similar to: Ayuda para hacer una lista

Muchas fracias por la rapida contastacion Javier. Si, ya me he dado cuenta que a veces es mas limpiar y formatear que calcular. Lo que yo necesito hacer no es crear un data.frame, es crear una lista por cada grupo/condicion de muestras. Y queria hacerlo en un for loop, para que no tuviese que indicar cuantas listas necesito si no que cogiese esa informacion del usuario (y) Creo que no me

Hola Leticia Acomodar datos para analizar suele llevar más trabajo que el análisis. Yo prefiero en un data.frame colocar todos los datos, porque siempre es más fácil filtrar que agregar. Cuándo tengo el data.frame con todo, realizo un plot (datos), y muchas veces en la gráfica veo cosas que me llaman la atención, de esta forma busco algo de antemano no sospechaba. No es necesario que conozcas

Hola, que tal? Sin saber nada mas de los datos, por lo que dices, mi aprioximacion seria usar la funcion split, e.g.: splittedData <- split(myData, "variablegrupo/condicion") Esto te crearia una lista con tantos objectos como condiciones tengas. Saludos On 6/27/24 10:15, Leticia G Leon wrote: > Muchas fracias por la rapida contastacion Javier. > > Si, ya me he dado

hi all ,? i have an problem in script R . But when I execute the script R I face this error . can you help me please ???error:----------------------------------------- Error in FUN(X[[i]], ...) :?? Theme element 'text' has NULL property: margin, debugIn addition: Warning messages:1: Removed 361 rows containing non-finite values (stat_smooth).?2: Removed 361 rows containing missing values

Hi, I have a data frame like this: > dput(df) structure(list(ID = 1:8, Type = c("gmx mdrun -ntmpi 8 -ntomp 1 -s benchPEP.tpr -nsteps 10000 -resethway", "gmx mdrun -ntmpi 8 -ntomp 1 -s benchPEP.tpr -nsteps 10000 -resethway", "gmx mdrun -ntmpi 8 -s benchPEP.tpr -nsteps 4000 -resetstep 3000", "gmx mdrun -ntmpi 8 -s benchPEP.tpr -nsteps 4000 -resetstep

?? Hola. Estoy intentando ordenar el gráfico tal que las columnas se apilen en el siguiente orden: debajo, los EPI; los SemiEPI en el medio y los NoEpi arriba de todo. Estos son mis datos: > tabla.barras Rangos Clase Asistentes 1 De 45d EPI 405 2 De 1a EPI 812 3 De 2a EPI 1639 4 De 3a EPI 2202 5 De 4a EPI 1994 6 De 5a EPI

Hello, I am trying to add a less than equal to symbol in a ggplot2 legend text. See sample code below. I have tried using the expression function and \u2264. I also tried adding labels to legend.text under theme. Neither of these 3 options work. Please help, Mahesh ++++++++++++++ Extra.column=ifelse(data[,covariate]>cutpoint,1,0) Grp1 <- "\u2264 1.5" Grp2 <-

Hola, Mira la versión de ggplot2 que estás usando por tenerla actualizada a la última... A mi me funciona introduciendo algún cambio salvo la última línea cuando cambias el tema... #----------- Lines <- " id Rangos Clase Asistentes 1 45d EPI 405 2 1a EPI 812 3 2a EPI 1639 4 3a EPI 2202 5 4a EPI 1994 6 5a EPI

Hello everybody, I have experience coding with R, but am brand new to R Shiny. I am trying to produce an application that will allow users to upload their own dataset, select columns they want an ANOVA analysis run on, and generate graphs that will allow users to view their results. However, I am getting the following error: *"Argument is of length zero."* Being new to Shiny, I am

Hi, I want to plot grouped bars to compare 95% confidence interval estimates from two models. Each bar represents a 95% confidence interval estimate of a coefficient from one of the two models. Each group represents confidence interval estimates of the same coefficient from the two models. I think such a bar plot will nicely present whether 95% confidence interval estimates of the same

I have a function: myplot <- function (X) { d <- plotCounts(dds2, gene=X, intgroup="condition", returnData=TRUE) png(paste("img/", X, ".png", sep="")) ggplot(d, aes(x=condition, y=count, color=condition)) + geom_point(position=position_jitter(w=0.1,h=0)) + scale_y_log10(breaks=c(25,100,400)) + ggtitle(X) +

I don't really understand. I mean, I understand the solution is print(ggplot(...)). But why is that required in a function and not at the console? Shouldn't I be able to rely on what I do at the console working in a script? Is this inconsistent behavior by design? On Thu, Nov 2, 2017 at 11:54 AM, David Winsemius <dwinsemius at comcast.net> wrote: > >> On Nov 2, 2017,

hi there.. i got a problem with ggplot2. here my example: library (ggplot2) v1 <- c(1,2,3,3,4) v2 <- c(4,3,1,1,9) v3 <- c(3,5,7,2,9) gender <- c("m","f","m","f","f") d.data <- data.frame (v1, v2, v3, gender) d.data x <- names (d.data[1:3]) y <- mean (d.data[1:3]) pl <- ggplot (data=d.data, aes (x=x,y=y)) pl

Hello, I'm attempting to alter the location of text in my axis labels in lattice plots and have been unsuccessful so far. For example, the y-axis labels are always right-justified, but I would like them to be horizontally centered. Here's an example: library(lattice); # create fake dataset to plot to.plot <- data.frame( x = 1:5, y = c("1\nAAA", "2\nBBB",

Putting names on a ggplot Can anyone suggest what I am doing wrong here. I am plotting daily temperatures at Ottawa Ontario for 2008 broken down by months, I seperate them by lines and want to put the names of the months at the top of the chart ( with in the graphing area) Everything is working as I want until I try to add the names of the months. I did something similar a few days ago and I

Hi all, I want to arrange two ggplot2 plots on the same page with their x-axes lined up - even though one is a boxplot and the other is a line plot. Is there a simple way to do this? I know I could do this using facetting if they were both the same type of plot (for example, if they were both boxplots), but I haven't been able to figure it out for two different types of plots. Below is my

> On Nov 2, 2017, at 9:27 AM, Ed Siefker <ebs15242 at gmail.com> wrote: > > I have a function: > > myplot <- function (X) { > d <- plotCounts(dds2, gene=X, intgroup="condition", returnData=TRUE) > png(paste("img/", X, ".png", sep="")) > ggplot(d, aes(x=condition, y=count, color=condition)) + >

I took some data from an online poll about which R GUI people used most and I am messing around with it to learn how to use qplot. Specifically I am making a horizontal bar graph and I have two questions. 1. The categories are ordered in rather strange way at least to me. It is not alphabetical or ascending/descending order of votes cast so i had to manually state the order I wanted which is

?s 05:11 de 13/01/2023, roslinazairimah zakaria escreveu: > Hi, > > I would like to customise my date series on the plot. I tried this: > > dt_ts <- ts(dt) > autoplot(dt_ts[,2]) + ylab("Charge counts") + xlab("Daily") > > but the label is not the date series. > > Tqvm for any help given. > > >> dput(dt) > structure(list(time

Hi All, I have a panel xyplot with 2 lines in each panel. I'd like to label one line only but don't know how to do this. The code below labels both lines. Any ideas how I could change it to show the y-values of only one of the lines? Many thanks! xyplot(apples + bananas ~ year | category, data=fruit, as.table=TRUE, par.strip.text=list(cex=1.2,font="bold"), par.settings =