similar to: Edited the How-To VirtualVsFtpd

Hello I am Thomas, alias Han Solo registered to wiki.centos.org with email libnacom{}gmail.com. I would like to contribute HowTO TUTORIAL for *Virtual Hosting with VSFTPD and MySQL on CentOS 5* which I posted in CentOS forums - link https://www.centos.org/modules/newbb/viewtopic.php?topic_id=24559&forum=38 Can I or someone post to WIKI for all others out there to help out configuring it,

This was sent to me regarding the wiki. ---------- Forwarded message ---------- From: "Martin Kon??ek" <mkonicek12 at gmail.com> Date: Mar 7, 2013 4:44 AM Subject: mistake on Securing SSH To: <timothy.ty.lee at gmail.com> Cc: Hi TImothy, I saw wiki http://wiki.centos.org/HowTos/Network/SecuringSSH and it is pretty good, but there is a mistake. *Instead of having* iptables

Hi, I have tried compiling the latest cvs version of dovecot on my FreeBSD 5.2.1-release box with the ports version of vpopmail: 5.4.3_1. In the configuration file I have two auth paragraphs, one for passwd authentication and one for vpopmail-auth: auth vpopmail { mechanisms = plain userdb = vpopmail passdb = vpopmail user = vpopmail } But the vpopmail dosn'nt work. I got the

Because you need to separate the instructions with a ; (semi-colon). Hope this helps Rui Barradas Enviado a partir do meu smartphone Samsung Galaxy.-------- Mensagem original --------De: Ek Esawi <esawiek at gmail.com> Data: 08/01/2018 16:03 (GMT+00:00) Para: Jeff Newmiller <jdnewmil at dcn.davis.ca.us>, r-help at r-project.org Assunto: Re: [R] Replace NAs in split lists Thank you

I don't know. You seem to be posting in HTML so your code is mangled. Can you post plain text and use the reprex package to make sure it produces the errorin a clean R session? -- Sent from my phone. Please excuse my brevity. On January 8, 2018 8:03:45 AM PST, Ek Esawi <esawiek at gmail.com> wrote: >Thank you Jeff. Your code works, as usual , perfectly. I am just >wondering why

OPS! Sorry i did indeed posted the code in HTML; should have known better. ifelse(is.na(z$Value),z$Value[!is.na(z$Value)][1],z$Value)z}) error. unexpected symbol in sdf2 On Mon, Jan 8, 2018 at 11:44 AM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote: > I don't know. You seem to be posting in HTML so your code is mangled. Can you post plain text and use the reprex package to

Thank you Jeff. Your code works, as usual , perfectly. I am just wondering why if i put the whole code in one line, i get an error message. sdf2 <- lapply( sdf, function(z){z$Value <-ifelse(is.na(z$Value),z$Value[!is.na(z$Value)][1],z$Value)z}) error. unexpected symbol in sdf2 Thanks again EK On Mon, Jan 8, 2018 at 3:12 AM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote: >

Hello all, during tests of my SecurID patch I found a small mistake (maybe) in initialization of kbd-int devices. When kbdintctxt->device->init_ctx(authctxt) returns NULL whole challenge response authentication is stopped regardless availability of next devices. Small patch solving this situation is attached. ____________________________________________________________ Vyzkou?ejte pohodl?

OPS, Sorry i did not read the post carfully. Mine will not work if you have zeros on columns A and B.. But you could modify it to work for specific columns i believe. EK On Wed, Nov 22, 2017 at 8:37 AM, Ek Esawi <esawiek at gmail.com> wrote: > Hi *Massimo,* > > *Try this.* > > *a <- mydf==0mydf[a] <- NAHTHEK* > > On Wed, Nov 22, 2017 at 5:34 AM, Massimo Bressan

