similar to: avoiding loops, gaining generality

Hi. Can anyone suggest a simple way to obtain in R a list of vector coordinates of the following form? The code below is Mathematica. In[5]:= Flatten[Table[{i,j,k},{i,3},{j,4},{k,5}], 2] Out[5]= {{1,1,1},{1,1,2},{1,1,3},{1,1,4},{1,1,5},{1,2,1},{1,2,2},{1,2,3},{1 ,2,4},{1,2, 5},{1,3,1},{1,3,2},{1,3,3},{1,3,4},{1,3,5},{1,4,1},{1,4,2},{1,4,3}, {1,4,

I did some benchmarking of data frame code, and it appears that R 3.0.0 is far worse than earlier versions of R in terms of how many large objects it allocates space for, for data frame operations - creation, subscripting, subscript replacement. For a data frame with n rows, it makes either 2 or 4 extra copies of all of: 8n bytes (e.g. double precision) 24n bytes 32n bytes

Dear R-users, Is there an easy way to determine all possible vectors of length 21 with each entry having permutations from 0 to 4, instead of doing it like this? It really takes up too much time, and I am convinced that there exists something easier. Can you help me? Thank you in advance! Kind regards, Elke for (a in 0:4){ for (b in 0:4){ for (c in 0:4){ for (d in 0:4){

Hi, is there any way to keep a sub matrix dimension? exemple : i1<-1; i2<-1 j1<-2; j2<-3; ret <-matrix(1,4,4)[i1:i2,j1:j2] ; dim(ret) is NULL because the submatrix single col or single row is coerce to a vector automaticaly. How can i bypass this cast : submatrix->vector ??????? Thank you. --------------------------------- [[alternative HTML version

Hi all, I've a vector with entries, which are all of the same type, e.g. string: k <- c("bb", "bb", "bb", "aa", "cc", "cc") and want to create a second vector containing the number of each entry in k in the same order as in k, i.e. c(3, 1, 2) or: k <- c(5,5,5,5,2,2,4) => c(4,2,1) thanks

Thanks, David. I got the answer from the web. Is there any easy way to permute a set (e.g., a set of characters) by the permutation it returns? Thanks, > x <- c(10,7,4,3,8,2) > sort(x, index.return=TRUE) $x [1] 2 3 4 7 8 10 $ix [1] 6 4 3 2 5 1 2018-05-23 10:49 GMT+08:00 David Winsemius <dwinsemius at comcast.net>: > > > > On May 22, 2018, at 10:06 PM, John

I'd like to have a three dimensional array of matrices. I thought I could construct a five dimensional array to have the three dimensional array of matrices. However, not all of the matrices in the array have the same dimensions, which seems to mean I can't use a five dimensional array. What I'd like is this: A = matrix(1:4,2,2) B = matrix(1:25,5,5) C = matrix(1,3,3) D =

Hi, Is there any way to find the permutation function of the sorting and to apply the function (or its inverse) elsewhere? For example, the following permutation function from the sorting in the matrix form is c(1,2,3), c(2,1,3) > sort(c("bc","ac","dd")) [1] "ac" "bc" "dd" I try to find it in the permutations/permute

Is there a simple function or process that will create a matrix of permutations with replacement? I know that using the combinat package ###### begin R code ###### > library(combinat) > m <- t(array(unlist(permn(3)), dim = c(3, 6))) # we can get the permutations, for example 3!=6 # gives us > m [,1] [,2] [,3] [1,] 1 2 3 [2,] 1 3 2 [3,] 3 1 2 [4,]

Hello, I am using R version 2.6.2 on Windows XP. I installed R using the installation file provided through one of the CRAN mirrors; I did not build it myself. as a result, the LAPACK functionality is limited. I'm trying to install a package that requires access to complex LAPACK functions that are not provided in the LAPACK library that is included in the basic installation of R; this is

On Thu, 20 Dec 2018 01:32:16 -0800 christian russell <christian.baltini at gmail.com> wrote: > Hi Rowland, I see the typo now too — I retyped it from scratch … oops. > > Here it is. > > [global] > workgroup = HOME > netbios name = IPA > realm = HOME.FRAPLIN.FUN > kerberos method = dedicated keytab > dedicated keytab file =

> On May 22, 2018, at 10:57 PM, John <miaojpm at gmail.com> wrote: > > Thanks, David. > I got the answer from the web. > Is there any easy way to permute a set (e.g., a set of characters) by the permutation it returns? Thanks, > > > > x <- c(10,7,4,3,8,2) > > sort(x, index.return=TRUE) > $x > [1] 2 3 4 7 8 10 > > $ix > [1] 6 4 3 2

As most Wine users probably know, running applications using Wine won't (in most cases) give you the same performance as running the application in native Windows. From my experience this is especially true when it comes to applications that make use of Direct3D, and I suppose the performance drop is (at least in part) due to the translation of Direct3D to OpenGL in Wine. Now, this got me

> sort(c("bc","ac","dd"), index.return=TRUE) $x [1] "ac" "bc" "dd" $ix [1] 2 1 3 We have the permutation, namely 1-->2, 2-->1, 3-->3. How can I apply the permutation function to a new set c("D","E", "F")? so that the result is c("E","D", "F"). 2018-05-23 11:06

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 I have two matrices: > m1 <- matrix(1,4,4) > m1 [,1] [,2] [,3] [,4] [1,] 1 1 1 1 [2,] 1 1 1 1 [3,] 1 1 1 1 [4,] 1 1 1 1 > m2 <- matrix(0,3,3) > diag(m2) <- 1 > m2 [,1] [,2] [,3] [1,] 1 0 0 [2,] 0 1 0 [3,] 0 0 1 I want to get indicies from m2

These are the latests.. And the Why, Andrew already explain. Due to the mappings with windows acls. If the exec bit is missing, no windows programm will be allowed to start of a share. If i download an msi file to install and put it on a share, its not allowed to execute it. Which is exact what i want in my case. You might want to read

I would like to efficiently find the first index of each unique value in a very large vector. For example, if I have a vector A<-c(9,2,9,5) I would like to return not only the unique values (2,5,9) but also their first indices (2,4,1). I tried using a for loop with which(A==unique(A)[i])[1] to find the first index of each unique value but it is very slow. What I am trying to do is easily

Hi Rail, We used a very simple pattern expansion (actually, not a pattern fragment). For example, for AND, ADD (horizontal sum), OR and XOR of 4 elements we use something like the following TableGen structure: class HORIZ_Op4<SDNode opc, RegisterClass regVT, ValueType rt, ValueType vt, string asmstr> : SHAVE_Instr<(outs regVT:$dst), (ins VRF128:$src),

Hello Marco, I am speaking about POSIX ACLs, yes. When I create a file via shell I get a 660 file. When I create a file via Samba I get a 770 file. I don’t understand why they would be different. Without ACLs shell / Samba created files get consistent permissions. Christian > On Dec 20, 2018, at 12:29 AM, Marco Gaiarin via samba <samba at lists.samba.org> wrote: > > Mandi!

Hello all, I have a .csv file like below. Tool,Step_Number,Data1,Data2... etc up to 100 columns. A,1,0,1 A,2,3,1 A,3,2,1 . . B,1,3,2 B,2,1,2 B,3,3,2 . . ...... so on upto 50 rows where the column "*Tool*" has distinct steps in second column "*Step_Number*",but both have same entries in Step_Number column. I want the output like below.