similar to: Is there a sexy way ...?

Rold, We need to be clear on what makes an answer sexy! LOL! I decided it was sexy to do it in a way that nobody (normal) would and had not suggested yet. Here is an original version I will explain in a minute. Or, maybe best a bit before. Hee is the unformatted result whicvh is a tad hard to read but will be made readable soon: x <- list(`1` = c(7, 13, 1, 4, 10), `2` = c(2, 5,

Admit it, Rolf. Haven't you wondered if S, in a more private way, is sexier than R? OK, kidding aside, we have talked this to death. Just FYI, the conversation was stimulating for some of us and I have continued on my own and located functions I see as useful in the stringi and stringr packages to make my silly version ever less silly! LOL! -----Original Message----- From: Rolf Turner

On Sat, 28 Sep 2024 10:26:31 +0100 CALUM POLWART <polc1410 at gmail.com> wrote: > Avi > > I fear this was all a huge social experiment. > > Testing if a post titled "sexy way" would increase engagement... <SNIP> I conjecture that this conjecture was tongue-in-cheek. Be that as it were ??, let me assure everyone that such was not my intention. The usage

Avi I fear this was all a huge social experiment. Testing if a post titled "sexy way" would increase engagement... On Sat, 28 Sep 2024, 07:21 , <avi.e.gross at gmail.com> wrote: > I see a book coming: > "666 ways to do the same thing in R ranked by sexiness." > > Kidding aside, if you look under the covers of some of the functions we > are

"Sexy code" may get a job done and demonstrate the code's knowledge of a programming language, but it often does this at the expense of clear, easy to document (i.e. annotate what the code does), easy to read, and easy to understand code. I fear that this is what this thread has developed "sexy" but not easily understandable code. While I send kudos to all of you, remember

>>>>> Chris Evans via R-help >>>>> on Fri, 27 Sep 2024 12:20:47 +0200 writes: > Oh glorious!? Thanks Duncan. > Fortune cookie nomination! I don't disagree with the nomination -- thank you, Duncan! However, please note that I'm sure Rolf's was challenged / question was ment to work correctly for all factors `f` with levels

Sorry to append, but I just realised that of course ``` x |> ? pmap(c) |> ? reduce(c) |> ? unname() ``` also works and is a general solution in case your list has more than three elements. Here, we map in parallel over all elements of the list, always combining the current set of elements into a vector, and then reduce the resulting list into a vector by combining the elements

I see a book coming: "666 ways to do the same thing in R ranked by sexiness." Kidding aside, if you look under the covers of some of the functions we are using, we may find we are taking steps back as some of them use others and perhaps more functionality than we need. But for a new reader , looking at many approaches may open up other ways and ideas and see the problem space as quite

Hi Rolf, this topic is probably already saturated, but here is a tidyverse solution: ``` library(purrr) x <- list( ? `1` = c(7, 13, 1, 4, 10), ? `2` = c(2, 5,? 14, 8, 11), ? `3` = c(6, 9, 15, 12, 3) ) x |> ? pmap(~ c(..1, ..2, ..3)) |> ? reduce(c) #> [1]? 7? 2? 6 13? 5? 9? 1 14 15? 4? 8 12 10 11? 3 ``` Here, we map over the elements of the list in parallel (hence pmap),

You could have negative indices. There are two ways to do this. 1) provide a large offset. Offset <- 30 for (i in -29 to 120) { print(df[i+Offset])} 2) use absolute values if all indices are negative. for (i in -200 to -1) {print(df[abs(i)])} Tim -----Original Message----- From: R-help <r-help-bounces at r-project.org> On Behalf Of Peter Dalgaard via R-help Sent: Monday, April 22,

I have no real idea what you are trying to do, but if a table is what you want, you can probably get it using the table() function. Or, more likely, the xtabs() function. Using your example from an earlier post (adjusted to make it comprehensible to the human mind): set.seed(1000) time <- factor(rep(c("Pre","Post"),each=200)) treatment <-

Hi Rolf, No it is not. I don't know to which question did you want to respond ? I desribed everything in my first email and attached links from SO with pictures included, which are quite understandable. Cheers, Jacek wt., 27 lut 2024 o 02:29 Rolf Turner <rolfturner at posteo.net> napisa?(a): > > I have no real idea what you are trying to do, but if a table is > what you

Heh. Did anyone bring up negative indices yet? -pd > On 22 Apr 2024, at 10:46 , Rolf Turner <rolfturner at posteo.net> wrote: > > > See fortunes::fortune(36). > > cheers, > > Rolf Turner > > -- > Honorary Research Fellow > Department of Statistics > University of Auckland > Stats. Dep't. (secretaries) phone: > +64-9-373-7599

Please see fortunes::fortune(285). cheers, Rolf Turner -- Honorary Research Fellow Department of Statistics University of Auckland Stats. Dep't. (secretaries) phone: +64-9-373-7599 ext. 89622 Home phone: +64-9-480-4619

See fortunes::fortune(36). cheers, Rolf Turner -- Honorary Research Fellow Department of Statistics University of Auckland Stats. Dep't. (secretaries) phone: +64-9-373-7599 ext. 89622 Home phone: +64-9-480-4619

On Tue, 7 May 2024 06:34:50 -0400 Duncan Murdoch <murdoch.duncan at gmail.com> wrote: > On 07/05/2024 6:31 a.m., Iago Gin? V?zquez wrote: > > Thanks Duncan. > > > > I am currently on Windows. Is there any solution for it? > > Switch to Linux or MacOS? Fortune nomination! cheers, Rolf Turner -- Honorary Research Fellow Department of Statistics University of

x[?V2?] would retain columns of x headed by V2. What I need is the opposite??I need a data grime with those columns excluded. Steven from iPhone > On Feb 13, 2023, at 9:33 AM, Rolf Turner <r.turner at auckland.ac.nz> wrote: > > ? >> On Sun, 12 Feb 2023 14:57:36 -0800 >> Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote: >> >> x["V2"]

Hi all, I've just could test your suggestions on using dataedit... entries now, and indeed they work... partially. See, please, the next screenshot: https://ibb.co/Dkn2pVs dataedituser modifies the red borders dataedittext the yellow text dataeditfg... I do not know, specified to green the output of View(mtcars) does not change from that of the screenshot dataeditbg is the (almost) black

Doesn't sound like you got the point. x[-1] normally removes the first element. With 0-based indices, this cannot work. - pd > On 22 Apr 2024, at 17:31 , Ebert,Timothy Aaron <tebert at ufl.edu> wrote: > > You could have negative indices. There are two ways to do this. > 1) provide a large offset. > Offset <- 30 > for (i in -29 to 120) { print(df[i+Offset])} >

Hello Peter, Unless I too misunderstand your point, negative indices for removal do work with the Oarray package (though -0 doesn't work to remove the 0th element, since -0 == 0 -- perhaps what you meant): > library(Oarray) > v <- Oarray(1:10, offset=0) > v [0,] [1,] [2,] [3,] [4,] [5,] [6,] [7,] [8,] [9,] 1 2 3 4 5 6 7 8 9 10 > dim(v)