similar to: R Packages in Windows

Hello, I have been trying to use the censored bootstrap function 'censboot' from the library boot, with the function 'survfit' from the library survival5. My code is: surv.fun <-function(data) { sur<-survfit(Surv(data[,1],data[,2]), data=data) } c.boot<-censboot(m,surv.fun,R=99) m is my data set I get the error message: Error in

Is it possible to calculate Kaplan-Meier for left-truncated, right-censored data using survival5? -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at

survexp in survival5 doesn't seem to work for me. see below: > library(survival5) Attaching Package "package:survival5": The following object(s) are masked from package:base : sort.list > library(chron) > data(ratetables) > survexp(~ratetable(year=julian(6,1,1991), + sex=1,age=35*365.24),times=(0:30)/6*365.24) Error in as.character(as.date(c(min(R[, 3]),

Hi, I am conducting a survival analysis and I have been trying, with not success, to do a log-log survival plots. Does anyone know how to do it in R? By the way I am using version 1.0.0 for windows. Many Thanks Marco -------------- next part -------------- An HTML attachment was scrubbed... URL: https://stat.ethz.ch/pipermail/r-help/attachments/20000503/e64aa9ee/attachment.html

> data(package=survival5) Warning: no data listing found Warning: package `survival5' contains datasets but no index The data loads OK. Mai Zhou -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the

Dear R-Helpers: What other references are there on the capabilities of the survival5 package other than the help files and the chapter on survival analysis in every edition of Modern Applied Statistics with S? I'm thinking of something like "An Introduction to Survival Analysis in R" with worked examples that might complement or extend the chapter in MASS. Thanks, Spencer

Hello everybody. First of all, I would like to present myself. I'm a french student in public health and I like statistics though I'm not that good in mathematics (but I try to catch up). I've discovered R recently while trying to find a statistical program in order to avoid rebooting my computer under windows when I need to do some statistical work. And here is my first question.

Dear all, in survival5, kidney data set, appears in help page: "survival5 does not reproduce the original analysis." What does it means? thanks in advance TCM -------------- next part -------------- An HTML attachment was scrubbed... URL: https://stat.ethz.ch/pipermail/r-help/attachments/20010927/e006b08d/attachment.html

Patrick Connolly wrote: > According to Richard A. Bilonick: > |> > |> I recently installed Red Hat Linux 7.0. I installed Version 1.2.0 (2000-12-15) of > |> R. I installed a number of packages including chron, date, ellipse, sgeostat, > |> survival5, and xtable. the "library()" command shows that they are installed. > |> > |> chron works but I get

My question is, how to compute hazard function(H(t)) after building the coxph model. I even aware of the terminology that differs from hazard function(H(t)) and the hazard rate(h(t)). Here onward I wish to calculate both. Here what I have done in two different methods; ##########################################################################################

I downloaded binary of survival5 for windows95 (also the splines, date). The function survsum shows up in content, has a help page, but the function itself is missing. Can we cut and paste the survsum from survival4 ? Mai Zhou P.S. I am not picking on R, not even complaining. I think R is great and I am try to contribute my (small) part to make it even better in way of bug report (or

Dear R-help readers, I'm trying to substitute my own version of plot.default, in order to capture low-level graphics input for further manipulation. I seem to be having difficulties getting the versions of functions that I intend to use called at the right places. Specifically, I have an object produced by survfit from the survival package, and I want to save the values that

Dear all, Are there functions or packages in R that can handle interval-censored data? I have looked in various packages (such as survival5 or event), but it seems that only right-censored data can be analysed. More generally, are there methods to analyse both interval-censored observations and right-censored observations in the same data set? Thanks in advance. Emmanuel Paradis

Dear all, I'm having difficulty getting access to data generated by survfit and print.survfit when they are using with a Cox model (survfit.coxph). I would like to programmatically access the median survival time for each strata together with the 95% confidence interval. I can get it on screen, but can't get to it algorithmically. I found myself examining the source of print.survfit to

Hi, I fit a Cox PH model to estimate the cause-specific hazards (in a competing risks setting). Then , I compute the survival estimates for all the individuals in my data set using the `survfit' function. I am currently playing with a data set that has about 6000 observations and 12 covariates. I am finding that the survfit function is very slow. Here is a simple simulation example

Hello, I create a plot from a coxph object called fit.ads4: plot(survfit(fit.ads4)) plot is located at: https://www.dropbox.com/s/9jswrzid7mp1u62/survfit%20plot.png I also create the following survfit statistics: > print(survfit(fit.ads4),print.rmean=T) Call: survfit(formula = fit.ads4) records n.max n.start events *rmean *se(rmean) median 0.95LCL 0.95UCL 203.0

I've a data set with 60000 rows of data representing 6000+ distinct loans. I did a coxph() regression on it (see call below), but a subsequent survfit() call on the coxph object is almost certainly wrong. It gives n=6 when it should be more like 6000+ (I think) > survfit(resultag) Call: survfit.coxph(object = resultag) n events median 0.95LCL 0.95UCL 6 489 Inf

Dear r-helpers, This is my first time to run survival analysis. Currently, I have a data set which contains two variables, the variable of time to event (or time to censoring) and the variable of censor indicator. For the indicator variable, it was coded as 0 and 1. 0 represents right censor, 1 means event of interest. Now I try to use "survfit" in the package of "survival". I

Hi everyone, I am not new to R, but new to running survival models in R. I am trying to create some basic KM curves, using the following code: library(survival) library(KMsurv) (import data etc - basic right censored, with continuously observed time of death) sleepfit <- survfit(Surv(timeb, death), data = sleep) Here timeb is measured is survival in years, death is a 1/0 indicator (1 =

I am confused when trying the function survfit. my question is: what does the survival curve given by plot.survfit mean? is it the survival curve with different covariates at different points? or just the baseline survival curve? for example, I run the following code and get the survival curve #### library(survival) fit<-coxph(Surv(futime,fustat)~resid.ds+rx+ecog.ps,data=ovarian)