I just came up with a solution right after i posted the question, but i figured there must be a better and shorter one.than my solution sdf1[[1]][1,4]<-lapplyresults[[1]] sdf1[[2]][1,4]<-lapplyresults[[2]] EK On Sun, Jan 7, 2018 at 10:13 PM, Ek Esawi <esawiek at gmail.com> wrote: > Hi all-- > > I stumbled on this problem online. I did not like the solution given > there

Hi Strahil, This is the output from the commands: root at uk3-prod-gfs-arb-01:~# du -h -x -d 1 /data/glusterfs/gv1/brick1/brick 2.2G /data/glusterfs/gv1/brick1/brick/.glusterfs 24M /data/glusterfs/gv1/brick1/brick/scalelite-recordings 16K /data/glusterfs/gv1/brick1/brick/mytute 18M /data/glusterfs/gv1/brick1/brick/.shard 0

Good afternoon I would like to ask if is possible somehow give more relevance to the recent documents in search results. I dont want to sort results according to the date, I still prefer relevance, but I would like to see recent documents with better scoring. I was trying to add search query using AND_MAYBE, which should use relevance from both subqueries, but it didnt add any benefit to the

Then you need to rethink your data structure. Use a list instead of a data frame. The components of a list can have different lengths, and the "apply" family of functions (lapply(), etc.) can operate on them. Consult any good R tutorial for details. Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it."

Hi! It seems my samba and cups won't communicate with each other. I've configured samba to load the printers from cups: load printers = yes printing = cups printcap name = cups [printers] comment = All Printers path = /var/spool/samba printable = yes public = no read only = yes create mode = 0700 valid users = @digiszfv

In y <- substr(x, i, 1) your third integer needs to be the location not the number of digits, so change it to y <- substr(x, i, i) and you should get what you want. Cheers, Tim > Date: Sun, 21 Jan 2018 10:50:31 -0500 > From: Ek Esawi <esawiek at gmail.com> > To: Luigi Marongiu <marongiu.luigi at gmail.com>, r-help at r-project.org > Subject: Re: [R] substr

Upon closer examination I see that you are not using the split version of df1 as I usually would, so here is a reproducible example: #---- df1 <- read.table( text= "ID ID_2 Firist Value 1 a aa TRUE 2 2 a ab FALSE NA 3 a ac FALSE NA 4 b aa TRUE 5 5 b ab FALSE NA ", header=TRUE, as.is=TRUE ) sdf <- split( df1, df1$ID ) # note the extra [ 1 ]

Yes, you are right if the IDs are always sequentially-adjacent and the first non-NA value appears in the first record for each ID. -- Sent from my phone. Please excuse my brevity. On January 8, 2018 2:29:40 AM PST, PIKAL Petr <petr.pikal at precheza.cz> wrote: >Hi > >With the example, na.locf seems to be the easiest way. >> library(zoo) > >> na.locf(df1) > ID

Why do you want to modify df1? Why not just reassemble the parts as a new data frame and use that going forward in your calculations? That is generally the preferred approach in R so you can re-do your calculations easily if you find a mistake later. -- Sent from my phone. Please excuse my brevity. On January 7, 2018 7:35:59 PM PST, Ek Esawi <esawiek at gmail.com> wrote: >I just came

Dear R Staff This is my file (www.fiscalforecasting.com/data.csv) if you don't download this file, my dataset same as following Year Month A B C D E 2005 July 0 *4* NA NA *1* 2005 July 0 NA NA 0 *9* 2005 July NA *4* 0 *1* 0 2005 July *4* 0 *2* *9* NA I try to count non-zero values which are not NA values for every *column* *Sincerely* *Engin YILMAZ*

Hi, I "developed" an implementation of /dev/random for HP-UX 11.00 that can be used to speed up entropy gathering for OpenSSL/OpenSSH implementations on HP-UX 11.00. It is still a first release, lots of stuff still to be done, but interested people can take a look at: http://www.josvisser.nl/hpux11-random/ Share and enjoy! ++Jos.nl P.S. I sent this message to the "user"