similar to: piping to littler

Hi, I'm not sure when this started occurring, but now I get: ---<--------------------cut here---------------start------------------->--- $ r -e 'quantile(rnorm(1e5))' Error in (function (name, package, ...) : autoloader did not find 'quantile.default' in 'stats' ---<--------------------cut here---------------end--------------------->--- I'm using

Hi, I've been using r (the little, but sweet one!), and recently found out about the magic argv vector of the rest of arguments passed to it. How can we process an argument that represents elements of a vector: $ r littler_ex.R 14 '3, 2' Error in ff * ss : non-numeric argument to binary operator where: ,-----[ cat ~/scripts/R/littler_ex.R ] | ff <- as.numeric(argv[1]) | ss

What ? ------ We are pleased to announce version 0.0.6 of littler What's new ? ------------ This version includes a bug fix or two as well as a number of small enhancements to the documentation. For OS X and the r/R confusion, our recommended suggestion is to call configure using either the --program-suffix=X or --program-prefix=Y option to have the binary and manual

What ? ====== littler - Provides hash-bang (#!) capability for R (www.r-project.org) Why ? ===== GNU R, a language and environment for statistical computing and graphics, provides a wonderful system for 'programming with data' as well as interactive exploratory analysis, often involving graphs. Sometimes, however, simple scripts are desired. While GNU R can be used

Hi, I'm trying to write a series of pipes using littler, and I get the following behaviour: Sorry if I'm just doing something witless, I'm new to R. I'm using the latest versions from debian testing (2.4.0 and 0.0.8). $ r -e 'a<-dget(file=stdin()); print(a)' ?list(a=2) Segmentation fault In R itself this works: > dget(file=stdin()) ?list(a=2) $a [1] 2 As do (from

Dear R folks, I have several data sets I want to process automatically using R. I found littler [1] and thought this will do the trick. 1. Read in data file to a data frame using `scan()`. 2. Do linear regression. 3. Write the data and the coefficients back to a file. #!/usr/bin/env r if (is.null(argv) | length(argv)!=1) { cat("Usage:

Hello list, I'm having some difficulty getting rJava to load in littler. Even after a R CMD javareconf and a reinstall of littler, I get this: jlaing at xenon:~$ r -e "require(rJava)" Loading required package: rJava Loading required package: methods Error : .onLoad failed in loadNamespace() for 'rJava', details: call: dyn.load(file, DLLpath = DLLpath, ...) error: unable

Hi, When using method L-BFGS-B along with a parscale argument, should the lower and upper bounds provided be on the scaled or unscaled values? Thanks. Cheers, -- Seb

Hi, I'm trying to write R scripts using littler (under Debian), and was originally using the shebang line: #!/usr/bin/env r However this picks up any .RData file that happens to be lying around, which I find a little disturbing, because it means that the script may not behave the same way on successive invocations. If you drop the /usr/bin/env trick then #!/usr/bin/r --vanilla seems to

Dear useRs, This is to announce that the maintainers of the various distributions have decided to provide "experimental" up-to-date versions of the following R related packages on Debian stable and Ubuntu (i386 and amd64 architectures): littler rkward python-rpy (not on Ubuntu Dapper) python-rpy-doc (not on Ubuntu Dapper) By "experimental" we mostly mean that

Dear useRs, This is to announce that the maintainers of the various distributions have decided to provide "experimental" up-to-date versions of the following R related packages on Debian stable and Ubuntu (i386 and amd64 architectures): littler rkward python-rpy (not on Ubuntu Dapper) python-rpy-doc (not on Ubuntu Dapper) By "experimental" we mostly mean that

Hi, I've run into a ridiculous problem I can't find any solutions for in the archives or help pages: data(barley) cutYield <- with(barley, by(yield, variety, cut, breaks = c(0, 30, 60, 90))) As in this example, I'm using 'by' to return a factor for each level of another factor. The problem is that 'by' returns a list of the factors, and I need all these factors

Dear R folks, wanting to compare different implementations of a solution I want to script it to iterate over the different implementations. Is there a way to do this in the R shell/command line? $ more /tmp/iterf.r f1 <- function(n = 100000, l = 100000) { z = n + l } f2 <- function(n = 100000,

Hello, I'm adding a private library tree in my home directory by adding this to my ~/.Renviron: R_LIBS="~/R/library:${R_LIBS}" so that once in R: R> cat(Sys.getenv("R_LIBS"), "\n") ~/R/library:/usr/local/lib/R/site-library:/usr/lib/R/site-library:/usr/lib/R/library Is this the best way to proceed? Cheers, -- Sebastian P. Luque

MyBSD% ./configure checking for a BSD-compatible install... /usr/bin/install -c checking whether build environment is sane... yes checking for gawk... no checking for mawk... no checking for nawk... nawk checking whether make sets $(MAKE)... yes checking build system type... i386-unknown-freebsd6.2 checking host system type... i386-unknown-freebsd6.2 checking for a BSD-compatible install...

Hi, I'd like to add, say, the sample size for every group in a bwplot as a parenthetical annotation to the axis. Here's a sketch: --8<---------------cut here---------------start------------->8--- require(Hmisc) age <- sample(1:100, 1000, replace = TRUE) sex <- gl(2, 8, 1000, c("Male", "Female")) grp <- gl(4, 6, 1000, letters[1:4]) bwplot(grp ~ age |

Hi, I came across a case where there's a discrepancy between minimum and maximum values reported by 'summary' and the 'min' and 'max' functions: ---<---------------cut here---------------start-------------->--- R> str(tt) num [1:1397] 1952 1970 1976 1967 1946 ... R> summary(tt) Min. 1st Qu. Median Mean 3rd Qu. Max. 1920 1960 1970

Hi, I'm usually confused about when to use 'slot' or '@'. I've frequently read that it's always preferable to use accessor functions, so I would think the '@' operator should be avoided. However, ?slot contains the following advise: "Generally, the only reason to use the functional form rather than the simpler operator is _because_ the slot name has to

Hi, The following code produces a plot on X11: splom(~iris[1:4], groups = Species, data = iris, panel = panel.superpose, key = list(title = "Three Varieties of Iris", columns = 3, points = list(pch = super.sym$pch[1:3], col = super.sym$col[1:3]), text = list(c("Setosa", "Versicolor", "Virginica")))) However,

Hello, I've encountered the need to cut some chron objects of the form: R> mychron <- chron(sort(runif(10, 0, 10))) R> mychron [1] (01/01/70 16:36:20) (01/02/70 00:08:46) (01/03/70 16:54:49) [4] (01/04/70 06:45:00) (01/07/70 06:21:24) (01/07/70 18:28:44) [7] (01/08/70 00:47:05) (01/08/70 05:11:44) (01/10/70 01:07:53) [10] (01/10/70 17:46:53) into arbitrary (e.g. a given number