, but it's not my fault. If necessary get your hat in the ring by Friday and see to the niceties later, may I suggest. This is a vacancy in my group in Cleveland. The work is interesting and the challenges large. Bill Venables. ---------------------------------------------------------------------------- Division of Marine Research

Hi all, What would be an efficient way to match rows of a matrix to a vector? ex: m<-matrix(1:9, nrow=3) m [,1] [,2] [,3] [1,] 1 4 7 [2,] 2 5 8 [3,] 3 6 9 ################################# which(m==c(2,5,8)) # I want this to return 2 ###################### Thanks, Sachin [[alternative HTML version deleted]]

I have just become painfully aware that objects of class "difftime", generated by the difference of two POSIXct objects, carry a "units" attribute, which flashes by when the object is printed, for example. The pain was occasioned when I tried to turn these objects into numberic objects for use elsewhere as a covariate. as.numeric(difftime object) simply turns off the units