similar to: Custom pagination

I have a little web app where we need to paginate collections of items. I''m trying to sort the collection and then pass it, sorted, to a Paginator, and still be able to paginate through the collection, across several pages, with the new sort order. The only thing I''m doing differently from the regular scaffolding approach is this: @order_pages = Paginator.new(self,

i''ve got several methods in my models i use to find based on certain criteria...i''ve done this so the controller code is less cluttered, plus the DRY factor. example: class Foo < ActiveRecord::Base def find_by_something(something) find :all, :joins => ..., :conditions => ... end def find_by_something_else(something_else) find :all, :joins => ...,

How do I adapt this code to only list articles made by the user logged into the session? def list @article_pages, @article = paginate :articles, :per_page => 10 end -- Posted via http://www.ruby-forum.com/.

I am a Rails newbie and I am trying to build a test site in which users will have their own sets of data. I understand how to manipulate shared data very well. Most of the Rails examples out there seem to deal with such shared data. I am struggling with the "best practice" method for a user to work with their own data however (and not be able to view/edit other users''

i''ve figured out how to use the next and previous links with the paginator class but now i''m trying to figure out how to display all the page numbers in between. looking through the rails api, i found paginator.each() but i''m not sure how to use it, or if that''s even what i am looking for. also, is there a way to limit the amount of pages like some sites

Hi all, Is there a way to create pagination with a complex SQL, more complex than the :conditions option will support? I have two databases, houses and images. Houses has_many images, and each Image belongs_to house. I''m creating a search engine for the house records and I''d like to be able to filter out all the houses without any associated images. So far I''m

There must be a better way to write this code: @project_pages, @projects= paginate :project, :per_page => 10, :conditions => ["account_id = ?", account] ?! If only I could pass the sub-collection account = ... @projects = account.project to paginate, instead of letting it extract it with a find :all + sql conditions Alain. -- Posted via

I have my list view filtering rows shown within the table <tr> tags like most of the introductory tutorials do. As I''m adding a few dozen entries I''m noticing the standard scaffolding pagination doesn''t pick up the number of rows from the filter since it is not being passed the number of rows returned within the scope of the filter statement. >From a

Hey all, I''m building a photo album site (for fun) and have a few questions. 1) This site will have a browse section, where you can view the photos by thumbnail. I want to let the user change how many thumbs they can see per page. I''ll have a couple links at the bottom of the page letting them do that. The problem is, if they are in the middle of browsing and decide to

Is there a count_by_content alternative to the find_by_content action? This is because I''m wanting to do the following in my pagination method: def list # step 1: set the variables you''ll need page = (params[:page] ||= 1).to_i items_per_page = 20 offset = (page - 1) * items_per_page # step 2: instead of performing a find, just get a count item_count =

I have searched for days for an example that demonstrates what i would like to do, and this morning i thought i''d worked it out, but no....here''s what i have: Controller ========== class ProfilesController < ApplicationController def friends current_user.profile.friends end def list_friends @profile_pages, @profiles = paginate( friends, :per_page => 10) end end

I have some code working that lists only items from a particular user. The code in my list action finds the user and then conditionally lists only his/her items: def list user = User.find(session[:user]) user_id = user.id @product_pages, @products = paginate :products, :per_page => 10, :conditions =>[''user_id = ?'', user.id]

Hi list, I Try to do a custom paginator, but the offset never increase ?? def showFriends @friends_pages = Paginator.new self, allFriends.size, 3, @params[''page''] limit= @friends_pages.items_per_page offset= @friends_pages.current.offset

Hi there, I''ve been trying to paginate over a list of members that all share a tag in common using the acts_as_taggable plugin. The regular way of paginating over a collection doesn''t seem to work with acts_as_taggable. Here''s what my method looks like that takes in a tag name, finds all the members that share the tag and then displays all the members. Nothing too fancy

Just wondering how to best integrate with pagination and still stick to MVC... Say I have a Post model that has a published attribute. I want to show all the recent published posts on a page. My first instinct is to create a method in the Post model called recent that does the find with proper conditions and order, but the problem I have is how do I use that with pagination (which definitely

def show_details @sd_ticket = ServiceDeskTicket.find(params[:id]) @servicedesk_cis = @sd_ticket.service_desk_cis end What I need is a pagination for @servicedesk_cis using the custom pagination..How can i give offset and limit to this? I have successfully done previously custom pagination in another def as below def search_sd_ticket @search_sd_ui_hash=params[:sd_ticket]

how exactly would I apply paginate to a .find I have: @posts = Post.find(:all, :conditions => [ ''(title) OR (body) LIKE ?'', ''%'' + params[:query] + ''%''], :order => ''end_date'') How would I go about paginating the uoputed list? Something like 10 on a page. -- Posted via

Hi I have the controller code as below # step 1: set the variables you''ll need page = (params[:page] ||= 1).to_i items_per_page = 20 offset = (page - 1) * items_per_page # step 2: instead of performing the full find, just find the record count @search_sd_ticket_count_result =

I''ve created a class method in my model called find_filtered. The intent is that I take various params that the user has submitted, and let the model build the query and return the AR collection, which is exactly what happens. However, now I''d like to paginate the recordset. Everything I''ve been able to find about pagination presumes that you have no pre-existing AR

Hi, I have @result_pages and @results obtained from paginate in an action. I want to show the pages as 1 | 2 | 3 | 4 > The fifth page will show: < 5 | 6 | 7 | 8 > and so on. How exactly do I render the paginator to give this effect? I guess I will have to use pagination_links_each. But being new to Rails, I need help. Thanks, Yash -- Posted via http://www.ruby-forum.com/.