similar to: save form values w/paginate (next page links fail)

How come I allways immediately run into difficult stuff when I''m trying some new programming language? Am I blind for the simplicity of Ruby/Rail, which a see must be there? Anyway, don''t try and answer this rhetoric question. I have got another one for you, seemingly difficult. I''m struggling with a n:m relationship (in a database, that is) and its join table.

Hi I use the scaffolded generated crud to handle my entries, and I cannot figure out how to reverse the list, what with the pagination. I can reverse the entries on a page, but not the entire paginated list. Also, it would be helpful to me to be able to redirect to the last page of a paginated list when I destroy, i figured out how to add such links to the view, but how to get from the

The built-in Rails pagination is fairly limited...you pass in the model name, and optionally some conditions, and it generates a paginated query for you. This gets to be very bad if you''ve got any custom queries. class Company < ActiveRecord::Base def complete_videos Video.find :all, :conditions => "company_id=#{id} AND status=''complete''", :order

hi i know i can do: @customer_pages, @customers = paginate :customers, :per_page => 8 but these customers have helpdesk calls which are child records. I hoped i could do something like paginate customers.calls, but dat doesn''t work what is the best way to get a paginated list of child records? remco -- Posted via http://www.ruby-forum.com/.

Using Ferret for searching, I''ve got results that I need to link to. Which is fine, except for that they''re displayed on paginated pages using Rails paginate function - so it''s not like I can''t get it from the database or anything else. Anyone have any ideas on how to go about this? It''s not so much a coding problem as a theory problem, and I

Hello, I want to know how can I paginate a set of records. It seems there is no direct way of doing this, and I am not able to understand the documentation of paginate, so any pointers on how to do this will be much appreciated. To be specific what I want is that the records returned by user.recipes, the recipes of the particular user be paginated. My attempt to do this failed because

I have this code in my controller and i cannot seem to figure out how to get it to paginate correctly.. Is there a trick to do something like this? There are a few others at www.rubyonrailsforum.com that are having the same issue. Any insite would be great, thanks in advance! def display_location if params[:search] && params[:search].size > 0 @listing_pages, @listings =

Hi, I have @result_pages and @results obtained from paginate in an action. I want to show the pages as 1 | 2 | 3 | 4 > The fifth page will show: < 5 | 6 | 7 | 8 > and so on. How exactly do I render the paginator to give this effect? I guess I will have to use pagination_links_each. But being new to Rails, I need help. Thanks, Yash -- Posted via http://www.ruby-forum.com/.

I put everything in a pastie to make it a bit more readable: http://pastie.org/593379 This is the gist: Will_paginate doesn''t play quite nice. The first result set is fine, and when I click on one of the paginated links, it returns the following error: Couldn''t find DictatedExam with ID=filter_widget observe_field triggers filter_widget which calls the paginated search.. Which

I am using the proven authorization plugin to defines roles for users, so I can get all groups where a user is ''member'' @groups = current_user.group_memberships I have an habtm association between groups and events class Group < ActiveRecord::Base has_and_belongs_to_many :events .. class Event < ActiveRecord::Base has_and_belongs_to_many :groups I am trying to list

I have a controller and list page for region object. My list page has a ''name'' text input that can be used to limit the list. It works except that the paginate gets the full set of regions unqualified by my search term. I believe this full list is contained in :regions symbol which I dont seem to be allowed to modify or replace (yes I am a ruby and rails newb). How can I

Is there a quick and easy way to paginate something like @member.items (Member with has_many :items)? Right now I do in the controller: @item_pages, @member_items = paginate :item, :conditions=>["member_id=?", @member.id], :per_page=>25, :order=>''datetime desc'' It''d be more DRY if this was possible: @item_pages, @member_items = paginate

I just published a new article on how and why (and when!) to do away with paginated search results, in favour of a more natural, endlessly scrolling page. http://unspace.ca/discover/pageless/ I provide code and an example of how to implement this in Rails and Prototype. Opinions and suggestions welcomed! Pete Unspace Interactive Inc. --~--~---------~--~----~------------~-------~--~----~ You

Does anybody know how to paginate a find_by_sql query? Unfortunately I need to paginate a query which is next to impossible for ActiveRecord or just too much of a pain to implement. So I''m using find_by_sql. However, I anticipate a large number of rows returned eventually. So I may need paginate. Does anyone know how? Thanks Phillip Novess http://primalart.net

I have this code in my controller and i cannot seem to figure out how to get it to paginate correctly.. Is there a trick to do something like this? There are a few others at www.rubyonrailsforum.com that are having the same issue. Any incite would be great, thanks in advance! (over 117 views and no answer in rubyonrailsforum???) def display_location if params[:search] &&

First I read previous thread with similar problem but I don''t find answer (problem is little diffrent) Hello, I have problem with display information from two tables using paginate.. Here is code. ##### SQL create table subscribers ( id integer not null auto_increment, name varchar(32) not null, surname varchar(64) not null, create_timestamp DATETIME not null, modify_timestamp DATETIME

Hi, I''m trying to figure out how to use paginate when one of the conditions depends on the association between one model and another. For example: I have a model Authors which has_many Posts. I would like to find all the authors and order them by the number of posts that they have published and then paginate those results. What if I wanted to base the paginate condition on all the

Im using this paginate function to paginate complex sql queries http://www.bigbold.com/snippets/posts/show/389, all seems to work fine but theres one thing, when i hit the next link it show nothing, i mean it only shows the first page, here is the code im using: #application.rb----------------- def paginate_collection(collection, options = {}) default_options = {:per_page => 10, :page

Hello, I have 2 tables table colors : +----------------------+ | id | user_id | name | +----------------------+ | 1 | 1 | test1 | | 2 | 2 | test2 | | 3 | 3 | test3 | +----------------------+ table users : +----------------------+ | id | enabled | name | +----------------------+ | 1 | 1 | bob | | 2 | 1

The head of the tree supports the :select option for find which allows one to override the default select(*) behavior of find. In my case, this allows me to throw in a DISTINCT call to ensure the results are of course distinct. Paginate supports :select since it passes it right through to find. However, count does not support it. This causes the paginator to think it has more entries to