Thanks, David. I got the answer from the web. Is there any easy way to permute a set (e.g., a set of characters) by the permutation it returns? Thanks,> x <- c(10,7,4,3,8,2) > sort(x, index.return=TRUE)$x [1] 2 3 4 7 8 10 $ix [1] 6 4 3 2 5 1 2018-05-23 10:49 GMT+08:00 David Winsemius <dwinsemius at comcast.net>:> > > > On May 22, 2018, at 10:06 PM, John <miaojpm at gmail.com> wrote: > > > > Hi, > > > > Is there any way to find the permutation function of the sorting and to > > apply the function (or its inverse) elsewhere? > > > > For example, the following permutation function from the sorting in the > > matrix form is > > c(1,2,3), c(2,1,3) > > > >> sort(c("bc","ac","dd")) > > [1] "ac" "bc" "dd" > > > > I think you are asking for the `order` function. > > > I try to find it in the permutations/permute package, but I can't find > it > > > > John > > > > [[alternative HTML version deleted]] > >[[alternative HTML version deleted]]
> On May 22, 2018, at 10:57 PM, John <miaojpm at gmail.com> wrote: > > Thanks, David. > I got the answer from the web. > Is there any easy way to permute a set (e.g., a set of characters) by the permutation it returns? Thanks, > > > > x <- c(10,7,4,3,8,2) > > sort(x, index.return=TRUE) > $x > [1] 2 3 4 7 8 10 > > $ix > [1] 6 4 3 2 5 1 >I don't understand what is being requested. The $ix value is the same as the one returned `by order`. David.> 2018-05-23 10:49 GMT+08:00 David Winsemius <dwinsemius at comcast.net>: > > > > On May 22, 2018, at 10:06 PM, John <miaojpm at gmail.com> wrote: > > > > Hi, > > > > Is there any way to find the permutation function of the sorting and to > > apply the function (or its inverse) elsewhere? > > > > For example, the following permutation function from the sorting in the > > matrix form is > > c(1,2,3), c(2,1,3) > > > >> sort(c("bc","ac","dd")) > > [1] "ac" "bc" "dd" > > > > I think you are asking for the `order` function. > > > I try to find it in the permutations/permute package, but I can't find it > > > > John > > > > [[alternative HTML version deleted]] > >
Perhaps the question was "what is indexing"? On May 23, 2018 5:06:39 AM GMT+02:00, David Winsemius <dwinsemius at comcast.net> wrote:> > >> On May 22, 2018, at 10:57 PM, John <miaojpm at gmail.com> wrote: >> >> Thanks, David. >> I got the answer from the web. >> Is there any easy way to permute a set (e.g., a set of characters) by >the permutation it returns? Thanks, >> >> >> > x <- c(10,7,4,3,8,2) >> > sort(x, index.return=TRUE) >> $x >> [1] 2 3 4 7 8 10 >> >> $ix >> [1] 6 4 3 2 5 1 >> > >I don't understand what is being requested. The $ix value is the same >as the one returned `by order`. > >David. > > >> 2018-05-23 10:49 GMT+08:00 David Winsemius <dwinsemius at comcast.net>: >> >> >> > On May 22, 2018, at 10:06 PM, John <miaojpm at gmail.com> wrote: >> > >> > Hi, >> > >> > Is there any way to find the permutation function of the sorting >and to >> > apply the function (or its inverse) elsewhere? >> > >> > For example, the following permutation function from the sorting >in the >> > matrix form is >> > c(1,2,3), c(2,1,3) >> > >> >> sort(c("bc","ac","dd")) >> > [1] "ac" "bc" "dd" >> > >> >> I think you are asking for the `order` function. >> >> > I try to find it in the permutations/permute package, but I can't >find it >> > >> > John >> > >> > [[alternative HTML version deleted]] >> >> > >______________________________________________ >R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code.-- Sent from my phone. Please excuse my brevity.
> sort(c("bc","ac","dd"), index.return=TRUE)$x [1] "ac" "bc" "dd" $ix [1] 2 1 3 We have the permutation, namely 1-->2, 2-->1, 3-->3. How can I apply the permutation function to a new set c("D","E", "F")? so that the result is c("E","D", "F"). 2018-05-23 11:06 GMT+08:00 David Winsemius <dwinsemius at comcast.net>:> > > > On May 22, 2018, at 10:57 PM, John <miaojpm at gmail.com> wrote: > > > > Thanks, David. > > I got the answer from the web. > > Is there any easy way to permute a set (e.g., a set of characters) by > the permutation it returns? Thanks, > > > > > > > x <- c(10,7,4,3,8,2) > > > sort(x, index.return=TRUE) > > $x > > [1] 2 3 4 7 8 10 > > > > $ix > > [1] 6 4 3 2 5 1 > > > > I don't understand what is being requested. The $ix value is the same as > the one returned `by order`. > > David. > > > > 2018-05-23 10:49 GMT+08:00 David Winsemius <dwinsemius at comcast.net>: > > > > > > > On May 22, 2018, at 10:06 PM, John <miaojpm at gmail.com> wrote: > > > > > > Hi, > > > > > > Is there any way to find the permutation function of the sorting and > to > > > apply the function (or its inverse) elsewhere? > > > > > > For example, the following permutation function from the sorting in > the > > > matrix form is > > > c(1,2,3), c(2,1,3) > > > > > >> sort(c("bc","ac","dd")) > > > [1] "ac" "bc" "dd" > > > > > > > I think you are asking for the `order` function. > > > > > I try to find it in the permutations/permute package, but I can't > find it > > > > > > John > > > > > > [[alternative HTML version deleted]] > > > > > >[[alternative HTML version deleted]]