similar to: Help needed in specifying conditions in pagination

Trying to create stuff without resorting to scaffold command. I have a list view in my login_controller.rb file... def list_users @user_pages, @users = paginate :users, :per_page => 14 end I have a command in my list_users.rhtml file which undoubtedly calls this pagination... <% odd_or_even = 0 for user in @users odd_or_even = 1 - odd_or_even %> and instead of being presented a

Hello! I''m a beginner of rails. I made a simple test project with rails 1.1.2 and ruby 1.8.2 on Windows XP. DB is SQLServer 7.0. I''m connecting the server thru ODBC. I created a table named "users" with about 10 columns. I inserted 1000 sample records. I created a scaffold for user model and login controller for it using the script. Everything''s fine

hey, i have users who are in groups, and i have a search form, where i can search on group, user lastname, and user firstname. All this is also with pagination. these are my models class User < ActiveRecord::Base has_and_belongs_to_many :groups end class Group < ActiveRecord::Base has_and_belongs_to_many :users end in my controller i do this THIS works (but in need pagination) @users2

Hi, Why can''t I use a variable to specify the :per_page attribute when using the most basic form of pagination? (if I use a hardcode number, it runs) What did I do? Thx. My code: def list_orders page_size = 20 ... order_pages, @orders = paginate(:orders, :per_page => page_size) end My Errors: undefined method `>'' for false:FalseClass RAILS_ROOT:

Hello, maybe that I''m a stupid, but I don''t know how I can working with pagination. In all examples is written (for example) next: def user_list @user_pages, @users = paginate(:users, :order_by => ''name'') end So, it''s OK (as a scaffold) for all set of users. But I need a little other functionality. For example I need paginate only a little bit

I am having this problem with pagination query in my controller class. I am using SQL server and following code to create pagination fails, complains about column name ''program_name'' (which is valid column/attribute of program) The error message is: DBI::DatabaseError: S0022 (207) [Microsoft][ODBC SQL Server Driver][SQL Server]Invalid column name

How do I display subsets of records on a Listing page (that lists in grid form table records)? In particular, when displaying the Listing page, it would be nice to allow the user to display a subset of the records, for example, by filtering. For example, I have the following Controller Listing and Filtering actions: def list @eng_sense_pages, @eng_senses = paginate :eng_senses,

Hi Guys, I am trying to paginate the results from a search. When I use actual constants in the search conditions, it works fine: def query @k2_result_pages, @k2_results = paginate (:k2_results, :conditions => [''e_date >= ? AND e_date <= ?'', ''2006-07-12'', ''2006-08-12''],

hi everybody, i am new to rails.. plz clear my doubt... this is my question In my table(public_topics), i have 11 rows of data.. whenever i run the following view, it shows the entire rows in the current page.. and i have set the '':per_page'' option to ''2''.so it must show two data per page..but it shows all the rows in a single page..and this case continue

Hi everyone, I have this code: @person_pages, @people = paginate :person, :per_page => 20, :conditions => [ "username LIKE ? OR first_name LIKE ? OR last_name LIKE ? OR preferred_name LIKE ?", "%" + params[:q].downcase + "%", "%" + params[:q].downcase + "%",

> Unfortunately I still get the same error. Here is my code now (the > commented line works): > > def list > @upload_pages, @uploads = paginate(:uploads, :per_page => > 20, :order > => ''id'') > # @upload_pages, @uploads = paginate(:uploads, :per_page => 20) > end You may have an older version, try using the order_by clause

I''m struggling with the issue of pagination and many to many relationships. I have products and categories (a many to many relationship.) When I go to a category page, I wish to load all products associated with that category and have pagination of the products. @category_products = @category.products gives me all the products associated with the category however, when I try to

I am trying to use pagination with the order option. I am following examples I''ve seen all over the web, but I am getting an error. My code seems simple: def list @upload_pages, @uploads = paginate :uploads, :per_page => 20, :order => ''id'' end Yet I keep getting this error: ___________________________________________

I''m using will_paginate in a Post class method; [code]def self.list(page) paginate :per_page => 10, :page => page, :include => :user end[/code] I can happily use the method on my posts controller index action; [code] class PostsController < ApplicationController def index @posts = Post.list(params[:page]) respond_to do |format|

Hello, I want to know how can I paginate a set of records. It seems there is no direct way of doing this, and I am not able to understand the documentation of paginate, so any pointers on how to do this will be much appreciated. To be specific what I want is that the records returned by user.recipes, the recipes of the particular user be paginated. My attempt to do this failed because

Hi all, I''m creating admin module. in that module i need to get the list of users and also the projects created by the each user. No doubt i''m getting the list of users. but i''m not getting the list of projects done by each user.. This is my code:: <% for user in @users %> <%=link_to

I have the following: def index begin @restaurant_pages, @restaurants = paginate :restaurants, :order => (params[ :sort ] || "name"), :per_page => 2 @cuisines = Cuisine.find_all rescue redirect_to :action => :index end end # sort by cuisine def

I have tried to use eager association with pagination, but the :include option is not supported: Here''s the one-line pagination call without :include @link_pages, @links = paginate :link, :per_page => 10, :order_by => sort_clause and here the work around, using the "classic" method # @link_pages = Paginator.new self, Link.count, 10,

I am trying to do a simple search by product name. The first page returns fine, but when I try to go to any other pages of the search results, I lose the original search parameters from my search form and get NilClass errors. Here is the code in my controller: namesearch = "%" + params[:name].strip + "%" @product_pages, @products = paginate :product,

Hey there, Previous to finding ferret I had a test query setup to do pagination like: @listing_pages, @listings = paginate(:listing, :per_page => 10, :conditions => [" name LIKE ? ", "%" + search_criteria + "%"], :order_by => "name ASC") Can I do similar pagination with @results array returned from a ferret